equals

Thanks to @ifaour for a lot of his help! This script includes: Jquery accordion using unordered lists. Active and Inactive states with toggling bullet arrow images Expand All / Collapse All that swaps its text. Equal height columns that expand and collapse when the accordion expands and collapses You can view a demo here http://jsbin.com/ucobo3/24/ (function($) { $.fn.equalHeights = function(minHeight, maxHeight) { tallest = (minHeight) ? minHeight : 0; this.each(function() { if($(this).height() > tallest) { tallest = $(this).height(); } }); if((maxHeight) && tallest > maxHeight) tallest =

I agree with the statement from this post What issues should be considered when overriding equals and hashCode in Java? Use the same set of fields that you use to compute equals() to compute hashCode(). But i've some doubts : Is this absolutely necessary to have same fields ? If yes, what if I don't use same field ? Will it affect HashMap performance or HashMap Accuracy ? The fields don't have to be the same. The requirement is for two objects that are equal, they must have the same hash code. If they have the same hash code, they don't have to be equal. From the javadocs: Whenever it is

Just for fun, I'm trying to implement a generic Pair class in Java. I'm having trouble with equals : public class Pair<A, B> { public final A _1; public final B _2; // ... unnecessary details left out ... public boolean equals(Pair<A, B> that) { return (_1.equals(that._1)) && (_2.equals(that._2)); } @Override public boolean equals(Object o) { return (o instanceof Pair<A, B>) && equals((Pair<A, B>) o); } } However, o instanceof Pair<A, B> does not seem to work. Why is that? Using (o instanceof Pair) && equals((Pair<A, B>) o) gives me a warning for the cast. Getting rid of the <A, B> part on the

newbie question here: So in my university homework I have to override the object class equals method for a new class created by me. The new class is "Product", each product has an "id" attribute which is unique. So this is how I Overrided it: @Override public boolean equals(Object obj) { final Product other = (Product) obj; if (id != other.id) return false; return true; } The thing is that doing this is 1,5 points out of 10 and it made me suspicius to be that easy. So i started searching and I found things like: @Override public boolean equals(Object obj) { if (this == obj) return true; if

Maybe I've been working too long on Java without really understanding some of its basics. I do understand that == is for object reference equality and .equals() is for object value equality. Comparing Integers : Integer x = 1, y = 1; System.out.println(x == y); // true Why? Since object reference equality is used, it should be false since they are both different objects. Comparing getClass() return values: String s1 = "a", s2 = "b"; System.out.println(s1.getClass() == s2.getClass()); // true Why? Again as per above, object reference is used. Both using getClass will return separate Class