error-handling

An error occurs when trying to set a child to my GameObject in script

无人久伴 提交于 2020-06-27 10:45:00
问题 GameObject enemy = Instantiate(spawnObject,spawnPosition,spawnObject.transform.rotation) as GameObject; enemy.transform.parent = transform; The above code generates the expected result when I test my game in game mode, however I'm gettting this error message: "Setting the parent of a transform which resides in a prefab is disabled to prevent data corruption." Yes, the spawnObject variable contains a prefab, however creating a new GameObject should have fixed the problem, I assume? 回答1: Check

Loop will run once at most, (loop increment never executed)

廉价感情. 提交于 2020-06-25 21:36:09
问题 I have a picker view and I want the the things in it to be the tail numbers of the planes. I use this code, but I get the warning Loop will run once at most, (loop increment never executed) , and then I get the error control may each end of non-void function. What is wrong here? CODE: - (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component { for (NSInteger i = [[NSUserDefaults standardUserDefaults]integerForKey:@"planeNum"]; (i = 0);

Loop will run once at most, (loop increment never executed)

喜你入骨 提交于 2020-06-25 21:36:07
问题 I have a picker view and I want the the things in it to be the tail numbers of the planes. I use this code, but I get the warning Loop will run once at most, (loop increment never executed) , and then I get the error control may each end of non-void function. What is wrong here? CODE: - (NSString *)pickerView:(UIPickerView *)thePickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component { for (NSInteger i = [[NSUserDefaults standardUserDefaults]integerForKey:@"planeNum"]; (i = 0);

Eclipse IDE - Error: Build path specifies execution environment Java SE 1.7

主宰稳场 提交于 2020-06-24 07:14:16
问题 In Eclipse, I am getting an error: Build path specifies execution environment Java SE 1.7. There are no JREs installed in the workspace that are strictly compatible with this environment. 回答1: Try this In Eclipse, your project -> properties -> java build path : Libraries Remove the "JRE System Library[J2SE 1.4]" -> click "Add Library" button -> JRE System Library -> select the new "Executin Environment" or Workspace default JRE 回答2: Go to Project|Properties Choose the Java Build Path section

must declare a named package eclipse because this compilation unit is associated to the named module

独自空忆成欢 提交于 2020-06-22 05:30:42
问题 I just downloaded eclipse for Java Yesterday but when I was trying to get make my first program, I kept on getting this error: must declare a named package eclipse because this compilation unit is associated to the named module x. How do I fix this? 回答1: Just delete module-info.java at your Project Explorer tab. 回答2: The "delete module-info.java at your Project Explorer tab" answer is the easiest and most straightforward answer, but for those who would want a little more understanding or

must declare a named package eclipse because this compilation unit is associated to the named module

主宰稳场 提交于 2020-06-22 05:30:09
问题 I just downloaded eclipse for Java Yesterday but when I was trying to get make my first program, I kept on getting this error: must declare a named package eclipse because this compilation unit is associated to the named module x. How do I fix this? 回答1: Just delete module-info.java at your Project Explorer tab. 回答2: The "delete module-info.java at your Project Explorer tab" answer is the easiest and most straightforward answer, but for those who would want a little more understanding or

warning :: invalid object or resource mysqli_stmt. What is the meaning and solution(s)?

霸气de小男生 提交于 2020-06-21 05:08:07
问题 The following code is throwing the mysterious Warnings. I can't understand what they mean. What do these errors indicate and how to eradicate them? require "conn.php"; $q = mysqli_stmt_init($dbconn); $query = "SELECT users.userid FROM users WHERE users.email = ? "; mysqli_stmt_prepare($q, $query); mysqli_stmt_bind_param($q, "s", $email); mysqli_stmt_execute($q); $result = mysqli_stmt_get_result($q); if (mysqli_num_rows($result) == 0) { $q = mysqli_stmt_init($dbconn); $query = "INSERT INTO

warning :: invalid object or resource mysqli_stmt. What is the meaning and solution(s)?

大憨熊 提交于 2020-06-21 05:07:39
问题 The following code is throwing the mysterious Warnings. I can't understand what they mean. What do these errors indicate and how to eradicate them? require "conn.php"; $q = mysqli_stmt_init($dbconn); $query = "SELECT users.userid FROM users WHERE users.email = ? "; mysqli_stmt_prepare($q, $query); mysqli_stmt_bind_param($q, "s", $email); mysqli_stmt_execute($q); $result = mysqli_stmt_get_result($q); if (mysqli_num_rows($result) == 0) { $q = mysqli_stmt_init($dbconn); $query = "INSERT INTO

Exception in thread “main” java.lang.IllegalAccessError: failed to access class

喜欢而已 提交于 2020-06-17 14:55:06
问题 So I'm trying to run a particular file called CountdownTree.java that inherits functions from a bunch of other files in the package comp2402a4. These were all starting files given by my instructor that I'm supposed to add to, and there shouldn't be any errors running these files. I compiled it using 'javac comp2402a4/CountdownTree.java' and it compiled fine with no problems. But when I try to run it using 'java comp2402a4/CountdownTree.java', I get the error: Exception in thread "main" java

Improve mongoose validation error handling

北城以北 提交于 2020-06-16 20:49:19
问题 I have the following schema with required validations: var mongoose = require("mongoose"); var validator = require("validator"); var userSchema = new mongoose.Schema( { email: { type: String, required: [true, "Email is a required field"], trim: true, lowercase: true, unique: true, validate(value) { if (!validator.isEmail(value)) { throw new Error("Please enter a valid E-mail!"); } }, }, password: { type: String, required: [true, "Password is a required field"], validate(value) { if (