fibonacci

The following function recurses infinitely and I don't see why. It enters the conditional statements but doesn't seem to be terminating with the return statement. use strict; use warnings; print fibonacci(100); sub fibonacci { my $number = shift; if ($number == 0) { print "return 0\n"; return 0; } elsif ($number == 1) { print "return 1\n"; return 1; } else { return fibonacci($number-1) + fibonacci($number-2); } } Your loop does not recurse infinitely, it just takes way too long with an input of 100. Try a memoized version: { my @fib; sub fib { my $n = shift; return $fib[$n] if defined $fib[$n]

I'm trying to solve Project Euler question 2 with Lisp. This recursive solution blows the stack on execution, but I thought Lisp (using clisp) would recognize the tail recursion. This is being entered into the top-level. (defun e2-problem (&optional (f1 1) (f2 1) (sum 0)) "Sum fibonacci sequence, even terms up to 4 million" (if (> f2 4000000) sum) (e2-problem f2 (+ f1 f2) (if (evenp f2) (+ sum f2) sum)) Is my implementation not correctly arranged for optimization? I imagine this would hinder my Lisp education quite a bit if I could not rely on idiomatic recursion. 1) Correct syntax error in

Here is the code: class Fibonacci { static final int MIN_INDEX = 1; public static void main (String[] args){ int high = 1; int low = 1; String jel; System.out.println("9: " + high); for (int i = 8; i >= MIN_INDEX; i--){ if (high % 2 == 0) jel = " *"; else jel = " "; System.out.println(i + ": " + high + jel); high = low + high; low = high - low; } } } I want to make this program, to write the output numbers backward. So I want that not only the ' i ' step from the last to the first, but the numbers too. In this example, the output is: 1, 1, 2, 3, 5, 8 , eg... But I want to show it in the

I'm learning about parallelization and in one exercise I'm given a couple of algorithms that I should improve in performance. One of them is a Fibonacci sequence generator: array[0] = 0; array[1] = 1; for (q = 2; q < MAX; q++) { array[q] = array[q−1] + array[q−2]; } My suspicion is, that this cannot be optimized (by parallelization), since every number depends on the two preceding numbers (and therefore indirectly on all preceding numbers). How could this be parallelized? The Fibonacci sequence is determined just by its first two elements; in fact, you could somehow parallelize it, although

I'm attempting to write a function that recursively computes the resulting fibonacci number from a given int n using forks in C. Here is the function specification: If print is true, print it. Otherwise, provide it to the parent process. The solution should be recursive and it must fork a new child for each call. Each process should call doFib() exactly once. The method signature cannot be changed. Helper functions cannot be used. Here is what I've written thus far based on my understanding of fork. I'm attempting to fork twice so I can spawn two child processes. One to do fib(n-1) and one to

Project Euler problem 25 : The Fibonacci sequence is defined by the recurrence relation: F n = F n−1 + F n−2 , where F 1 = 1 and F 2 = 1. Hence the first 12 terms will be F 1 = 1, F 2 = 1, F 3 = 2, F 4 = 3, F 5 = 5, F 6 = 8, F 7 = 13, F 8 = 21, F 9 = 34, F 10 = 55, F 11 = 89, F 12 = 144 The 12th term, F 12 , is the first term to contain three digits. What is the first term in the Fibonacci sequence to contain 1000 digits? I made a brute force solution in Python, but it takes absolutely forever to calculate the actual solution. Can anyone suggest a non brute force solution? def Fibonacci