excel-formula

问题 I have the following Excel spreadsheet: A B C D E F 1 MFC2 MFC1 QFC Search Criteria: CW14 2 CW11 Column Name: MFC1 3 CW13 4 CW14 5 CW17 6 CW18 7 CW19 8 9 In Cells A1:C8 I have different calender weeks. All of them are unique ! In Cell E2 I want that the column name is displayed based on the value that is put in Cell E1 . In this case the search criteria is CW14 so the result should be column name MFC1 . I tried to modify the formula from this question but could not make it work: E1 = INDEX($A

问题 I swear this just worked yesterday... I have a program that creates formulas within certain cells that depend on subsequent data entries into other cells: Cells(i, 40).Formula = "= (N" & i & ")/AP" & i So, AP i can be input and/or changed after the fact, and the formula should give you the result for whatever value is there. However, I get a #Div/0! error no matter what value is in that cell. When I evaluate the formula (within Excel) and step through the calculations, it shows this (for one

问题 people! I do not often refer to VBA in Excel, but when I do, I find answer by Googling. However, there is no answer for my current need. I have following function to count colours in range (possible source - http://www.ozgrid.com/VBA/sum-count-cells-by-color.htm): Function ColorFunction(rColor As Range, rRange As Range, Optional SUM As Boolean) Dim rCell As Range Dim lCol As Long Dim vResult lCol = rColor.Interior.Color If SUM = True Then For Each rCell In rRange If rCell.Interior.Color =

问题 people! I do not often refer to VBA in Excel, but when I do, I find answer by Googling. However, there is no answer for my current need. I have following function to count colours in range (possible source - http://www.ozgrid.com/VBA/sum-count-cells-by-color.htm): Function ColorFunction(rColor As Range, rRange As Range, Optional SUM As Boolean) Dim rCell As Range Dim lCol As Long Dim vResult lCol = rColor.Interior.Color If SUM = True Then For Each rCell In rRange If rCell.Interior.Color =

问题 people! I do not often refer to VBA in Excel, but when I do, I find answer by Googling. However, there is no answer for my current need. I have following function to count colours in range (possible source - http://www.ozgrid.com/VBA/sum-count-cells-by-color.htm): Function ColorFunction(rColor As Range, rRange As Range, Optional SUM As Boolean) Dim rCell As Range Dim lCol As Long Dim vResult lCol = rColor.Interior.Color If SUM = True Then For Each rCell In rRange If rCell.Interior.Color =

问题 I have records like RF123456789, RF1234567890 etc. I just want to match the records which are starting with 'RF' followed by exactly 9 digits of number. If it is more than 9 digit or less than 9 digit It should show Invaid. I have wrote the below code, but the problem with this is , if the number is more than 9 also it is showing valid. I understand that I have written to check only if it starts with RF and followed by 9 digits, so in case of 10 digits it is obviously matching my pattern. Is

问题 I have records like RF123456789, RF1234567890 etc. I just want to match the records which are starting with 'RF' followed by exactly 9 digits of number. If it is more than 9 digit or less than 9 digit It should show Invaid. I have wrote the below code, but the problem with this is , if the number is more than 9 also it is showing valid. I understand that I have written to check only if it starts with RF and followed by 9 digits, so in case of 10 digits it is obviously matching my pattern. Is

问题 I have records like RF123456789, RF1234567890 etc. I just want to match the records which are starting with 'RF' followed by exactly 9 digits of number. If it is more than 9 digit or less than 9 digit It should show Invaid. I have wrote the below code, but the problem with this is , if the number is more than 9 also it is showing valid. I understand that I have written to check only if it starts with RF and followed by 9 digits, so in case of 10 digits it is obviously matching my pattern. Is

问题 Background For those of you not familiar with Cribbage, it uses a standard 52 card deck with aces being always low. A player's hand consists of 4 cards, and there is 1 turn card that all players can use to help score their hand. So for a little practice problem for myself, I wrote a we bit of VBA and had all ~12.9 million possible scoring combination printed in an excel sheet. I assigned each card an integer 1 to 52 and set it up so that each suit is a sequential block of 13 cards. 1-13 =

问题 Background For those of you not familiar with Cribbage, it uses a standard 52 card deck with aces being always low. A player's hand consists of 4 cards, and there is 1 turn card that all players can use to help score their hand. So for a little practice problem for myself, I wrote a we bit of VBA and had all ~12.9 million possible scoring combination printed in an excel sheet. I assigned each card an integer 1 to 52 and set it up so that each suit is a sequential block of 13 cards. 1-13 =