fgetcsv

<?php $row = 1; $handle = fopen ("test.csv","r"); while ($data = fgetcsv ($handle, 1000, ",")) { $num = count ($data); print "<p> $num fields in line $row: <br>\n"; $row++; for ($c=0; $c < $num; $c++) { print $data[$c] . "<br>\n"; } } fclose ($handle); ?> The above comes from php manual,but I didn't see where to specify the encoding(like utf8 or so) Try to change the locale. Like it says below the example in the manual you gave: Note: Locale setting is taken into account by this function. If LANG is e.g. en_US.UTF-8, files in one-byte encoding are read wrong by this function. Suggested

I have a .CSV file with headings: Description, BusinessSurname, IsCustomer, IsSupplier, AddressType, Business Address, IsInternational. First row: Contact1, Contact1, True, True, Business, 123 Fake St, False Remaining rows not important, its just more like that - examples. I have a few rows of data in there. I need to get it into this format json: { Description:'Desc_47AE3208-87F5-4BBA-BE40-AA4130AB4768', SurnameBusinessName:'Name_Business', IsCustomer:true, IsSupplier:true, Addresses: [ {AddressType:'Business',Line1:'addr1_bus',IsInternational:false}, {AddressType:'Postal',Line1:'addr1_pos'

I have a CSV file with an initial header row and an unknown number of rows. The row format is: name_data, email_data, cell_data, dob_data I'd like to open the CSV file and then depict the data from the last entered row in a table, like this: Name: name_data Email: email_data Cell: cell_data D.O.B.: dob_data I'm thinking I can use fgetcsv() but I'm not sure how to parse the data once I get it. Any ideas? Thanks - Joe Seems inefficient to parse every line of the file with fgetcsv() when you only care about the first and last line. As such, I'd use file() and str_getcsv() : $rows = file('data.csv

This is my code to check if a row of my .csv file contains a specific name, but it does not work. I think it has something to do with the if statement. $file_handle = fopen("sources.csv", "r"); while (!feof($file_handle) ) { $line_of_text = fgetcsv($file_handle, 1024); if ($line_of_text[0] = 'paul') { echo 'Found'; } } fclose($file_handle); I am trying to check in sources.csv files, for the name 'Paul' . I can't use a database like MySQL for technical reasons. Since you haven't provided a sample of your file, am submitting the following as an alternative. Do note that in your present code, you

I have this script that I did, it basically grabs all the files in my "logs" folder and merge them all in one array file, my only problem is that, sometimes the script breaks if there is blank line or empty line! how can I tell it to automatically skip blank empty lines and go to next? blank lines are not necessarily at the top or bottom! could be in the middle of the csv file <?php $csv = array(); $files = glob('../logs/*.*'); $out = fopen("newfile.txt", "w"); foreach($files as $file){ $in = fopen($file, "r"); while (($result = fgetcsv($in)) !== false) { $csv[] = $result; } fclose($in);

Using fgetcsv , can I somehow do a destructive read where rows I've read and processed would be discarded so if I don't make it through the whole file in the first pass, I can come back and pick up where I left off before the script timed out ? Additional Details: I'm getting a daily product feed from a vendor that comes across as a 200mb .gz file. When I unpack the file, it turns into a 1.5gb .csv with nearly 500,000 rows and 20 - 25 fields. I need to read this information into a MySQL db, ideally with PHP so I can schedule a CRON to run the script at my web hosting provider every day. I have