fibonacci

Fibonacci series in C++ can't get more than 47 numbers

冷暖自知 提交于 2019-12-13 05:37:40
问题 I designed this program that can print the Fibonacci Series ( series[i] = series[i-1] + series[i-2] ) but i can't get more than 47 numbers because the 48th they become negative and strange numbers (i think this happens when the list is out of range or the item is null): #include <iostream> #include <vector> using namespace std; int main () { int length; string again = ""; do { cout << "Enter the length you want in your sequence: "; cin >> length; vector<int> series(length); for (int n=0; n<=1

Why is this Fibonacci code not correct? [closed]

五迷三道 提交于 2019-12-13 04:33:47
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . Project Euler Question 2. Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of

Fibonacci calculation

隐身守侯 提交于 2019-12-13 04:29:30
问题 This program is supposed to get a Fibonacci number from the user and the program will calculate what it is while making sure that the user entered a positive number and a number no less than the Fibonacci number 70. So, if the user entered 7, it should print 13. The method fibcalc() is supposed to do the calculations. When I try and compile the program, I get the errors "method fibcalc in class Fibonacci cannot be applied to given types: System.out.printf("Fibonacci #%d is %f", num, fibcalc

Fibonacci in C works great with 1 - 18 but 19 does nothing at all

会有一股神秘感。 提交于 2019-12-13 03:56:26
问题 I have to program a little program that show a Fibonacci sequence from 1 to n. 1 to 18 works great. But from 19 the program does nothing at all and just exit as it's done. I can not find the error... so please give me an hint. #include<sys/types.h> #include<stdio.h> #include<unistd.h> #include<stdlib.h> int main(int argc, char **argv) { pid_t pid; int fib[argc]; int i, size; size = strtol(argv[1], NULL, 0L); fib[0] = 0; fib[1] = 1; pid = fork(); printf("size = %d \n", size); if(pid == 0){ for

Fibonacci function from book “The Book of R”

五迷三道 提交于 2019-12-13 03:49:48
问题 What modification is needed so function returns a sequence without the number 1 duplicated? myfib<- function(){ fib.a<-1 fib.b<- 1 cat(fib.a,", ",fib.b,",",sep="") repeat{ temp<- fib.a+fib.b fib.a<-fib.b fib.b<-temp cat(fib.b,", ", sep="") if(fib.b>150){ cat("BREAK NOW...") break } } } instead of 1, 1, 2, 3, 4, 8, 13, 21, 34, 55, 89, 144, 233, BREAK NOW... return 1, 2, 3, 4, 8, 13, 21, 34, 55, 89, 144, 233, BREAK NOW... 回答1: Remove the first number from your cat : myfib <- function() { fib.a

Stack overflow with Fibonacci's recursive call

和自甴很熟 提交于 2019-12-12 22:15:14
问题 How exactly is the Java stack set up? For university, I shall determine what the biggest possible Fibonacci number that is calculated by a recursive method and can be handled by the stack. The interesting thing is: Tests showed that it doesn't matter how much -Xmx and -Xms the JVM has. I am able to run up to Fib(4438). But the results aren't consistent. Somtimes it goes down to 4436. Is there formular for the stack? Any increase of the stack via -Xss 4096m doesn't make a difference. 回答1: -Xmx

JavaScript fibonacci using recursion

扶醉桌前 提交于 2019-12-12 14:39:46
问题 Trying to get my fibonacci sequence to work using recursion but am running into the error maximum callstack exceeded . Code: var genFib = function(count, limit, fibArray) { if (count === undefined || count === null) { var count = 0; } if (fibArray === undefined || fibArray === null) { var fibArray = [0, 1]; } if (count === limit) { console.log(fibArray); return fibArray; } var pushFibNo = function(fibArray) { fibArray.push(fibArray[fibArray.length - 1] + fibArray[fibArray.length - 2]); return

Single Statement Fibonacci [duplicate]

断了今生、忘了曾经 提交于 2019-12-12 14:04:18
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Fibonacci numbers, with an one-liner in Python 3? It may be very easy thing, but I am very new to Python. I came up with this single statement Fibonacci. [fibs.append(fibs[-2]+fibs[-1]) for i in xrange(1000)] Not really single statement, though. I need to initialise the list, fibs , before firing this statement i.e. fibs = [0, 1] . Now, I have 2 questions, How can we get rid of this list initialisation statement

Fibonacci Search

好久不见. 提交于 2019-12-12 11:14:27
问题 Somebody please explain me the fibonacci search algorithm. I have tried numerous resources around and searched a lot, but the algorithm is still unclear. Most of the resources described it in link with binary search, but I didn't understand 'em. I know fibonacci search algorithm is an extension of binary search, which I know quite well. My books failed to explain as well. I know about fibonacci numbers defined as F(n) = F(n-1) + F(n-2), so no need to explain that. Updating the question by

How to print out this certain fibonacci sequence?

心已入冬 提交于 2019-12-12 04:44:58
问题 public static int getFib(int num) { if (num < 2) { return num; } return getFib(num - 1) + getFib(num - 2); } How can I use this code to print out this sample output like file attached with the same format of print out 回答1: Assuming your getFib() is like this: public static int getFib(int num) { if (num < 2) { return num; } int tmp = getFib(num - 1) + getFib(num - 2); return tmp; } In the main() function call the getFib() function for the asked number of times and print the values returned, as