exit

问题 I am working on a school assignment, and we were told that whenever we have an input error we should print a message and exit the program. Obviously I use exit(1), but the problem is I have memory leaks when using this functions. I don't understand why - every single variable I've used was on the stack and not on the heap. What should I do to prevent those memory leaks? Thanks! 回答1: exit does not call the destructors of any stack based objects so if those objects have allocated any memory

问题 This question was migrated from Unix & Linux Stack Exchange because it can be answered on Stack Overflow. Migrated 7 years ago . I was reading about linux kernel development and I just read some text that I don't understand. Here is the paragraph, which talks about the __init and __exit macros for modules: This demonstrates a feature of kernel 2.2 and later. Notice the change in the definitions of the init and cleanup functions. The __init macro causes the init function to be discarded and

问题 I need show a simple dialog with the question : 'Do you want to exit the application?' YES or NO. This dialog will be shown when the user presses the back button of the device. I know how I can show this dialog , but I don't know how to disable the back action: close app. It's always closed. 回答1: If I understand you correctly, you want to display a confirmation dialog when the user clicks the back button on the main page of your app to ask whether they really want to exit. If the user selects

问题 Within PHP, if I have one function that calls another function; is there any way to get the called function to exit out of the caller function without killing the entire script? For instance, let's say I have some code something like: <?php function funcA() { funcB(); echo 'Hello, we finished funcB'; } function funcB() { echo 'This is funcB'; } ?> <p>This is some text. After this text, I'm going to call funcA.</p> <p><?php funcA(); ?></p> <p>This is more text after funcA ran.</p>

问题 A basic question. I need to exit a function without throwing any exceptions. How do I do that in C#? 回答1: It's just as simple as: void Function() { ... if(needToLeave) return; ... } Nevertheless this would be a one minute search in any programming tutorial. 回答2: I'm not sure I understand you correctly. Maybe using return; ? 回答3: Instead of using "return;" I've always suggested a right logic. In other words, you don't need to leave execution from some method: just use a conditional statement

问题 The 'exit' command doesn't work for my case, and I don't get it why: ssh user@mysever <<'HEREDOC' echo "1. Running PM2 log..." pm2 log & echo "2. PM2 log is now in background" exit echo "3. Won't be here" HEREDOC echo "4. Out." I can't terminate the ssh pipeline, even with the 'exit' command above. I can see the first echo, second echo; no third echo of course; and stuck. I expected the behaviour that I can see the fourth echo. I have to press Ctrl+C, and I see the 4th echo after that. 回答1:

问题 I am remotely working on a server that automatically logs me out after 5 minutes of inactivity. Here's the message that it usually provides when it does so: Read from remote host XXXXXXX: Operation timed out I typically have several sessions open, which I use at roughly 30-minute intervals, so I wonder what I could do to avoid getting disconnected. I've already tried: [a] hiring a monkey to hit some keys before the session logs me out [b] running the top command [c] threatening the server

问题 UIApplicationExitsOnSuspend does not force my app to exit. I have cleaned the target, removed the app, rebuilt, and reinstalled many times. I really need my app to exit. 回答1: Did you link against SDK 4? This key is only effective in this case. 回答2: Are you sure your application is still active ? You will always see your application when double tapping the home button : this is a list of the recently used apps, not a list of currently running apps Put a breakpoint in the

问题 Compiler: Qt Language: C++ This program is just not for me haha, this is the third time I've had to ask for help, and it's driving me crazy (thank you everyone for being so patient and helpful with me) I tried running my program (again for the millionth time) Since I can't get the ostream sorted out, I commented out all the cout functions in my main so I could deal with the rest of my code. But when I try to run it I get collect2: ld returned 1 exit status in my build issues. I switched to

问题 I have objects, they get locks. I want to test if they are locked without acquiring a lock. The idea is if I TryEnter() then i have to Exit() if true to only check the lock correctly. Seems like a really basic question, how is it done? 回答1: What possible information can you get from knowing the lock was unlocked back when you looked at it? By the time you make a decision based on that information, the lock may be already taken. 回答2: Because the lock statement is equivalent to: System