Flask

问题 I am trying to deploy my Flask app using the EB CLI following this official AWS tutorial. I receive the error 'Create environment operation is complete, but with errors'. Observing the environment logs, the server seems to be lacking the correct Python version. Below are the EB environment details, my PipFile, the EB CLI output and the error in the deploy logs. How can I fix this problem? Environment details: Application name: server_eb Region: eu-west-2 Deployed Version: XXX Environment ID:

问题 Are there any way to replace html tag on WTForms? Form code: class BasicForm(Form): some_select = RadioField("something", choices=[('first', 'first_choice'), ('second', 'second_choice')]) Thanks. 回答1: Your field accepts a widget argument you can pass to override default widget(that renders your field). Docs: http://wtforms.simplecodes.com/docs/0.6/fields.html#wtforms.fields.Field 来源： https://stackoverflow.com/questions/31405666/how-can-wtforms-radiofield-generate-html-without-ul-and-li-tag

问题 I just started using Flask WTF forms. I can do everything that I need with them except I can't seem to figure out one thing. I have a multiple choice field presenting various options to the user, and if the user selects "other", I want them to describe what they mean. Like this: impact = wtforms.SelectMultipleField('What is the expected impact?', choices=[('Sales', 'Sales'), ('Lift', 'Lift'), ('Other', 'Other')] I don't know if it's even possible when it's not an independent field with its

问题 Basically what i want to do is, join 2 tables 'users' & 'company' and get the users with their relevant company details . this is the user model: class User(db.Model): __tablename__ = 'user' id = db.Column(db.Integer, primary_key=True, autoincrement=True) firstname = db.Column(db.String(10), nullable=False) lastname = db.Column(db.String(25), nullable=False) username = db.Column(db.String(250), nullable=False) email = db.Column(db.String(100), nullable=False) password = db.Column(db.String

问题 Is there a way to generate a specific IP address or make a specific site of flask http://127.0.0.1:5000/ site which runs locally, to access the web-app made using flask from different device as by default it runs locally and under http://127.0.0.1:5000/ but,i want to access it from different devices.If,there's a way please help 回答1: refer first to this doc (section Externally Visible Server ) on how to expose your local Flask app to make it accessible from trusted devices in your network for

问题 Is there a way to generate a specific IP address or make a specific site of flask http://127.0.0.1:5000/ site which runs locally, to access the web-app made using flask from different device as by default it runs locally and under http://127.0.0.1:5000/ but,i want to access it from different devices.If,there's a way please help 回答1: refer first to this doc (section Externally Visible Server ) on how to expose your local Flask app to make it accessible from trusted devices in your network for

问题 So I am developing a project to scrape a website and deliver data to users, however I am using selenium/selenium web driver with python/flask. I was originally going to use beautifulsoup, but the website I am scraping requires some interactions on the page. I have everything working with the scraper, I am just trying to figure out a way to make this work universally if I wanted to host this service on a website using a service such as heroku. Currently Selenium is opening a chrome browser and

问题 So I am developing a project to scrape a website and deliver data to users, however I am using selenium/selenium web driver with python/flask. I was originally going to use beautifulsoup, but the website I am scraping requires some interactions on the page. I have everything working with the scraper, I am just trying to figure out a way to make this work universally if I wanted to host this service on a website using a service such as heroku. Currently Selenium is opening a chrome browser and

问题 Main.py from flask_sqlalchemy import SQLAlchemy app = Flask(__name__) app.config['SECRET_KEY'] = '123' app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///database.db' app.config['SQLALCHEMY_TRACK_MODIFICATIONS'] = False db = SQLAlchemy(app) class User(db.Model): __table_name__ = 'user' id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) password = db.Column(db.String(80)) def __init__(self, username, password): self.username = username self.password =

问题 I have ModuleNotFoundError: No module named 'project' while trying to run test_req.py My project structure is: ├── instance/ │ ├── flask.cfg ├── project/ │ ├── __init__.py │ ├── base_processing.py │ ├── models.py | ├── views.py │ ├── templates/ │ │ ├── base.html │ │ ├── login.html │ │ ├── note.html │ │ ├── notes.html │ └── static/ │ │ │ └── tests/ │ ├── test_req.html ├── run.py My UnitTest file is: # project/test_req.py import unittest import os from project import app from project.models