exit

This question already has an answer here: Capture console exit C# 10 answers I have a little console C# program like Class Program { static void main(string args[]) { } } Now I want to do something after main() exit. I tried to write a deconstructor for Class Program, but it never get hit. Does anybody know how to do it. Thanks a lot Try the ProcessExit event of AppDomain : using System; class Test { static void Main(string[] args) { AppDomain.CurrentDomain.ProcessExit += new EventHandler (OnProcessExit); // Do something here } static void OnProcessExit (object sender, EventArgs e) { Console

I was using "exit 1" statement in my bash functions to terminate the whole script and it worked fine: function func() { echo "Goodbye" exit 1 } echo "Function call will abort" func echo "This will never be printed" But then I realized that it doesn't do the work when called like: res=$(func) I understand that I created a subshell and "exit 1" aborts that subshell and not the primary one.... But is there a way to write a function which aborts the whole execution, no matter how it is called? I just need to get the real return value (echoed by the function). What you could do, is register the top

What is the command in C# for exit a Console Application? You can use Environment.Exit(0); and Application.Exit Environment.Exit(0) is cleaner . Several options, by order of most appropriate way: Return an int from the Program.Main method Throw an exception and don't handle it anywhere (use for unexpected error situations) To force termination elsewhere, System.Environment.Exit ( not portable! see below ) Edited 9/2013 to improve readability Returning with a specific exit code: As Servy points out in the comments, you can declare Main with an int return type and return an error code that way.

In C and C++, what is the difference between exit() and abort() ? I am trying to end my program after an error (not an exception). abort() exits your program without calling functions registered using atexit() first, and without calling objects' destructors first. exit() does both before exiting your program. It does not call destructors for automatic objects though. So A a; void test() { static A b; A c; exit(0); } Will destruct a and b properly, but will not call destructors of c . abort() wouldn't call destructors of neither objects. As this is unfortunate, the C++ Standard describes an

What is the difference between the return and exit statement in Bash functions with respect to exit codes? Diego Sevilla From man bash on return [n] ; Causes a function to stop executing and return the value specified by n to its caller. If n is omitted, the return status is that of the last command executed in the function body. ... on exit [n] : Cause the shell to exit with a status of n. If n is omitted, the exit status is that of the last command executed. A trap on EXIT is executed before the shell terminates. EDIT: As per your edit of the question, regarding exit codes, return has

The docs say that calling sys.exit() raises a SystemExit exception which can be caught in outer levels. I have a situation in which I want to definitively and unquestionably exit from inside a test case, however the unittest module catches SystemExit and prevents the exit. This is normally great, but the specific situation I am trying to handle is one where our test framework has detected that it is configured to point to a non-test database. In this case I want to exit and prevent any further tests from being run. Of course since unittest traps the SystemExit and continues happily on it's way