fgets

This question already has an answer here: Why is the gets function so dangerous that it should not be used? 11 answers The declaration of gets is: char * gets ( char * str ); Note the glaring omission of a maximum size for str . cplusplus.com says 2 : Notice that gets is quite different from fgets: not only gets uses stdin as source, but it does not include the ending newline character in the resulting string and does not allow to specify a maximum size for str ( which can lead to buffer overflows ). And also: The most recent revision of the C standard (2011) has definitively removed this

I have been struggling with a pretty simple issue writing a little program in C . Getting input (commands, arguments, flags to be executed) via fgets() works fine as long as the size of the input does not exceed 1024 bytes. After 1024 characters are typed, no more characters are accepted -- the prompt just stops. I assume reason for the problem doesn't lay in the fgets() parameters/configuration because otherwise it would at least take the input up to defined size instead of blocking. How can I make fgets() accept lines as long as _SC_LINE_MAX ( 2048 ) bytes/chars? Terminal drivers limit the

I'm trying to use fgets and strtok() to read in a file line by line, and create a linked list of each different line of information. Right now, I'm only just putting the information into an array, just to try to figure out how to read the information in correctly, but it's not working right. In the while(fgets) portion, it seems to load everything into the array properly, and prints it out. However, after that loop has executed and I try to print out the whole array, I get really weird results.. which is mostly portions of the last line ONLY, and not complete words or anything for the most

I am running the following code: #include<stdio.h> #include<string.h> #include<io.h> int main(){ FILE *fp; if((fp=fopen("test.txt","r"))==NULL){ printf("File can't be read\n"); exit(1); } char str[50]; fgets(str,50,fp); printf("%s",str); return 0; } text.txt contains: I am a boy\r\n Since I am on Windows, it takes \r\n as a new line character and so if I read this from a file it should store "I am a boy\n\0" in str , but I get "I am a boy\r\n" . I am using mingw compiler. Since I am on Windows, it takes \r\n as a new line character... This assumption is wrong. The C standard treats carriage

Problem: I need to be able identify when two whitespaces occur consecutively. I have read the following questions: how to read a string from a \n delimited file how to read scanf with spaces And I am aware of scanf problems: http://c-faq.com/stdio/scanfprobs.html Input will be in the following format: 1 5 3 2 4 6 2 1 9 0 Two white spaces indicates that the next set of data needs to be handle and compared to itself. The length of the line is unknown and the number or integers in each group is unknown. Two whitespaces is the most that will separate the next data set. While I can use fgets and

I'm trying to read user input and store it as a string including the whitespace. I did a search for a solution and was pointed to fgets() or scanf(%[^\n], str). But both these solutions give me an error. This is what I have: //MAX_CHARACTERS is set to 30 scanf("%d", &input); if (input == 1){ int pr; char na[MAX_CHARACTERS+1]; printf("\nEnter the name: "); scanf("%[^\t\n]", &na); while (strlen(na)>MAX_CHARACTERS){ printf("\nName is too long, enter new name: "); scanf("%[^\t\n]", &na); }// end na check printf("\nEnter priority: "); scanf("%d", &pr); while (pr>MAX_PRIORITY || pr <MIN_PRIORITY){