formula

Find intersecting point of three circles programmatically [closed]

馋奶兔 提交于 2020-01-11 01:46:27
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . As the title says, I have 3 Circle . Each one have different radius . I know the radius of each circles. Also know the center points of each circle. Now I need to know how I can calculate the intersecting point of three circles programmatically, is there is any formula or something? It may look like below image

What is wrong with my excel formula syntax?

萝らか妹 提交于 2020-01-09 08:05:40
问题 I have made several formula to dynamically create a SQL query but to make it perfect, I want to add a condition : "if cell is not blank". I've tried a lot of different syntaxe but even with a very simple one (see exemple below), I get an error. My formula is : ="""" & SUBSTITUE(E2;"'";"''") & """" It works well and give me "Accordéoniste d''hier" I've tried =IF(E2<>"";"""" & SUBSTITUE(E2;"'";"''") & """";"") Excel display #NOM? in the cell but doesn't give me an explicit error. I've tried a

dynamic column reference in formula

穿精又带淫゛_ 提交于 2020-01-07 09:03:15
问题 I'd like to place a formula 3 cells to the left of the last column. Is there a way to do this? Perhaps through a column address? lc = .Cells(3, Columns.count).End(xlToLeft).Column .Cells(3, lc + 3).Formula = "=CountCcolor(E3:N" & lrPT & ", " & .Cells(0, lc + 2) & "3)" Regards, 回答1: lc + 3 is three columns to the right, not the left but that is almost assuredly a typo. This should square your formula construction away. lc = .Cells(3, Columns.count).End(xlToLeft).Column .Cells(3, lc + 3)

If cell contains value n, how can I create a column of n cells, each containing value n (and then repeat with another cell)?

老子叫甜甜 提交于 2020-01-07 05:49:13
问题 For the sake of simplicity, let's say I have a column of 5 numbers as follows:- 8 15 8 3 26 What I want to do is create a column composed firstly of 8 cells containing the value '8', then 15 cells containing the value '15', then 8 cells containing the value '8', and so on. This example would therefore result in a column length of 60 cells (however, my real-life column has over 200 numbers and would result in a column of about 2500 numbers!). Is this possible? Would it need a formula or a

Removing hyperlinks, retaining formulas and format

旧时模样 提交于 2020-01-07 05:30:52
问题 I'm not very good with Excel but I'm going to try and explain my problem. Somehow an excel was created via a Timer and somehow has 100's of invisible hyperlinks spread throughout the sheet. I am trying to find a way to copy from A1:k50 remove all hyperlinks but keep the formulas, values, and format. I found this code online, and I've tried adding HR.PasteSpecial xlPasteFormulas but that doesnt seem to work. Any thoughts/ideas would be much appreciated. Sub RemoveHlinks() 'Remove hyperlinks

Is there a maximum number of formula fields allowed in Excel (2010)

北战南征 提交于 2020-01-07 03:54:06
问题 Im using a csv file to build some insert statements for SQL server and am trying to clean my data before it gets inserted, and am using formulas to fo it. I have around 64000 rows and about 30 columns to clean. Ive got most of the way through it, but now a formula to make sure telephone numbers are correct has just started to fail, and now just puts the text of the forumla into the cell, rather than the cleaned telephone number. The same forumla is working in other cells. Is there a limit to

How to refer the value of a cell in excel into a formula

ぐ巨炮叔叔 提交于 2020-01-07 02:48:10
问题 I want to use the value of a cell in a reference formula. For example: I have a sheet with name '815108' which has all the data I need. Now in the sheet1(new sheet), in A1 I type in ='815108'!A3 which gets the data from A3 in the sheet '815108'. But the question I have - In my new sheet 815108 is a defined attribute (For example: SO = 815108 is defined in cell F5.) Instead of using '815108'!A3 I want to use the location in the current sheet. I tried ='=F5'!A3 which doesn't work. Any help is

Maximum and Minimum values from a summed Formula in Crystal Reports 2008

守給你的承諾、 提交于 2020-01-06 13:30:51
问题 Maximum and Minimum values from a summed Formula problem Hello, I am currently using Crystal Reports 2008 which is getting its data from an Oracle database. I have looked into this at length and I have been unable to find the information I need. I have query about getting the Maximum and Minimum values from a given formula which totals 2 or more fields. A snapshot of the information I am using is: Field1 = dB1.Left_Serious Field2 = dB1.Left_Dangerous Field3 = @Tester Formula = @LeftTot Fields

Maximum and Minimum values from a summed Formula in Crystal Reports 2008

倾然丶 夕夏残阳落幕 提交于 2020-01-06 13:29:16
问题 Maximum and Minimum values from a summed Formula problem Hello, I am currently using Crystal Reports 2008 which is getting its data from an Oracle database. I have looked into this at length and I have been unable to find the information I need. I have query about getting the Maximum and Minimum values from a given formula which totals 2 or more fields. A snapshot of the information I am using is: Field1 = dB1.Left_Serious Field2 = dB1.Left_Dangerous Field3 = @Tester Formula = @LeftTot Fields

as.formula does not like equivalence '=' (object not found)

匆匆过客 提交于 2020-01-06 12:50:54
问题 consider the following example df1 <- data.frame(a=c(1,2,3),b=c(2,4,6)); transform(df1,c=a+b) a b c 1 1 2 3 2 2 4 6 3 3 6 9 So far, so good. Now I would like to code this dynamically, using as.formula: transform(df1,as.formula("c=a+b")) However, R says Error in eval(expr, envir, enclos) : object 'b' not found This error does not occur using "~" as separator of left hand and right hand side. Can I somehow delay the evaluation of the formula? Is it possible at all to use as.formula on an