exists

Hbase error zookeeper exists failed after 3 retiries

匿名 (未验证) 提交于 2019-12-03 02:24:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using HBASE 0.94.8 standalone mode in Ubuntu. Its working fine i am able to do every operations in Hbase-shell. But after i logged of my system its giving following error 15/07/28 15:10:30 ERROR zookeeper.RecoverableZooKeeper: ZooKeeper exists failed after 3 retries 15/07/28 15:10:30 WARN zookeeper.ZKUtil: hconnection-0x14ed40513350009 Unable to set watcher on znode (/hbase) org.apache.zookeeper.KeeperException$ConnectionLossException: KeeperErrorCode = ConnectionLoss for /hbase at org.apache.zookeeper.KeeperException.create

IF EXISTS condition not working with PLSQL

匿名 (未验证) 提交于 2019-12-03 02:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am trying to print the TEXT when condition is TRUE. The select code is perfectly working fine. It's showing 403 value when i only run select code. But I have to print some text when condition exists. What's the problem with following code. BEGIN IF EXISTS ( SELECT CE . S_REGNO FROM COURSEOFFERING CO JOIN CO_ENROLMENT CE ON CE . CO_ID = CO . CO_ID WHERE CE . S_REGNO = 403 AND CE . COE_COMPLETIONSTATUS = 'C' AND CO . C_ID = 803 ) THEN DBMS_OUTPUT . put_line ( 'YES YOU CAN' ); END ; Here is the error report: Error report : ORA -

“No appropriate mapping exists” error while unshelving shelveset in TFS

匿名 (未验证) 提交于 2019-12-03 02:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using TFS 2012. In TFS there are more than 15 users. When I try to unshelve a shelveset files it shows error as shown below Interesting is that this error does not comes for few users, and they are able to unshelve it. All the users have same permission. The error comes for one user and for another user it does not come in same PC(TFS server installed PC).So it's little strange error. Initially i was thinking like may be a problem with mappings,but for another user same kind of mapping allows to unshelve it. I also tried re creating the

In XSLT how do you test to see if a variable exists?

匿名 (未验证) 提交于 2019-12-03 02:22:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: When using XSLT how do you test to see if a locally scoped variable exists, or is this even possible? 回答1: Considering the XSLT stylesheet as an XML DOM, a variable declaration element makes the variable visible to all following siblings and their descendants. This allows XSLT processors to statically analyze any XPath containing a variable reference to see if the variable exists; if the variable declaration exists on the preceding-sibling or ancestor axis, the variable reference is legal, otherwise it's not. Note that this is entirely

SQL JOIN vs IN performance?

匿名 (未验证) 提交于 2019-12-03 02:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a case where using a JOIN or an IN will give me the correct results... Which typically has better performance and why? How much does it depend on what database server you are running? (FYI I am using MSSQL) 回答1: Generally speaking, IN and JOIN are different queries that can yield different results. SELECT a.* FROM a JOIN b ON a.col = b.col is not the same as SELECT a.* FROM a WHERE col IN ( SELECT col FROM b ) , unless b.col is unique. However, this is the synonym for the first query: SELECT a.* FROM a JOIN ( SELECT DISTINCT col FROM

php Checking if value exists in array of array

匿名 (未验证) 提交于 2019-12-03 02:18:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have an array within an array. $a = array ( 0 => array ( 'value' => 'America', ), 1 => array ( 'value' => 'England', ), ) How do I check if 'America' exists in the array? The America array could be any key, and there could be any number of subarrays, so a generalized solution please. Looking on the php manual I see in_array, but that only works for the top layer. so something like in_array("America", $a) would not work. Thanks. 回答1: A general solution would be: function deep_in_array($needle, $haystack) { if(in_array($needle, $haystack)) {

SQL Server 2008 - IF NOT EXISTS INSERT ELSE UPDATE

匿名 (未验证) 提交于 2019-12-03 02:18:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I apologize, but this is kind of a two part question. I'm extremely new to SQL and am trying to develop a time clock application for the small office that I work in. I'm playing around with the SQL backend right now and have a question about compound statements. Where I'm stuck is if a user tries to clock out for break but never clocked in at the start of the shift, SQL needs to create a new row rather than update an existing. Here is what I tried: IF NOT EXISTS(SELECT * FROM Clock WHERE clockDate = '08/10/2012') AND userName = 'test') BEGIN

No mapping exists from object type System.Collections.Generic.List when executing stored proc with parameters in EF 4.3

匿名 (未验证) 提交于 2019-12-03 02:18:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Lately I've been working on stored procedure and encountered 1 strange problem. First, I was able to successfully call a stored procedure from the database via: IList<XXXViewModel> XXXList = _context.Database.SqlQuery("spXXX").ToList(); But when I needed to pass parameters it failed: var parameters = new List<SqlParameter>(); parameters.Add(new SqlParameter("param1", param1Value)); parameters.Add(new SqlParameter("param2", param2Value)); IList<XXXViewModel> XXXList = _context.Database.SqlQuery<XXXViewModel>("spXXX @param1, @param2",

Objective-C - Checking if URL exists

匿名 (未验证) 提交于 2019-12-03 02:14:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a for-loop that currently loops 4 times. //Add all the URLs from the server to the array for (int i = 1; i <= 5; i++){ NSString *tempString = [[NSString alloc] initWithFormat : @"http://photostiubhart.comoj.com/GalleryImages/%dstiubhart1.jpg", i]; [myURLS addObject: [NSURL URLWithString:tempString]]; [tempString release]; } As you can see the URL has a digit in it that get incremented by 1 each loop to create a new URL where the next image will be. However, the amount of images on the server won't necessarily be 4, it could be a lot

android getlastknownlocation returns null

匿名 (未验证) 提交于 2019-12-03 02:14:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I know there's a few questions about this, but I'm not finding exactly the answer I want. I'm calling getLastKnownLocation for the GPS provider and it's returning null. The docs say this might happen if the provider isn't enabled, but I know it is. Is it possible for the provider to return null if no last known location exists? I don't see where the docs say "may return null if no last known location exists" Thanks! 回答1: Is it possible for the provider to return null if no last known location exists? Yes. In fact, much of the time, it will