formula

问题 I'm creating a little game in Javascript, and I have trees that can hold a certain amount of max experience, and each tree have a varied amount of branches that also needs to be leveled up with experience, and they should total to the tree max experience. If it was that easy, I would just divide them equally, like max / branches , but since it's for a game, I need to make a formula where the first branch needs no experience, and then each branch experience needed steadily increase (while

问题 I'm creating a little game in Javascript, and I have trees that can hold a certain amount of max experience, and each tree have a varied amount of branches that also needs to be leveled up with experience, and they should total to the tree max experience. If it was that easy, I would just divide them equally, like max / branches , but since it's for a game, I need to make a formula where the first branch needs no experience, and then each branch experience needed steadily increase (while

问题 I have tried multiple different functions CUBESET , CUBEVALUE etc., but I cant seem to find a way to SUM multiple Measures within the same formula. Any tips on how to get this done? I've searched extensively but couldn't find a way The Idea would be something of the following (but this doesn't work) CUBEVALUE("Connection",Period,Filter1,Filter2,CUBESET("Connection","{Measure1,Measure2}")) This is required to avoid: =CUBEVALUE("Connection",Period,Filter1,Filter2,Measure1)+ CUBEVALUE(

问题 I'm trying to write a function in R that accepts a formula such as the following: y ~ 1 + sex + age + (1 | school) + (1 | school:section) Is there an easy way to extract the various components of this formula for use in my function? For example, I would like to be able to get the left hand side, each of the variables, the random effects variables and how they are nested, etc. Is there an easier way to do this than walking the formula parse tree? 回答1: If you want a solution which doesn't

问题 I'm trying to write a function in R that accepts a formula such as the following: y ~ 1 + sex + age + (1 | school) + (1 | school:section) Is there an easy way to extract the various components of this formula for use in my function? For example, I would like to be able to get the left hand side, each of the variables, the random effects variables and how they are nested, etc. Is there an easier way to do this than walking the formula parse tree? 回答1: If you want a solution which doesn't

问题 IFERROR(INDEX($I$7:$I,MODE(IF($I$7:$I<>"",MATCH($I$7:$I,$I$7:$I,0)))),"No data") With this formula, which calculates the most common text value, I need to have the 2nd most common. Column I content: Apple Orange Apple Apple Orange In this example, I need to get Orange . How is that possible? I can't figure how. 回答1: You can extract the most frequent item in the list with an array formula. =INDEX(MyList,MATCH(MAX(COUNTIF(MyList,MyList)),COUNTIF(MyList,MyList),0)) Note that an array formula

问题 I'm trying to install Wine on my Mac via Brew. I'm using Catalina and just updated brew, installed XQuartz and have Xcode installed. When I type the command "Brew install wine" it returns the following: Error: No available formula with the name "wine" ==> Searching for a previously deleted formula (in the last month)... Warning: homebrew/core is shallow clone. To get complete history run: git -C "$(brew --repo homebrew/core)" fetch --unshallow wine was deleted from homebrew/core in commit

问题 I have looked all over and tried a bunch of different things and non are working. I can get the error to show - but I also want a blank cell to return - . Right now blank cells are returning 0 . The blank cells appear in the $C$6:$DD$50 section if that helps. =IFERROR(INDEX('Foundation Plates'!$C$6:$DD$50,MATCH($C9,'Foundation Plates'!$B$6:$B$50,0),MATCH(D$8,'Foundation Plates'!$C$5:$DD$5,0)),"-") 回答1: =Index(...) & “” it would convert 0 (Blank value) to an empty string. 回答2: Your formula

问题 I want to use mutate to give me predicted values based on pre-specified variables with a quadratic / polynomial function. I can easily do this with a linear formula like this: library(tidyverse) xvar <- "Sepal.Length" yvar <- "Sepal.Width" ##linear fit #what does formula text look like? formula = !!sym(yvar) ~ !!sym(xvar) formula models <- iris %>% nest(-Species) %>% mutate( # Perform loess (or lm) calculation on each group m = map(data, lm, formula = !!sym(yvar) ~ !!sym(xvar) ), # Retrieve

问题 I was wondering if there is anyway to return the name of the table using a formula? I was working on a way to break down a few thousand addresses into there perspective column of information. ie.. #, Street, City, State, Zip-code and Phone#. The addresses are not in any consistent format that Text to Columns would work. I finally came up with the formulas to get the job done, but the are very long. In a post I found it suggested to use repeated parts of the formulas as a Defined Name. And it