filesize

Are there pitfalls for specific operating systems, I should know of? There are many duplicates ( 1 , 2 , 3 , 4 , 5 ) of this question but they were answered decades ago. The very high voted answers in many of these questions are wrong today. Methods from other (old QA's) on .sx stat.h (wrapper sprintstatf ), uses syscall tellg() , returns per definition a position but not necessarily bytes . The return type is not int . <filesystem> (added in C++17) makes this very straightforward . #include <cstdint> #include <filesystem> // ... std::uintmax_t size = std::filesystem::file_size("c:\\foo\\bar

I have a folder of images over 4MB - let's call this folder dsc_big/ . I'd like to use convert -define jpeg:extent=2MB to convert them to under 2MB and copy dsc_big/* to a folder dsc_small/ that already exists. I tried convert dsc_big/* -define jpeg:extent=2MB dsc_small/ but that produces images called -0 , -1 , and so on. What do I do? convert is designed to handle a single input file as far as I can tell, although I have to admit I don't understand the output you're getting. mogrify is better suited for batch processing in the following style: mogrify -path ../dsc_small -define jpeg:extent

I have a file on a server and it is a zip file. How to check if the file size is bigger than 27 MB? File file = new File("U:\intranet_root\intranet\R1112B2.zip"); if (file > 27) { //do something } Use the length() method of the File class to return the size of the file in bytes. // Get file from file name File file = new File("U:\intranet_root\intranet\R1112B2.zip"); // Get length of file in bytes long fileSizeInBytes = file.length(); // Convert the bytes to Kilobytes (1 KB = 1024 Bytes) long fileSizeInKB = fileSizeInBytes / 1024; // Convert the KB to MegaBytes (1 MB = 1024 KBytes) long

I am new to python. I am trying to use os.path.getsize() to obtain the file size. However, if the file name is not in Englist, but in Chinese, Gemany, or French, etc, Python cannot recognize it and do not return the size of the file. Could you please help me with it? How can I let Python recognize the file's name and return the size of these kind of files? For example: The file's name is:Показатели естественного и миграционного прироста до 2030г.doc path="C:\xxxx\xxx\xxxx\Показатели естественного и миграционного прироста до 2030г.doc" I'd like to use" os.path.getsize(path) But it does not

im testing around with the " SimpleFTPSample " project from apple to understand how ftp with iOS works. i have added two lines in the "GetController.m" to get the size of the file to download. -(void)_startReceive { . . . // Open a CFFTPStream for the URL. ftpStream = CFReadStreamCreateWithFTPURL(NULL, (CFURLRef) url); CFReadStreamSetProperty(ftpStream, kCFStreamPropertyFTPFetchResourceInfo, kCFBooleanTrue); // Added: To get file size . . . } - (void)stream:(NSStream *)aStream handleEvent:(NSStreamEvent)eventCode { . . . switch (eventCode) { case NSStreamEventOpenCompleted: { // Added: Finally