formula

问题 I have a gls model in which I assign a formula (from another object) to the model: equation <- as.formula(aic.obj[row,'model']) > equation temp.avg ~ I(year - 1950) mod1 <- gls(equation, data = dat) > mod1 Generalized least squares fit by maximum likelihood Model: equation Data: dat Log-likelihood: -2109.276 However I do not want the "Model" to be "equation" but rather the quation itself! How do I do this?? 回答1: This is pretty standard, even lm would do this. One approach: hijack the print

问题 I wonder if there is a formula in Google Docs Spreadsheet which could identify and display (for example in column D) the most frequent (key)words in a spreadsheet? Let's say that I have a column (Column B) full of tweets (see example image) and I would like to find top keywords in the column B and display them in column D. Is there a way to do that? Thank you! 回答1: To return the top 10 individual words in column B, with their frequency, try: =ArrayFormula(QUERY(TRANSPOSE(SPLIT(JOIN(" ";B3:B);

问题 When using formulas that have factors, the fitted models name the coefficients XY, where X is the name of the factor and Y is a particular level of it. I want to be able to create a formula from the names of these coefficients. The reason: If I fit a lasso to a sparse design matrix (as I do below) I would like to create a new formula object that only contains terms for the nonzero coefficients. require("MatrixModels") require("glmnet") set.seed(1) n <- 200 Z <- data.frame(letter=factor(sample

问题 This is what I have right now, thanks to Pavel Anossov. I am trying to convert the word frequency that has been outputed into asterisks. import sys import operator from collections import Counter def candidateWord(): with open("sample.txt", 'r') as f: text = f.read() words = [w.strip('!,.?1234567890-=@#$%^&*()_+')for w in text.lower().split()] #word_count[words] = word_count.get(words,0) + 1 counter = Counter(words) print("\n".join("{} {}".format(*p) for p in counter.most_common()))

问题 Hi In the database, we have a PRSN_ADDRESS table which has many addresses. A user is shown these addresses in a grid. The requirement is show the addresses associated with this user's state first and then show all other states. For example, say the table has 10 records with 5 of the addresses having state as Maryland, 2 from PA and 3 from NJ. Now if the user is associated with Maryland, we need to show all the 10 addresses, but Maryland addresses should show up in the first five and then the

问题 With the linear model function lm() polynomial formulas can contain a shortcut notation like this: m <- lm(y ~ poly(x,3)) this is a shortcut that keeps the user from having to create x^2 and x^3 variables or typing them in the formula like I(x^2) + I(x^3) . Is there comparable notation for the nonlinear function nls() ? 回答1: poly(x, 3) is rather more than just a shortcut for x + I(x ^ 2) + I(x ^ 3) - it actually produces legendre polynomials which have the nice property of being uncorrelated:

问题 Are there any easy ways to convert mathematical formulas to Python code? Perhaps translators, web reference, specific book chapters, anything ~ For regular expressions there are programs such as Kodos and sites such as pythonregex.com, so I was hoping there would be something similar for formula notation and Python. 回答1: No, this isn't possible in general. There are mathematical functions that aren't computable (for example, see wikipedia/Halting_problem). There are other mathematical

问题 What formula can be used to count unique values in column A if Column B is a value. i have seen many online but none of them seem to work when only using Column ranges , the data will be of varied length so only column ref can be used this worked =SUMPRODUCT((A1:A18<>"")*(B1:B18=$D$1)/COUNTIF(A1:A18,A1:A18)) but not when changed to =SUMPRODUCT((A:A<>"")*(B:B=$D$1)/COUNTIF(A:A,A:A)) table A B C D E 12/12/2015 criteria1 criteria1 3 12/12/2015 criteria1 13/12/2015 criteria1 13/12/2015 criteria1

问题 I've been using as.formula for setting up a glm, and I can't figure out where the unexpected symbol is. Part of the problem is that the character vector I'm converting is so long. It's about 700 words with + inserted in between in order to turn it into a formula. The error presents as follows: Error in parse(text = x, keep.source = FALSE) : <text>:2:10080: unexpected symbol with the following snippet of the text: 2: c_1_E + Campaign_Search_Payroll_Generic_1_P + Campaign_Search_Performing_Core

问题 Sorry I'm a noob in excel and need help with this. Say I have the following text in my excel. D:/folder A/ folder B.1/text_01.txt D:/folder A/Folder C/ folder C.1/text_02.msg I like to remove all the text from the right after the first occurrence "/" counting from the right. So I would get the followings. D:/folder A/ folder B.1 D:/folder A/Folder C/ folder C.1 回答1: Use LEFT() with FIND and SUBSTITUTE to find the last / =LEFT(A1,FIND("}}}",SUBSTITUTE(A1,"/","}}}",LEN(A1)-LEN(SUBSTITUTE(A1,"/"