fn

附录 C - Impala 保留关键字 下面是 Cloudera Impala 1.2.3 中的保留关键字。保留关键字不能直接用于标识符；你必须使用添加反引号(backticks)。例如，语句 CREATE TABLE select (x INT) 会失败，而 CREATE TABLE `select` (x INT) 则会成功。Impala 保留了聚合函数的名字，而不是正常的内置函数的(Impala reserves the names of aggregate functions, but not regular built-in functions)。 因为不同的数据库系统据有不同的保留关键字集合，并且不同版本之间会发生变化，请仔细的检查数据库、表、列的名称以确保在不同的产品和版本之间最大兼容性。 add aggregate all alter and as asc avg avro between bigint boolean by case cast change char column columns comment compute count create cross data database databases date datetime delimited desc describe distinct distinctpc distinctpcsa div

前端笔试 从输入网址到显示网页的过程分析 1、 应用层DNS解析域名 ：客户端先检查本地是否有对应的IP地址，若找到则返回响应的IP地址。若没找到则请求上级DNS服务器，直至找到或到根节点。 2、 浏览器与服务器建立TCP连接 （默认端口80）(详细点可以说下三次握手的过程) 3、 应用层客户端发送HTTP请求 。 4、 服务器响应请求 ：查找客户端请求的资源，并返回响应报文，响应报文中包括一个重要的信息——状态码（200-300，成功；304使用缓存）。 5、 服务器返回相应文件给浏览器 。 6、 Tcp连接释放 (可以说下四次挥手的过程)。 7、 浏览器 对HTML文件进行**解析构建**DOM树 ，构建渲染树 ，js根据DomAPI操作执行绑定事件等，页面显示完成。 TCP TCP协议简介 以太网协议：子网内部点对点通信 IP协议：局域网互通，路由功能 TCP协议：保证数据通信的完整性和可靠性，防止丢包 三次握手（TCP连接建立）： 1. C向S发出连接请求 ，进入同步已发送状态，S在监听状态 2. S向C发出确认报文 ，进入同步接受状态 3. C向S发出确认报文 ，进入建立连接状态，S收到也进入建立连接状态 四次挥手（TCP连接释放） 1. C向S发出连接释放报文 ，进入终止等待1状态 2.S接收， S向C发出确认报文 ，进入关闭等待状态 3.C接收，进入终止等待2状态 4

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an array like structure that exposes async methods. The async method calls return array structures that in turn expose more async methods. I am creating another JSON object to store values obtained from this structure and so I need to be careful about keeping track of references in callbacks. I have coded a brute force solution, but I would like to learn a more idiomatic or clean solution. The pattern should be repeatable for n levels of nesting. I need to use promise.all or some similar technique to determine when to resolve the

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Given that I have the following in my knowledge-database: 1 0 6 20 0 0 6 20 1 0 3 6 0 0 3 6 1 0 15 45 0 0 15 45 1 0 17 44 0 0 17 44 1 0 2 5 0 0 2 5 I want to be able to find the nearest neighbors of the following vector: 1 0 5 16 0 0 5 16 according to a distance metric. So in this case, given a particular threshold, I should find that the first vector listed is a near-neighbor to the given vector. Currently, the size of my knowledge database is in the order of millions so calculating the distance metric for each and every point and then

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am using tf.estimator.Estimator to train a model: def model_fn(features, labels, mode, params, config): input_image = features["input_image"] eval_metric_ops = {} predictions = {} # Create model with tf.name_scope('Model'): W = tf.Variable(tf.zeros([784, 10]), name="W") b = tf.Variable(tf.zeros([10]), name="b") logits = tf.nn.softmax(tf.matmul(input_image, W, name="MATMUL") + b, name="logits") loss = None train_op = None if mode != tf.estimator.ModeKeys.PREDICT: loss = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(labels=labels,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Maybe not because the call is slow, but rather the lookup is; I'm not sure, but here is an example: var foo = {}; foo.fn = function() {}; var bar = {}; bar.fn = function() {}; console.time('t'); for (var i = 0; i < 100000000; i++) { foo.fn(); } console.timeEnd('t'); Tested on win8.1 firefox 35.01: ~240ms chrome 40.0.2214.93 (V8 3.30.33.15): ~760ms msie 11: 34 sec nodejs 0.10.21 (V8 3.14.5.9): ~100ms iojs 1.0.4 (V8 4.1.0.12): ~760ms Now here is the interesting part, if i change bar.fn to bar.somethingelse : chrome 40.0.2214.93 (V8 3.30.33.15)

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a for loop in a search function, with a function that does a callback that does a callback inside the loop, and I want to execute a BUILD() function after the loop, and after all the callbacks are completed. I am not sure how to do that, because the loop finishes before all the callbacks are done. The callbacks are API requests to get me data, and I want to BUILD() with that data. I read up on deferred, so I tried to put the for loop inside a function to the deferred, and then calling BUILD() on '.then( ... )'. But that doesn't seem

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: In the Rustonomicon's guide to PhantomData , there is a part about what happens if a Vec -like struct has *const T field, but no PhantomData<T> : The drop checker will generously determine that Vec<T> does not own any values of type T . This will in turn make it conclude that it doesn't need to worry about Vec dropping any T 's in its destructor for determining drop check soundness. This will in turn allow people to create unsoundness using Vec 's destructor. What does it mean? If I implement Drop for a struct and manually destroy all T s in

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Note that this question refers to a version of Rust before Rust 1.0. Although the syntax has changed, the concepts are still valid. You can easily implement a forwards only linked list using owned pointers, something like: struct Node<T> { next: Option<~Node<T>>, data: T } Imagine, though, if you want to efficiently implement a queue that supports four basic operations: push : add to end of list pop : remove and return from the end of the list unshift : add to the front of the list shift : remove and return from the end of the list In a

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Alan Kay said that reading the code closely and finding the 1 and only bug in the code on page 13 of the Lisp 1.5 manual, helped him understand Computer Science by a factor of 100 better . The code in question is the 1st release of eval & apply that looks anything remotely like modern lisp (that I'm aware of). Since the correct answer is likely known but lost (my google-fu is decent and I've searched for 20 mins at least) I will award the 1st correct answer (I will be looking at edit times so don't try to cheat) a 250 point bounty As Soon As