extends

JAVA: JProgressbar & Files.copy With Observer and Swingworker in 1 Class

本秂侑毒 提交于 2020-01-07 03:52:11
问题 I wrote an aricle a couple months agoMY POST but I want to make some changes to I. Now all my code is worked out in the Swingworker class. But I want to use the MVC methode and use the observer pattern to update my variables in the view. Now i have something like this public class CopyFrame extends JFrame { private JTextarea textArea; private JProgresbar progresbar; public CopyFrame(){ progresbar = new JProgresbar textArea = new JTextarea(); progresbar.setMaximum(100)); /*in this method I

Override a protected method, and try to call it from the super class

那年仲夏 提交于 2020-01-04 05:33:06
问题 My question comes from a project. So let me abstract away a bit unrelated details. I have a JAVA public class A that has two protected static methods, foo() and bar(). The method foo() calls bar() in its body. public class A{ protected static foo(){ ... bar() ... } protected static bar(){print("A.bar()");} } Now I also have a class B extending A. In B, I override bar() class B extends A{ @Overrides static protected bar(){ print("A.bar() extended"); } Finally, I call foo() from a class in B

IVY Extends via ivy:resolve

一曲冷凌霜 提交于 2020-01-03 05:58:05
问题 We have recently introduced a common dependency in our build system which uses ivy:extends option within each individual ivy.xml. Common ivy.xml contents are as follows; common-ivy.xml <?xml-stylesheet type="text/xsl" href="http://repository.xyz.com/xsl/version-doc.xsl"?> <ivy-module version="2.0" xmlns:e="http://ant.apache.org/ivy/extra"> <info organisation="XYZ" branch="MAIN" module="CommonDependencies" revision="1.0.0" /> <configurations defaultconfmapping="test->test(*);compile->compile(*

Javascript es6 override static properties

笑着哭i 提交于 2020-01-01 11:50:33
问题 Trying out ES6 and tried to create a class with static properties and function for parsing. Then I want to extend the base parser for each different type I am parsing. Not sure if I am doing a anti-pattern but I cannot override static properties. This is my base parser class Module { static name = 'Default Module' static version = {major:10000, minor: 10000} static checkVersion({majorVersion = 10000, minorVersion = 10000}) { if(this.version.major !== majorVersion || this.version.minor >

Javascript es6 override static properties

时间秒杀一切 提交于 2020-01-01 11:49:32
问题 Trying out ES6 and tried to create a class with static properties and function for parsing. Then I want to extend the base parser for each different type I am parsing. Not sure if I am doing a anti-pattern but I cannot override static properties. This is my base parser class Module { static name = 'Default Module' static version = {major:10000, minor: 10000} static checkVersion({majorVersion = 10000, minorVersion = 10000}) { if(this.version.major !== majorVersion || this.version.minor >

PHP - extend method like extending a class

天涯浪子 提交于 2020-01-01 07:57:29
问题 I have 2 class: class animal{ public function walk(){ walk; } } class human extends animal{ public function walk(){ with2legs; } } This way, if i call human->walk(), it only runs with2legs; But I want the run the parent's walk; too. I know I can modify it this way: class human extends animal{ public function walk(){ parent::walk(); with2legs; } } But the problem is, I have many subclasses and I don't want to put parent::walk(); into every child walk(). Is there a way I can extend a method

PHP - extend method like extending a class

我是研究僧i 提交于 2020-01-01 07:57:25
问题 I have 2 class: class animal{ public function walk(){ walk; } } class human extends animal{ public function walk(){ with2legs; } } This way, if i call human->walk(), it only runs with2legs; But I want the run the parent's walk; too. I know I can modify it this way: class human extends animal{ public function walk(){ parent::walk(); with2legs; } } But the problem is, I have many subclasses and I don't want to put parent::walk(); into every child walk(). Is there a way I can extend a method

How to Inherit A Model from Another Model in CodeIgniter

你离开我真会死。 提交于 2020-01-01 04:27:05
问题 i'm using codeigniter for my project and i have this class model which i call Genesis which looks like this: class Genesis_model extends CI_Model { function __construct() { parent::__construct(); } function get() { return 'human soul'; } } and i have another model, stored in the same directory, which extends Genesis_model class Human_model extends Genesis_model { function __construct() { parent::__construct(); } function get_human() { return $this->get(); } } Human_model is used by Human

Codeigniter extending controller, controller not found

拟墨画扇 提交于 2019-12-30 02:04:05
问题 In Codeigniter 2.1.2 I want to create base controller and then extends from this controller. It does not work and I have no idea why and I'm pretty desperate now. In \application\core\MY_Base_Controller.php I have this: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class MY_Base_Controller extends CI_Controller { function __construct() { parent::__construct(); ... In \application\controllers\Home.php I have this: <?php if ( ! defined('BASEPATH')) exit('No direct

Codeigniter extending controller, controller not found

给你一囗甜甜゛ 提交于 2019-12-30 02:03:29
问题 In Codeigniter 2.1.2 I want to create base controller and then extends from this controller. It does not work and I have no idea why and I'm pretty desperate now. In \application\core\MY_Base_Controller.php I have this: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class MY_Base_Controller extends CI_Controller { function __construct() { parent::__construct(); ... In \application\controllers\Home.php I have this: <?php if ( ! defined('BASEPATH')) exit('No direct