generator

问题 I was making an answer for this question, and when I tested the timing for my solution I came up with a contradiction to what I thought was correct. The guy who made the question wanted to find a way to know how many different lists were contained within another list. (for more information, you can check the question) My answer was basically this function: def how_many_different_lists(lists): s = set(str(list_) for list_ in lists) return len(s) Now, the situation came when I measured the time

问题 All the examples that I see for using spacy just read in a single text file (that is small in size). How does one load a corpus of text files into spacy? I can do this with textacy by pickling all the text in the corpus: docs = textacy.io.spacy.read_spacy_docs('E:/spacy/DICKENS/dick.pkl', lang='en') for doc in docs: print(doc) But I am not clear as to how to use this generator object (docs) for further analysis. Also, I would rather use spacy, not textacy. spacy also fails to read in a single

问题 All the examples that I see for using spacy just read in a single text file (that is small in size). How does one load a corpus of text files into spacy? I can do this with textacy by pickling all the text in the corpus: docs = textacy.io.spacy.read_spacy_docs('E:/spacy/DICKENS/dick.pkl', lang='en') for doc in docs: print(doc) But I am not clear as to how to use this generator object (docs) for further analysis. Also, I would rather use spacy, not textacy. spacy also fails to read in a single

问题 Assume I have the following input: items = [1, 2, [3, 4], (5, 6), 'ciao', range(3), (i for i in range(3, 6))] and I want to perform some recursive operation on items . For the sake of simplicity, let's say I want to flatten items (but could be anything else), one way of doing this would be: def flatten(items, shallow=(str, bytes, bytearray)): for item in items: if isinstance(item, shallow): yield item else: try: yield from flatten(item) except TypeError: yield item this would produce: print

问题 Assume I have the following input: items = [1, 2, [3, 4], (5, 6), 'ciao', range(3), (i for i in range(3, 6))] and I want to perform some recursive operation on items . For the sake of simplicity, let's say I want to flatten items (but could be anything else), one way of doing this would be: def flatten(items, shallow=(str, bytes, bytearray)): for item in items: if isinstance(item, shallow): yield item else: try: yield from flatten(item) except TypeError: yield item this would produce: print

问题 I would like to have a function that can, optionally, return or yield the result. Here is an example. def f(option=True): ... for...: if option: yield result else: results.append(result) if not option: return results Of course, this doesn't work, I have tried with python3 and I always get a generator no matter what option value I set. As far I have understood, python checks the body of the function and if a yield is present, then the result will be a generator. Is there any way to get around

问题 Just a fundamental question regarding python and .join() method: file1 = open(f1,"r") file2 = open(f2,"r") file3 = open("results","w") diff = difflib.Differ() result = diff.compare(file1.read(),file2.read()) file3.write("".join(result)), The above snippet of code yields a nice output stored in a file called "results", in string format, showing the differences between the two files line-by-line. However I notice that if I just print "result" without using .join(), the compiler returns a

问题 I have written an invoice module for our reservation system. So when I create a new invoice, I automatically generate a primary key through MySQL. However for the moment this is just a simple integer counting up. The problem is that we are obligated to have an invoice number in the form of "#year#id" where #year is e.g. 2013 and #id is an id that start every year back at 1. So e.g. 20131, 20132, 20133 and in 2014 it wil be 20141, 20142. How can I fix this with a custom primary key generator?

问题 Here is a seemingly simple problem: given a list of iterators that yield sequences of integers in ascending order, write a concise generator that yields only the integers that appear in every sequence. After reading a few papers last night, I decided to hack up a completely minimal full text indexer in Python, as seen here (though that version is quite old now). My problem is with the search() function, which must iterate over each posting list and yield only the document IDs that appear on

问题 What is the best way to inform who use my generator function if something errors occurs, instead of writing weird return or raising exception like this piece of code function csv_file_generator($csvFilename, $delimiter = ";", $enclousure = '"') { if(($csvHandler = fopen($csvFilename, 'rb')) === false) { return; } while (($row = fgetcsv($csvHandler, 0, $delimiter, $enclousure)) !== false) { yield $row; } if (feof($csvHandler) === false) { return; } if (fclose($csvHandler) === false) { return;