fwrite

最近在做ctf的时候，碰见了好几次关于php伪协议的妙用，所以通过学习整理出相关知识 文档： http://cn2.php.net/manual/zh/wrappers.php.php#refsect2-wrappers.php-unknown-descriptioo php伪协议，事实上是其支持的协议与封装协议 支持的种类有这12种 * file:// — 访问本地文件系统 * http:// — 访问 HTTP(s) 网址 * ftp:// — 访问 FTP(s) URLs * php:// — 访问各个输入/输出流（I/O streams） * zlib:// — 压缩流 * data:// — 数据（RFC 2397） * glob:// — 查找匹配的文件路径模式 * phar:// — PHP 归档 * ssh2:// — Secure Shell 2 * rar:// — RAR * ogg:// — 音频流 * expect:// — 处理交互式的流 先整理一下关于php://的用法 php:// PHP 提供了一些杂项输入/输出（IO）流，允许访问 PHP 的输入输出流、标准输入输出和错误描述符， 内存中、磁盘备份的临时文件流以及可以操作其他读取写入文件资源的过滤器。 php://stdin, php://stdout 和 php://stderr php:/

I'm trying to save contents of a div to new html file. I'm using jQuery AJAX to send data to php. However, the php in its current form writes an empty file. Html: <div id="data2save"> <span>data1</span> <span>data2</span> <span>data3</span> <span>data4</span> </div> <input type="button" value="save" id="save"> JQuery: $("#save").live("click",function() { var bufferId =$("#data2save").html(); $.ajax({ method : "POST", url : "saver.php", data: {id : bufferId}, dataType: "html", success: function(data){ alert("ok"); } }); }); PHP: <?php $handle = fopen("test.html", 'w+'); $data = $_POST['data'];

I could not understand the output of this code? int main() { FILE* f, *f1; f = fopen("mytext", "w"); if ((f1 = fopen("mytext", "w")) == 0) printf("unable\n"); fprintf(f, "hello\n"); fprintf(f1, "hi\n"); return 0; } OUTPUT IS hello in mytext file. Why is it not being written? "unable" is not printed to stdout . You have 2 FILE* open to the same file, pointing at the beginning of the file, so one of the writes overwrites the other. Note also that FILE* are normally buffered, so these small strings actually gets written to the file when you fclose() or fflush() the FILE*. Since you do neither,

$fp = fopen('log.txt', 'w'); fwrite($fp, 'Missing gallery image for: ' . $row['toolbar_id'] . '\n'); The code above is not writing to the file. the $row['toolbar_id'] is a value from a for each loop. Any suggestions? There is no PHP error, as the file does open as I have debugged that part. Try this for extra surety ini_set('display_errors', 'On'); error_reporting(E_ALL); $fp = fopen('log.txt', 'ab'); if (false === $fp) { throw new RuntimeException('Unable to open log file for writing'); } $bytes = fwrite($fp, 'Missing gallery image for: ' . $row['toolbar_id'] . PHP_EOL); printf('Wrote %d

I am often confronted with negative comments whenever I want to have a PHP script write output to a file on the server. I use the fopen() , fwrite() and fclose() functions. The only way I know how to make this happen is to either set the permissions for the output file to 0666 or have it owned by "nobody" (which is the user that PHP runs under on our Apache web server). So, if "0666" or "owned by nobody" are security risks, how do you successfully and securely allow a PHP script to write to a file? Thanks for sharing guidance on this topic. If you need to access the files from PHP after they

I have the following program: #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAXLEN 100 typedef struct {int key; char data[MAXLEN];} record; main(int argc, char *argv[]) { int n, i; record x; FILE *fp; fp = fopen(argv[1], "w+"); printf("How many records will be entered? \n"); scanf("%d", &n); for (i=0; i<n; i++) { printf("Enter record: \n"); scanf("%d", &x.key); scanf("%s", &x.data); fwrite(&x, sizeof(record), 1, fp); } } What I am doing is creating records from user input, and then storing these "records" into a file. However, when I use fwrite(), the file that is created