fopen

问题 I have this function to check if a file exists: #include <stdio.h> int main(int argc, char **argv) { int textFileExists(const char *filename){ FILE *fp= fopen(filename,'r'); if(fp==NULL){ printf("%s %s.\n","There was an error opening ", filename); return -1; } return 1; } textFileExists("text.txt"); return 0; } But when I compile this code, I get this warning. warning: passing argument 2 of ‘fopen’ makes pointer from integer without a cast FILE *fp= fopen(filename,'r'); Running this code

问题 I'm having trouble creating a form that exports to a .CSV file in PHP. I created a fiddle for the HTML which is here: http://jsfiddle.net/tqs6g/ I'm coding in PHP so I can't really show the full code on JSFiddle since it can't support the PHP but here's my PHP code: <?php if($_POST['formSubmit'] == "Submit") { $errorMessage = ""; if(empty($_POST['brandname'])) { $errorMessage .= "<li>Please enter a business/brand name.</li>"; } if(empty($_POST['firstname'])) { $errorMessage .= "<li>Please

问题 I have this super simple code where I read blocks of 8 bytes (I will encrypt them later in the code) and then write them down in a new file. It works well but for the last 8 bytes which don't get written. Any idea why? #include <stdbool.h> #include <stdlib.h> #include <stdio.h> #include <stdint.h> int main() { uint64_t data; FILE *input, *output; // create output file output = fopen("output.txt", "w"); // read file input = fopen("test.txt", "rb"); if(input) { while(fread(&data, 8, 1, input) =

问题 Now, I want to upload an image file to gcp bucket, for that I am using this code: require __DIR__ . '\vendor\autoload.php'; $storage = new StorageClient(); $file = fopen($params['book']['tmp_name'], 'r'); $bucket = $storage->bucket('fingertips-books'); $object = $bucket->upload($params['book']['name'], [ 'name' => 'test.pdf' ]); Where $params variable contains this Array ( [type] => PDF [description] => dsds [book] => Array ( [name] => 2017-03-23.pdf [type] => application/pdf [tmp_name] => C:

问题 I am using ups service for my project,I have the following code which is working fine in my localhost, ....... $fp = fopen($url, "r"); while(!feof($fp)){ $result = fgets($fp, 500); $result = explode("%", $result); //print_obj($result); $errcode = substr($result[0], -1); switch($errcode){ case 3: $returnval = $result[8]; break; case 4: $returnval = $result[8]; break; case 5: $returnval = $result[1]; break; case 6: $returnval = $result[1]; break; } } fclose($fp); ..... But fopen is not working

问题 I've placed File.rtf in the directory library/Developer/Xcode/DerivedData/Test(projectname)/Build/Products/Debug and the code seems to open it but prints out the wrong output.The output is 1606422622 for any integer value in the file. Going through the solutions of question similar to mine ,the answers were to get the input file in the right directory.I think I've done that but I just can't get the correct output. Desperate for help.Thanks. int main() { int b; FILE *fp; fp=fopen("File.rtf","r

问题 I want to check whether a HTML page exists on another site. More exactly, my users need to upload a .html page onto their own site and after that they need to press "verify now" on my site. My site then needs to confirm that the html page exists on their site. I found this code: $url = 'http://domain.tld/my_page.html'; $handle = @fopen($url,'r'); if($handle !== false){ echo 'Page Exists'; } else { echo 'Page Not Found'; } But if my_page.html don't exist, this code returns just "Page Exists".

问题 Ok, I know that there's been similar questions on this site about this problem, but none of this questions and provided answers isn't exactly what I need. I'm building flat-file based CMS. What if, for example: 2, 3, 10..... fwrite in appending mode requestes come to same php file "contact_form_messages_container.php" at the same time? 2, 3, 10..... fwrite in "w" mode requestes come to same php file which holds the simpley nubmer of specific page visits, again at the same time? I know about

问题 In my PHP code, I open a file and append text to it. I use this code: $ourFileHandle = fopen($ourFileName, 'a') or die("can't open file"); This happens when the PHP page is loaded. Now what happens if two people load the PHP page at the same time? Will this code work for one of the persons, and for the other person, will it execute die() ? In general, when can fopen fail? Thanks. 回答1: TL;DR - Just use a database This is not a simple subject. What you are doing will definitely not work as

问题 I have a folder in the same directory as my mac .app and in it is a file called test.ssm. This is trying to be opened by this function: FILE *input_file = fopen("./data/maps/test.ssm", "r"); The problem is that the application keeps getting the code: EXC_BAD_ACCESS, because it cannot open this file. My project has been set up in xcode using a normal coccoa project. This is an opengl/glut application. 回答1: The problem is that a .app is a package, and therefore it is actually a directory