formula

问题 //The error message I'm getting is saying "cannot find symbol- method second(double) but I feel as though I have identified everything already. (I'm clearly wrong). I think there is a problem with the formula as well but that is the code I was given for the formula. Any help would be greatly appreciated. import java.util.GregorianCalendar; import javax.swing.JComponent; import java.awt.geom.Ellipse2D; import java.awt.geom.Line2D; import java.awt.*;//import * Class public class ClockComponent

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . So, Leibniz's formula for pi is pi/4 = 1 - 1/3 + 1/5 - 1/7 + 1/9... I can't figure out how to use this formula in Java. I just need some help on how to incorporate the second part into it. I know I need a loop and I need the have a divisor variable, and that it needs plus 2 each time. Thanks for any help. 回答1:

问题 So, I have this 120k rows in excel with format. id number description 1 1 apple 2 1 banana 3 1 pineapple 4 1 b 5 1 c 6 6 d 7 6 e 8 6 f 9 6 g 10 6 e what formula can I use in the number column so that it will be the same as the table above? every 5th rows I will change the number of number column based on number on the 6th row of id column. Note that number column is blank right now. 回答1: Although Enigmativity's solution gives you the desired result, the results will vary by the row from where

问题 I want to write this into the range B1.. =split(A1," ") (the delimiter is a space) How do I do it using code? I tried this... var splitCell = "=SPLIT(A1," ")"; SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet1").getRange("B1").setFormula(splitCell); But the quotes are obviously ruinous. Therefore how are quotes handled in such instances? EDIT Sorry. Brain-fart. var splitCell = '=SPLIT(A8," ")'; I thought that I had already tried that (about a million times) but when I just tried it

问题 I was trying to use @Formula annotation in one of my Hibernate4.1 entity classes. From some articles I learnt that this annotation need to be placed upon the property definition, and so I did. But nothing happened. No matter how simple the formula content was, Hibernate just kept putting the property directly into generated sql, and then threw an "invalid identifier" exception, because obviously there was no corresponding column with that name in the physical table. There are only a few

问题 The forumla I'm using is =IF(E7<30,E7,"") Edit:More specifically: =IF(E7<30,CONCATENATE(A7,B7,C7,"-",TEXT(D7,"hh:mm:ss"),"-",E7),"") This leaves me with a lot of blank rows out of 288000 of them. I would like to be able to see all the cells that have a returned value together. Rather than having to scroll through all of them. I've tried using the find and replace method, but of course the cells still contain the formula, not the actual return value that it displays. Sample. 15 Mar 2015 00:23

问题 This question already has answers here : ISO week number in CMD (3 answers) Closed 2 years ago . Hi Not sure if anyone can help me. How can I convert current date to week number in a batch scripting? I only know how to generate current date from my pc. %DATE% eg. 3/16/2017 is week 11 回答1: Alternatively, call Powershell from the batch file with a simple one-liner: @for /f %%a in ('powershell.exe get-date -UFormat %%V') do @set WeekInYear=%%a 回答2: use this: @echo off set "weekn=" for /f %%W in

问题 I have 2 worksheets in an excel workbook. Data Column A Column B (PO) Column C (Supplier No) Column D (Item No) Column E(date) Column F (week no) 123406121601 - 555 =LEFT(A1,12) =LEFT(A1,3) =RIGHT(A1,3) 06/12/2016 =WEEKNUM(A1,21) I have about about 1000 rows of data like the above. In column A, each cell contains jumbled information consisting of a PO number and item number. The PO number is the first 12 digits in the cell in column A, and the first 4 digits contain the supplier number. The

问题 I need to list a running count in column A of each occurrence of the value "4A" in column B, but the count needs to reset to 0 if the value in column B equals "2B". I have attached a sample of my workbook, column A shows how I need the count to operate. I am open to using VB or a formula. Or in text format: | A | B | +---+----+ | 0 | 2B | | | 3A | | 1 | 4A | | | 4B | | | 4B | | 2 | 4A | | | 4B | | 3 | 4A | | | 9A | | 0 | 2B | | | 3A | | 1 | 4A | | | 4C | | 2 | 4A | | | 9A | | 0 | 2B | | | 3A

问题 I have some problems to find an area of a segment of a circle. I try to use this formula but have another result, as here http://planetcalc.com/1421/ , i use calculator circle segment area to check my result from terminal. my code: #define PI 3.14159265 double r = 12; double a = 22; double result = ((r*r)/2)*(PI*(a/180)-sin(a)); 回答1: You have to correct your sin calculations a bit, it should look like this: sin(M_PI * angle / 180) 来源： https://stackoverflow.com/questions/35807728/how-to-find