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Java8 Lambdas vs Anonymous classes

匿名 (未验证) 提交于 2019-12-03 01:18:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Since Java8 has been recently released and its brand new lambda expressions looks to be really cool, I was wondering if this means the demise of the Anonymous classes that we were so used to. I've been researching a bit about this and found some cool examples about how Lambda expressions will systematically replace those classes, such the Collection's sort method, which used to get an Anonymous instance of Comparator to perform the sort: Collections.sort(personList, new Comparator (){ public int compare(Person p1, Person p2){ return p1

Spring Data JPA Unable to locate Attribute with the the given name

匿名 (未验证) 提交于 2019-12-03 01:18:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I was trying to use Spring Data JPA on Spring Boot and I kept getting error, I can't figure out what the problem is: Unable to locate Attribute with the the given name [firstName] on this ManagedType [com.example.h2demo.domain.Subscriber] FirstName is declared in my entity class. I have used a service class with DAO before with different project and worked perfectly. My Entity class (getters and setters are also in the class) : @Entity public class Subscriber { @Id @GeneratedValue private long id; private String FirstName,LastName,Email;

Json Schema example for oneOf objects

匿名 (未验证) 提交于 2019-12-03 01:17:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to figure out how oneOf works by building a schema which validates two different object types. For example a person (firstname, lastname, sport) and vehicles (type, cost). Here are some sample objects: {"firstName":"John", "lastName":"Doe", "sport": "football"} {"vehicle":"car", "price":20000} The question is what have I done wrongly and how can I fix it. Here is the schema: { "description": "schema validating people and vehicles", "$schema": "http://json-schema.org/draft-04/schema#", "type": "object", "required": [ "oneOf" ],

Spring Reactive xml payload exception java.lang.IllegalStateException: Failed to resolve argument 0 of type 'reactor.core.publisher.Mono'

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a spring boot application. trying to send xml payload through postman to a Post request. I get the following exception java.lang.IllegalStateException: Failed to resolve argument 0 of type 'reactor.core.publisher.Mono' on public reactor.core.publisher.Mono<com.event.gateway.rest.controller.Sir> com.event.gateway.rest.controller.WBController.hello(reactor.core.publisher.Mono<com.event.gateway.rest.controller.Sir>) at org.springframework.web.reactive.result.method.InvocableHandlerMethod.getArgumentError(InvocableHandlerMethod.java:198)

Authentication Succeeds when Debugging but Fails on Azure App Service

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am simply getting some users from SharePoint using CSOM using the below method. This has always worked for me and I've had no issues. All of a sudden, when I try calling this method today it fails with this error The sign-in name or password does not match one in the Microsoft account system. at Microsoft.SharePoint.Client.Idcrl.IdcrlAuth.GetServiceToken(String securityXml, String serviceTarget, String servicePolicy) at Microsoft.SharePoint.Client.Idcrl.IdcrlAuth.GetServiceToken(String username, String password, String serviceTarget,

Sequelize Unknown column '*.createdAt' in 'field list'

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm getting a Unknown column 'userDetails.createdAt' in 'field list' When trying to fetch with association. Using findAll without association works fine. My code is as follows: var userDetails = sequelize . define ( 'userDetails' , { userId : Sequelize . INTEGER , firstName : Sequelize . STRING , lastName : Sequelize . STRING , birthday : Sequelize . DATE }); var user = sequelize . define ( 'user' , { email : Sequelize . STRING , password : Sequelize . STRING }); user . hasOne ( userDetails , { foreignKey : 'userId' }); user .

Using POJO&#039;s with SelectOneMenu with Generic Converter

匿名 (未验证) 提交于 2019-12-03 01:10:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Hello How to use List of POJO's with JSF h:selectOneMenu or Primefaces p:selectOneMenu ? I know that there are lot of related questions which suggest to use Converter but no clear build from scratch example. I want a generic converter code for the above Purpose. Please suggest any alternatives/point me to the right question if its a duplicate. 回答1: here is a complete example of using a POJO with Primefaces p:selectOneMenu.the primfaces select one menu display a list of students.If you press details button after select any student, a

org.hibernate.hql.internal.ast.QuerySyntaxException: table is not mapped

匿名 (未验证) 提交于 2019-12-03 01:10:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have example web application Hibernate 4.3.5 + Derby database 10.10.1.1+ Glassfish4.0 with IDE NetBeans 8.0Beta. I have the next exception: Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: CUSTOMERV is not mapped at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:189) at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:109) at org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:95) at org.hibernate

How to use the PropertyValueFactory correctly?

匿名 (未验证) 提交于 2019-12-03 01:08:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to make a table with a TableView and fill it programmatically based on a list of User objects. The User has three variables, nameProperty (String), rankProperty (Enum called Rank), and netMeritsProperty (int). These are all stored in SimpleStringProperty objects. My problem is that the data will not appear in the actual table, as shown here: Here is my code for the table. What am I not understanding? TableColumn name = new TableColumn("Name"); name.setCellValueFactory(new PropertyValueFactory ("nameProperty")); TableColumn rank =

Converting List&lt;string&gt; to EntityFramework column/field list

匿名 (未验证) 提交于 2019-12-03 01:07:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Using EntityFramework, I can get a list of entities of a certain type using the following syntax: List customers = ((IQueryable )myEntities.Customers .Where(c => c.Surname == strSurname) .OrderBy(c => c.Surname)).ToList (); I can then do something like this to end up with only the data I'm interested in: var customerSummaries = from s in customers select new { s.Surname, s.FirstName, s.Address.Postcode }; I'm given a list of string s (based on user selection) of the fields (and tables where necessary) that comprise the requested summarized