exit

参考： os._exit() 和 sys.exit() 来源： CSDN 作者： 爱问西瓜爱大树 链接： https://blog.csdn.net/u011208984/article/details/103243074

In my application i want exit from app when press back button, this my code: @Override public void onBackPressed() { new AlertDialog.Builder(this).setIcon(android.R.drawable.ic_dialog_alert).setTitle("Exit") .setMessage("Are you sure you want to exit?") .setPositiveButton("Yes", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { finish(); } }).setNegativeButton("No", null).show(); } it's work correctly but when i exit from app it does not exit completely and show empty page with my app logo and when i again press back button exit from app

I'm writing a script in Bash to test some code. However, it seems silly to run the tests if compiling the code fails in the first place, in which case I'll just abort the tests. Is there a way I can do this without wrapping the entire script inside of a while loop and using breaks? Something like a dun dun dun goto? Michael Foukarakis Try this statement: exit 1 Replace 1 with appropriate error codes. See also Exit Codes With Special Meanings . Shizzmo Use set -e #!/bin/bash set -e /bin/command-that-fails /bin/command-that-fails2 The script will terminate after the first line that fails

So I've been doing a little bit of reading up on how to exit a while loop by the user pressing the enter key and I've come up with the following: import sys, select, os switch = 1 i = 1 while switch == 1: os.system('cls' if os.name == 'nt' else 'clear') print "I'm doing stuff. Press Enter to stop me!" print i while sys.stdin in select.select([sys.stdin], [], [], 0)[0]: line = raw_input() if not line: print "Finished! =]" switch = 0 else: print "Finished! =]" switch = 0 i = i+1 Is there a way to tidy this up? In particular the "if not line" and the following "else" look messy. Can they be

Why is it that when I shift the exit code, $?, in Perl by eight, I get 255 when I expect it to be -1? Jonathan Leffler The exit status returned by 'wait()' is a 16-bit value. Of those 16 bits, the high-order 8 bits come from the low-order 8 bits of the value returned by 'exit()' — or the value returned from main() . If the program dies naturally, the low-order 8 bits of the 16 are all zero. If the program dies because of signal, the low-order 8 bits encode the signal number and a bit indicating whether a core dump happened. With a signal, the exit status is treated as zero — programs like the

pythoncom.PumpMessages() From what I understand this line basically tells the program to wait forever. For my purposes it seems to be working. However, I'd like to be able to end the program given the right stimulus. How would one go about ending the above line, or stopping the program from running any further. According to these docs , pythoncom.PumpMessages() : Pumps all messages for the current thread until a WM_QUIT message. So one way to stop collecting messages is by posting a WM_QUIT message to the message queue by using the ctypes library to call PostQuitMessage : ctypes.windll.user32

Is there a line of code that will terminate the program? Something like python's sys.exit() ? #include <cstdlib> ... exit( exit_code ); While you can call exit() (and may need to do so if your application encounters some fatal error), the cleanest way to exit a program is to return from main() : int main() { // do whatever your program does } // function returns and exits program When you call exit() , objects with automatic storage duration (local variables) are not destroyed before the program terminates, so you don't get proper cleanup. Those objects might need to clean up any resources

consider this function : func doAllWork() error { var wg sync.WaitGroup wg.Add(3) for i := 0; i < 2; i++ { go func() { defer wg.Done() for j := 0; j < 10; j++ { result, err := work(j) if err != nil { // can't use `return err` here // what sould I put instead ? os.Exit(0) } } }() } wg.Wait() return nil } In each goroutine, the function work() is called 10 times. If one call to work() returns an error in any of the running goroutines, I want all the goroutines to stop immediately, and the program to exit. Is it ok to use os.Exit() here ? How should I handle this ? Edit : this question is