epoch

How can one convert a serial date number, representing the number of days since epoch (1970), to the corresponding date string? I have seen multiple posts showing how to go from string to date number, but I haven't been able to find any posts on how to do the reverse. For example, 15951 corresponds to "2013-09-02" . >>> import datetime >>> (datetime.datetime(2013, 9, 2) - datetime.datetime(1970,1,1)).days + 1 15951 (The + 1 because whatever generated these date numbers followed the convention that Jan 1, 1970 = 1.) TL;DR: Looking for something to do the following: >>> serial_date_to_string

This question already has an answer here: Convert string date to timestamp in Python 13 answers I am using tweepy to get a tweet. I am trying to send this tweet over Slack. Tweepy gives the time in a strange format, and Slack requires the time in epoch. for i in tweets: created=(i.created_at) print(created) print(created.strftime('%s')) This returns 2017-01-17 14:36:26 Traceback (most recent call last): File "C:\Users\Administrator\Desktop\slackbot3\run.py", line 287, in main print(created.strftime('%s')) ValueError: Invalid format string How can I get 2017-01-17 14:36:26 into epoch time? You

This question already has an answer here: Convert a date format in epoch 5 answers Is there a way to convert a given Date String into Milliseconds ( Epoch Long format) in java? Example : I want to convert public static final String date = "04/28/2016"; into milliseconds (epoch). The getTime() method of the Date class returns the number of milliseconds since January 1, 1970, 00:00:00 GMT represented by this Date object. You can simply parse it to java.util.Date using java.text.SimpleDateFormat and call it's getTime() function. It will return the number of milliseconds since Jan 01 1970. public

I have been using Processing 3.0, and I am trying to print a simple timestamp when my Arduino outputs certain values, but it is not working. I tried to use SimpleDateFormat, but it always returns 1970.01.17 17:48:35 GMT , rather than the actual time. Below is the MVCE: void setup () { SimpleDateFormat format = new SimpleDateFormat ("yyyy.MM.dd HH:mm:ss z"); format.setTimeZone (TimeZone.getDefault()); long timestamp = getTimeNow(); println(format.format(new Date(timestamp))); println(timestamp); } long getTimeNow () { Date d = new Date (); Calendar cal = new GregorianCalendar(); long current =

I am attempting to write a Perl script that parses a log where on each line the second value is the date. The script takes in three arguments: the input log file, the start time, and the end time. The start and end time are used to parse out a certain value on each line that that falls between those two times. But to properly run this I am converting the start and end time to epoch time. The problem I am having is that to convert the loops 'i' value back to normal time to compare against the log file. After running localtime($i) I print the value and only see a reference printed not the actual

Redis-Cluster 实战- 转载请注明出处哈 : http://carlosfu.iteye.com/blog/2240426 一、准备 redis( 下载、编译、安装、配置目录、数据目录 ) 1. 下载、编译、安装 Java代码 cd /opt/soft wget http://download.redis.io/releases/redis-3.0.3.tar.gz tar xzf redis-3.0.3.tar.gz cd redis-3.0.3 make make install 2. 配置目录、数据目录 Java代码 cd /opt/soft/redis-3.0.3 mkdir -p data mkdir -p conf 3. 建立软链接： Java代码 ln -s /opt/soft/redis-3.0.3 /opt/soft/redis 二、配置、启动 Redis 节点（本例子以 3 主、 3 从组成 Redis-Cluster ） (1) 配置 redis 节点，在 conf 目录下添加 6 个 (7000-7005)redis-${port}.conf 作为 6 个节点的配置文件 其中 7000-7005 是六个端口号 Java代码 port 7000 cluster-enabled yes cluster-config-file nodes-7000

I'm working with dates since epoch, and already got, for example: date = 6928727.56235 I'd like to transform this into another relative format, so that I'll be able to transform this into something relative to epoch. Using time.gmtime(date), it returned year=1970, mon=3, day=22, hour=4, min=38, sec=47 I think epoch starts in '01/01/1970 00:00:00', so the method should return the relative date in something like: '2 months 21 days 04:38:47' Anything that help? from datetime import timedelta a = timedelta(seconds=6928727.56235) # a is now datetime.timedelta(80, 16727, 562350) print "%d days %02d:

I'm aware that the default value of a std::chrono::system_clock::time_point is the clock's epoch, but I can't find any mandate in the C++11 standard that system_clock 's epoch is the same as the POSIX epoch (1970-01-01T00:00:00Z). Is it safe to assume on Linux and Windows that this is the case? Or would it be smarter to use std::chrono::system_clock::from_time_t(0) ? The standard leaves the epoch of std::chrono::system_clock::time_point unspecified. There are three implementations of std::chrono::system_clock::time_point I am aware of: libc++ libstdc++ VS All three of these are thin wrappers

一、Kafka在zookeeper中存储结构图 二、分析 2.1　topic注册信息 /brokers/topics/[topic] : 存储某个topic的partitions所有分配信息 [zk: localhost: 2181 (CONNECTED) 1 ] get /brokers/topics/topic2 Schema: { " version " : " 版本编号目前固定为数字1 " , " partitions " : { " partitionId编号 " : [ 同步副本组brokerId列表 ], " partitionId编号 " : [ 同步副本组brokerId列表 ], ....... } } Example: { "version": 1, "partitions": { "2": [1, 2, 3], "1": [0, 1, 2], "0": [3, 0, 1 ], } } 2.2　partition状态信息 /brokers/topics/[topic]/partitions/[0...N] 其中[0..N]表示partition索引号 /brokers/topics/[topic]/partitions/[partitionId]/state Schema: { " controller_epoch " :

In Instant there are methods: toEpochMilli which converts this instant to the number of milliseconds from the epoch of 1970-01-01T00:00:00Z getEpochSecond which gets the number of seconds from the Java epoch of 1970-01-01T00:00:00Z . Both of these methods lose precision, e.g. in toEpochMilli JavaDoc I see: If this instant has greater than millisecond precision, then the conversion drop any excess precision information as though the amount in nanoseconds was subject to integer division by one million. I don't see corresponding methods to obtain more precise timestamp. How can I get number of