fibonacci

Fibonacci numbers with OpenMP tasks

感情迁移 提交于 2019-11-29 17:11:50
Is there any benefit by using OpenMP to parallelize the Fibonacci number calculations? There are several examples online which calculate Fibonacci numbers using the task directive in OpenMP. For example at http://docs.oracle.com/cd/E19205-01/820-7883/girtd/index.html and here http://openmp.org/forum/viewtopic.php?f=3&t=1231 Some of these examples claim the performance is better with OpenMP. I don't understand this as calculating the Fibonacci series is, to my understanding, fundamentally non parallel (ignoring methods based on closed form solutions, e.g. from Binet's formula). Additionally,

In the Fibonacci sequence, is fib(0) 0 or 1 ?

安稳与你 提交于 2019-11-29 16:49:39
问题 I'm doing a task in a subject were fib(0) is defined to = 1. But that can't be right? fib(0) is 0? Program with fib(0) = 1; spits out fib(4) = 5 Program with fib(0) = 0; spits out fib(3) = 3 What is the correct definition? 回答1: You're correct. The Fibonacci sequence is defined with seed values fib(0) = 0 and fib(1) = 1 . This is a requirement for the rest of the sequence to be correct. The only condition under which fib(0) = 1 could work is if you defined a "-1 based counting system" (as

MIPS Recursive Fibonacci Sequence

倾然丶 夕夏残阳落幕 提交于 2019-11-29 16:34:06
问题 I'm having trouble dealing with stacks recursively in MIPS. I get the concept, but my program isn't reacting as I mean it to. My goal is to take user input as n and print the Fibonacci number at n. What I have so far is below. (I'm fairly certain the problem is in the actual calculation of the number in the fib function.) Thanks for any help! :) .text main: # Prompt user to input non-negative number la $a0,prompt li $v0,4 syscall li $v0,5 syscall move $t2,$v0 # Call function to get fibonnacci

Parallel Fibonacci Number Calculator

China☆狼群 提交于 2019-11-29 16:25:29
I'm using Task Parallel Library (TPL ) for calculating Fibonacci number. Program is given below: public static int Fib(int n) { if (n <= 1) { return n; } Task<int> task = Task.Factory.StartNew<int>(() => Fib(n - 1)); var p = Fib(n - 2); return task.Result + p; } public static void Main(string[] args) { Stopwatch watch = new Stopwatch(); watch.Start(); Console.WriteLine("Answer: " + Fib(44)); watch.Stop(); Console.WriteLine("Time: " + watch.ElapsedMilliseconds); } } Unfortunately this program takes a very long time to complete. But serial version of this program ( as given below ) takes less

Fibonacci function

此生再无相见时 提交于 2019-11-29 14:36:08
We have been given a task, which we just can't figure out: Write an R function which will generate a vector containing the first n terms of the Fibonacci sequence. The steps in this are as follows: (a) Create the vector to store the result in. (b) Initialize the first two elements. (c) Run a loop with i running from 3 to n, filling in the i-th element Work so far: vast=function(n){ vast=vector() vast[1]=1 vast[2]=1 for(i in 3){vast[i]=vast[i-1]+vast[i-2]} } All we end up is with the error: object of type 'closure' is not subsettable ?? How are we supposed to generate the wanted function? My

How do I print a fibonacci sequence to the nth number in Python?

廉价感情. 提交于 2019-11-29 14:24:28
问题 I have a homework assignment that I'm stumped on. I'm trying to write a program that outputs the fibonacci sequence up the nth number. Here's what I have so far: def fib(): n = int(input("Please Enter a number: ")) if n == 1: return(1) elif n == 0: return(0) else: return (n-1) + (n-2) mylist = range[0:n] print(mylist) I'm thinking I could use separate functions but I can't figure out how to pass the argument that calculates the fibonacci sequence. Then the next step would be to to print out

Recursive Fibonacci in Bash script

六眼飞鱼酱① 提交于 2019-11-29 12:50:25
This is my attempt: #!/bin/bash function fibonacci(){ first=$1 second=$2 if (( first <= second )) then return 1 else return $(fibonacci $((first-1)) ) + $(fibonacci $((second-2)) ) fi } echo $(fibonacci 2 0) I think i'm having trouble with the else statement. I get the error return: +: numeric argument required on line 14. The other problem that i'm having is that the script doesn't display any numbers even if i do echo $(fibonacci 0 2) . I thought it would display a 1 since i'm returning a 1 in that case. Can someone give me a couple of tips on how to accomplish this? After checking out some

Create faster Fibonacci function for n > 100 in MATLAB / octave

倖福魔咒の 提交于 2019-11-29 12:35:21
问题 I have a function that tells me the nth number in a Fibonacci sequence. The problem is it becomes very slow when trying to find larger numbers in the Fibonacci sequence does anyone know how I can fix this? function f = rtfib(n) if (n==1) f= 1; elseif (n == 2) f = 2; else f =rtfib(n-1) + rtfib(n-2); end The Results, tic; rtfib(20), toc ans = 10946 Elapsed time is 0.134947 seconds. tic; rtfib(30), toc ans = 1346269 Elapsed time is 16.6724 seconds. I can't even get a value after 5 mins doing

Returning Nth Fibonacci number the sequence?

五迷三道 提交于 2019-11-29 03:34:24
问题 I have a question on my homework for class and I need to know how to return nth number of Fibonacci sequence using iteration (no recursion allowed). I need some tips on how to do this so I can better understand what I am doing wrong. I output to the console in my program.cs, hence it being absent in the code below. // Q1) // // Return the Nth Fibonacci number in the sequence // // Input: uint n (which number to get) // Output: The nth fibonacci number // public static UInt64

Fibonacci Code Golf

一笑奈何 提交于 2019-11-28 17:33:23
问题 Locked . This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions. Generate the Fibonacci sequence in the fewest amount of characters possible. Any language is OK, except for one that you define with one operator, f , which prints the Fibonacci numbers. Starting point: 25 14 characters in Haskell : f=0:1:zipWith(+)f(tail f) f=0:scanl(+)1f 回答1: RePeNt, 9 , 8 chars 1↓[2?+1] Or 10 chars