fibonacci

I was reading about the DP version of fibonnaci. In Sedgewick I saw: int[] T = new int[47]; for storage of the previous calculations. Elsewhere I saw that the max input for fibonacci should be less than 92 . It is not clear to me how does these numbers come up? I understand that it has to do with overflow and size of int but I am not clear how we end up with these limits. Any help? Well, the fibonacci series grows (approximately) exponentially with a ratio of 1.618 (the golden ratio). If you take the log base 1.618 of Integer.MAX_VALUE it will therefore tell you approximately how many

Should return the n place of the array. But instead of the value I'm only getting 0. int fibonacci(int n) { int f[100]; f[0] = 0; f[1] = 1; for (int i=2; i<n; i++) { f[i] = f[i-2] + f[i-1]; } return f[n]; } int main() { cout << fibonacci(3); return 0; } New CODE: New problem its returning one number further then it should. For example if 'n==7' its returning '13' not '8' like it should. int fibonacci(int n) { int f[100] = { 0, 1 }; for (int i=2; i<=n; i++) { f[i] = f[i-2] + f[i-1]; } return f[n-1]; } int main() { cout << fibonacci(7); return 0; } well, you never set f[n] , you only go up to i

I want to calculate the Fibonacci of very large value of N ie. 10^6 with a complexity of O(logN). Here is my code but it gives the result for 10^6 in 30 seconds which is very time consuming.Help me point out the mistake.I have to give the output in modulo 10^9+7. static BigInteger mod=new BigInteger("1000000007"); BigInteger fibo(long n){ BigInteger F[][] = {{BigInteger.ONE,BigInteger.ONE},{BigInteger.ONE,BigInteger.ZERO}}; if(n == 0) return BigInteger.ZERO; power(F, n-1); return F[0][0].mod(mod); } void power(BigInteger F[][], long n) { if( n == 0 || n == 1) return; BigInteger M[][] = {

I wonder if there is any way to generate Fibonacci numbers that beat in simplicity and efficiency this one I wrote: WITH d (seq) AS (SELECT LEVEL FROM DUAL CONNECT BY LEVEL < 195) SELECT seq ,fib FROM d MODEL DIMENSION BY(seq) MEASURES(0 AS fib) RULES (fib [1] = 0, fib [2] = 1, fib [seq BETWEEN 3 AND 194] = fib[CV(seq) - 2] + fib[CV(seq) - 1], fib [seq > 194] = NULL) ORDER BY 1 / Execution Plan ---------------------------------------------------------- Plan hash value: 2245903385 --------------------------------------------------------------------------------------- | Id | Operation | Name |

Here's the code I wrote for finding the n-th Fibonacci number: unsigned long long fib(int n) { unsigned long long u = 1, v = 1, t; for(int i=2; i<=n; i++) { t = u + v; u = v; v = t; } return v; } While the algorithm runs pretty quickly, the output starts to freak out when n>93. I think/know it's because of the unsigned long long's 64bit size. I'm new to C++ but are there ways of getting around this so I can get the answer of something like fib(9999)? Thanks BlueRaja - Danny Pflughoeft http://gmplib.org/ GMP is a free library for arbitrary precision arithmetic, operating on signed integers,

I need to to write a Java code that checks whether the user inputed number is in the Fibonacci sequence. I have no issue writing the Fibonacci sequence to output, but (probably because its late at night) I'm struggling to think of the sequence of "whether" it is a Fibonacci number. I keep starting over and over again. Its really doing my head in. What I currently have is the nth. public static void main(String[] args) { ConsoleReader console = new ConsoleReader(); System.out.println("Enter the value for your n: "); int num = (console.readInt()); System.out.println("\nThe largest nth fibonacci: