epoch

前置条件：需要编译 ngx_http_headers_module 模块，才支持 header 头信息操作 add_header 意思为将自定义的头信息的添加到响应头，指令为 add_header name value [always];，可以用在 http {}, server {}, location {}, if in location {} 上下文中， 只有当响应状态码等于 200, 201 (1.3.10), 204, 206, 301, 302, 303, 304, 307 (1.1.16, 1.0.13), 或 308 (1.13.0) 时生效，如果 always 参数指定了，头信息将无视状态码，在所有响应中强制返回。 注意: 可以声明多个 add_header 指令，当且仅当 当前区块没有 add_header 的时候，才会继承上级声明的 add_header 信息 例如： server { add_header a 123; location / { root /path; } location /download/ { add_header b 321; } } 如上的例子，在访问 /download/ 路由的时候，将返回 b 321 这样的头信息，而访问 / 路由时，将返回上级指定的 a 123 头信息。 add_trailer

How do I extract the epoch value to Long from instances of LocalDateTime or LocalDate ? I've tried the following, but it gives me other results: LocalDateTime time = LocalDateTime.parse("04.02.2014 19:51:01", DateTimeFormatter.ofPattern("dd.MM.yyyy HH:mm:ss")); System.out.println(time.getLong(ChronoField.SECOND_OF_DAY)); // gives 71461 System.out.println(time.getLong(ChronoField.EPOCH_DAY)); // gives 16105 What I want is simply the value 1391539861 for the local datetime "04.02.2014 19:51:01" . My timezone is Europe/Oslo UTC+1 with daylight saving time. The classes LocalDate and LocalDateTime

What I want to do is convert an epoch time (seconds since midnight 1/1/1970) to "real" time (m/d/y h:m:s) So far, I have the following algorithm, which to me feels a bit ugly: void DateTime::splitTicks(time_t time) { seconds = time % 60; time /= 60; minutes = time % 60; time /= 60; hours = time % 24; time /= 24; year = DateTime::reduceDaysToYear(time); month = DateTime::reduceDaysToMonths(time,year); day = int(time); } int DateTime::reduceDaysToYear(time_t &days) { int year; for (year=1970;days>daysInYear(year);year++) { days -= daysInYear(year); } return year; } int DateTime:

I am parsing an SQLite database using the PowerShell SQLite module, and a couple of the return values are created and modified, both of which are in Unix time. What I would like to do is somehow convert that into "human time". I have removed some of the other SQL queries for ease of reading. Import-Module SQLite mount-sqlite -name GoogleDrive -dataSource E:\Programming\new.db $cloud_entry = Get-ChildItem GoogleDrive:\cloud_entry foreach ($entry in $cloud_entry) { $entry.created } The output looks like a large column of Unix timestamps: 1337329458 Update : I ultimately went with the following:

I have a date inside a string, something like "12-December-2012". How can I convert this into milliseconds (long)? Jon Lin Using SimpleDateFormat String string_date = "12-December-2012"; SimpleDateFormat f = new SimpleDateFormat("dd-MMM-yyyy"); try { Date d = f.parse(string_date); long milliseconds = d.getTime(); } catch (ParseException e) { e.printStackTrace(); } SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy"); Date date = (Date)formatter.parse("12-December-2012"); long mills = date.getTime(); Take a look to SimpleDateFormat class that can parse a String and return a Date and