formatting

How do I format all files in a Visual Studio Code project?

我怕爱的太早我们不能终老 提交于 2020-08-21 03:43:50
问题 Is there a way to format all files in a project without formatting each one individually? 回答1: You can use a extension called ”Format Files”. ”Use: Open command pallette (Ctrl+Shift+P) & enter "Format Files" Create keybinding to 'editor.action.formatFiles' command. Right click a workspace folder and select 'Format Files' to format all files in directory.” Source: https://marketplace.visualstudio.com/items?itemName=jbockle.jbockle-format-files 回答2: This works for me Install prettier: npm init

How to convert number format of a calculated column to time (hh:mm:ss) format, sql query

筅森魡賤 提交于 2020-08-10 20:13:05
问题 First I'm sorry for the poor English but I'll try to be as understandable as possible. I'm trying to make a Oracle Database SQL Query which subtracts the datetime value of two existing columns, I managed how to do it using the instruction shown below but the column TEMPO that I created is returning with NUMBER format. SELECT M.NUMOS, M.CODFUNCOS, M.DTINICIOOS, M.DTFIMSEPARACAO, M.DTFIMSEPARACAO - M.DTINICIOOS AS TEMPO FROM PCMOVENDPEND M WHERE DTFIMSEPARACAO IS NOT NULL AND DATA >= SYSDATE-1

Grouped mean of difftime fails in data.table

爱⌒轻易说出口 提交于 2020-08-02 08:39:15
问题 Preface: I have a column in a data.table of difftime values with units set to days. I am trying to create another data.table summarizing the values with dt2 <- dt[, .(AvgTime = mean(DiffTime)), by = Group] When printing the new data.table, I see values such as 1.925988e+00 days 1.143287e+00 days 1.453975e+01 days I would like to limit the decimal place values for this column only (i.e. not setting options() unless I can do this specifically for difftime values this way). When I try to do this

Grouped mean of difftime fails in data.table

你离开我真会死。 提交于 2020-08-02 08:36:55
问题 Preface: I have a column in a data.table of difftime values with units set to days. I am trying to create another data.table summarizing the values with dt2 <- dt[, .(AvgTime = mean(DiffTime)), by = Group] When printing the new data.table, I see values such as 1.925988e+00 days 1.143287e+00 days 1.453975e+01 days I would like to limit the decimal place values for this column only (i.e. not setting options() unless I can do this specifically for difftime values this way). When I try to do this

Grouped mean of difftime fails in data.table

为君一笑 提交于 2020-08-02 08:36:32
问题 Preface: I have a column in a data.table of difftime values with units set to days. I am trying to create another data.table summarizing the values with dt2 <- dt[, .(AvgTime = mean(DiffTime)), by = Group] When printing the new data.table, I see values such as 1.925988e+00 days 1.143287e+00 days 1.453975e+01 days I would like to limit the decimal place values for this column only (i.e. not setting options() unless I can do this specifically for difftime values this way). When I try to do this

Grouped mean of difftime fails in data.table

余生颓废 提交于 2020-08-02 08:36:29
问题 Preface: I have a column in a data.table of difftime values with units set to days. I am trying to create another data.table summarizing the values with dt2 <- dt[, .(AvgTime = mean(DiffTime)), by = Group] When printing the new data.table, I see values such as 1.925988e+00 days 1.143287e+00 days 1.453975e+01 days I would like to limit the decimal place values for this column only (i.e. not setting options() unless I can do this specifically for difftime values this way). When I try to do this

UnsupportedTemporalTypeException: Unsupported field: InstantSeconds

一个人想着一个人 提交于 2020-07-29 10:50:09
问题 I have this code which is producing a timestamp and then parsing. DateTimeFormatter formatter = DateTimeFormatter .ofPattern("yyyyMMdd kk:HH:ss.SSSZ") .withLocale(Locale.getDefault()) .withZone(ZoneId.systemDefault()); Instant now = Instant.now(); String formatted = formatter.format(now); Instant parsed = formatter.parse(formatted, Instant::from); When it runs, the last line produces an exception: java.time.format.DateTimeParseException: Text '20180123 12:12:45.648-0500' could not be parsed: