fibonacci

I'm a newcomer to clojure who wanted to see what all the fuss is about. Figuring the best way to get a feel for it is to write some simple code, I thought I'd start with a Fibonacci function. My first effort was: (defn fib [x, n] (if (< (count x) n) (fib (conj x (+ (last x) (nth x (- (count x) 2)))) n) x)) To use this I need to seed x with [0 1] when calling the function. My question is, without wrapping it in a separate function, is it possible to write a single function that only takes the number of elements to return? Doing some reading around led me to some better ways of achieving the

My Fibonacci calculator works fine, but when going up to higher numbers the result comes up negative, as it would if it was an Integer over its max value. It is working with a cache java.util.Map<Integer, Long> . Everything that goes into the Map is exactly what is expected, but when printing it out I get e.g. for 291: -784134397488903422 According to http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/fibCalcX.html , it should be: 2923602405716568564338475449381171413803636207598822186175234 It seems something goes wrong with my Long s, but I am not sure yet, what exactly. Could

Fibonacci numbers have become a popular introduction to recursion for Computer Science students and there's a strong argument that they persist within nature. For these reasons, many of us are familiar with them. They also exist within Computer Science elsewhere too; in surprisingly efficient data structures and algorithms based upon the sequence. There are two main examples that come to mind: Fibonacci heaps which have better amortized running time than binomial heaps. Fibonacci search which shares O(log N) running time with binary search on an ordered array. Is there some special property of

I am using 64 bit operating system ,then also i am not able to print 46th fibonacci number correctly which is less than 4 billion. #include<cs50.h> #include<stdio.h> int main(void) { unsigned int n=50; int array[n]; array[0]=0; array[1]=1; printf("%i\n",array[0]); printf("%i\n",array[1]); for(int i=2;i<n;i++) { array[i]=array[i-1]+array[i-2]; printf("%i\n",array[i]); } You have to use long long as your data type of the array. because You are going to store out-range numbers of the integer range.(-2,147,483,648 to 2,147,483,647) And declaration of int i should be before the for loop. #include

This question already has an answer here: Java recursive Fibonacci sequence 36 answers I am learning Java and I have this code from the internet and running it in Eclipse: public class Fibonacci { public static void main (String [] args) { for (int counter = 0; counter <= 3; counter++){ System.out.printf("Fibonacci of %d is: %d\n", counter, fibonacci(counter)); } public static long fibonacci(long number) { if ((number == 0) || (number == 1)) return number; else return fibonacci(number - 1) + fibonacci(number - 2); } } I've tried to understand it but cannot get it. So I run through the code and

I am learning Java RMI and I have created a very simple server that calculates Fibonacci numbers. The server (FibonacciServer) creates an object responsible for calculating the sequence (Fibonacci) and that object implements an interface (IFibonacci): FibonacciServer.java: package myrmifibonacciserver; import java.net.MalformedURLException; import java.rmi.Naming; import java.rmi.RemoteException; public class FibonacciServer { public static void main(String args[]){ try{ Fibonacci fib = new Fibonacci(); Naming.rebind("fibonacci", fib); System.out.println("Fibonacci Server ready."); }catch