file-upload

问题 I'm currently developing an application using iOS 10 and Swift 3 and Alamofire 4 The purpose of this application is to upload a PDF file generated previously. The PDF generation is working perfectly and the file is created. However the upload doesn’t work…
 I received a success response but the file is not uploaded. My server response Multi part Content-Type => multipart/form-data; boundary=alamofire.boundary.56958be35bdb49cb Multi part Content-Length => 293107 Multi part Content-Boundary =>

问题 I'm currently developing an application using iOS 10 and Swift 3 and Alamofire 4 The purpose of this application is to upload a PDF file generated previously. The PDF generation is working perfectly and the file is created. However the upload doesn’t work…
 I received a success response but the file is not uploaded. My server response Multi part Content-Type => multipart/form-data; boundary=alamofire.boundary.56958be35bdb49cb Multi part Content-Length => 293107 Multi part Content-Boundary =>

问题 I am in the process of building my first application that makes use of Google Apps Script. I need to have a form that allows the upload of a file to a Google Documents List. I currently have this working using code based on the Google Apps Script FileUpload docmentation : function doGet(e) { var app = UiApp.createApplication().setTitle("Upload CSV to Sheet"); var form = app.createFormPanel().setId('frm').setEncoding('multipart/form-data'); var formContent = app.createVerticalPanel(); form.add

问题 I am using "plupload" to upload files then redirect to an acknowledgement page. What I would like to do is add the filename to the url string EG(www.mysite/thanks.php?file=file.jpg) For someone at my level the documentation for plupload comes across as somewhat sparse and I have been unable to identify which variable/object carries the file name. Here's where I would like to put the code Uploader.bind('FileUploaded', function(Up, File, Response) { if( (Uploader.total.uploaded + 1) == Uploader

问题 I am using "plupload" to upload files then redirect to an acknowledgement page. What I would like to do is add the filename to the url string EG(www.mysite/thanks.php?file=file.jpg) For someone at my level the documentation for plupload comes across as somewhat sparse and I have been unable to identify which variable/object carries the file name. Here's where I would like to put the code Uploader.bind('FileUploaded', function(Up, File, Response) { if( (Uploader.total.uploaded + 1) == Uploader

问题 here is my web server class : import http.server import socketserver class WebHandler(http.server.BaseHTTPRequestHandler): def parse_POST(self): ctype, pdict = cgi.parse_header(self.headers['content-type']) if ctype == 'multipart/form-data': postvars = cgi.parse_multipart(self.rfile, pdict) elif ctype == 'application/x-www-form-urlencoded': length = int(self.headers['content-length']) postvars = urllib.parse.parse_qs(self.rfile.read(length), keep_blank_values=1) else: postvars = {} return

问题 What would be the best way to handle very large file uploads (1 GB +) with Flask? My application essentially takes multiple files assigns them one unique file number and then saves it on the server depending on where the user selected. How can we run file uploads as a background task so the user does not have the browser spin for 1hour and can instead proceed to the next page right away? Flask development server is able to take massive files (50gb took 1.5 hours, upload was quick but writing

问题 What would be the best way to handle very large file uploads (1 GB +) with Flask? My application essentially takes multiple files assigns them one unique file number and then saves it on the server depending on where the user selected. How can we run file uploads as a background task so the user does not have the browser spin for 1hour and can instead proceed to the next page right away? Flask development server is able to take massive files (50gb took 1.5 hours, upload was quick but writing

问题 This is same/similar question as : Fetching uploaded files in Jenkins But with solution followed per this : Upload file in Jenkins input step to workspace , it is resulting in ' Can not open file 'file1.zip' as archive' Since bytes are manipulated as part of upload process, think may be it is resulting in problem. Tried alternative solution per https://github.com/janvrany/jenkinsci-unstashParam-library - its not helping either as it results in error ''ERROR: unstashParam: No file parameter

问题 I read on this docs : https://github.com/pqina/vue-filepond I try to add like this : <FilePond allowMultiple="true" accepted-file-types="image/jpg, image/jpeg, application/pdf" maxFileSize="2MB" required="true"/> multiple, validation file type, max file works But, required does not works How can I solve this problem guys? 回答1: Using the v-bind:required prop works: <form method="post" action=""> <file-pond v-bind:required="true"/> <button type="submit">submit</button> </form> Related GitHub