epoch

redis sentinel 安装

由 时光总嘲笑我的痴心妄想 提交于 2019-12-16 21:09:13
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 启动方式 redis-server redis-6381.conf /rdb/6380/redis-6381.conf port 6380 bind 127.0.0.1 requirepass "myredis" daemonize yes logfile "6381.log" dbfilename "dump-6381.rdb" dir "/Users/huitingting/notes/rdb/6380" #如若master设置了认证密码，那么所有redis数据节点都配置上masterauth属性 #masterauth "myredis" slaveof 127.0.0.1 6379 ~/notes/rdb/rdb_sentinel/26379/sentinel-26379.conf #filename: sentinel-26379.conf port 26379 daemonize yes logfile "26379.log" dir "/Users/huitingting/notes/rdb/rdb_sentinel/26379" #redis数据master节点设置了认证，则需要如下配置 # sentinel myid

Looping through JSON array and print out same key values

由 你说的曾经没有我的故事 提交于 2019-12-14 04:06:54
问题 Have JSON array with multiple keys of same which shows time in epoch, want to print then out and convert time to EST { "contents":[ { "name":"windows-Instance", "Buildid":"1234", "Buildtime":"1563350400238" }, { "name":"linux-Instance", "Buildid":"1454", "Buildtime":"1563264000198" }, { "name":"linux-Instance", "Buildid":"1278685", "Buildtime":"1563177600092" } ] } 回答1: You can try this out to print each objects converted Epoch to current timezone: Function Get-EpochDate ($epochDate) {

Perl convert microseconds since epoch to localtime

由 ℡╲_俬逩灬. 提交于 2019-12-14 04:03:39
问题 In perl, given microseconds since epoch how do I convert to localtime in a format like my $time = sprintf "%02ld,%02ld,%02ld.%06ld", $hour, $min, $sec, $usec; Eg: "Input = 1555329743301750 (microseconds since epoch) Output = 070223.301750" 回答1: The core Time::Piece can do the conversion, but it doesn't handle subseconds so you'd need to handle those yourself. use strict; use warnings; use Time::Piece; my $input = '1555329743301750'; my ($sec, $usec) = $input =~ m/^([0-9]*)([0-9]{6})$/; my

Conversion from UNIX time to timestamp starting in January 1, 2000

由 僤鯓⒐⒋嵵緔 提交于 2019-12-14 00:23:30
问题 I am trying to interact with an API that uses a timestamp that starts at a different time than UNIX epoch. It appears to start counting on 2000-01-01, but I'm not sure exactly how to do the conversion or what the name of this datetime format is. When I send a message at 1456979510 I get a response back saying it was received at 510294713. The difference between the two is 946684796 (sometimes 94668479 7 ) seconds, which is approximately 30 years. Can anyone let me know the proper way to

Cron Expression To List of Dates/Timepoints

由 和自甴很熟 提交于 2019-12-13 13:13:46
问题 I was wondering what is the most efficient way/best library to parse a cron expression and return a list of time points in Java. For example I would have a cron expression, say, Fire every minute in October 2010 and would get a list/array of epoch times (or some other date format) returned that correspond to the times the trigger fires. Thanks 回答1: You could use org.quartz.CronExpression.getNextValidTimeAfter() . Using this method you can iteratively get as many trigger times as you wish. You

如何测量函数执行所需的时间

由 老子叫甜甜 提交于 2019-12-13 09:57:46
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 我需要获取执行时间（以毫秒为单位）。 我最初是在2008年问这个问题的。当时接受的答案是使用 new Date（）。getTime（）。 但是，我们现在都同意使用标准 performance.now（） API更合适。 因此，我正在改变对此的公认答案。 #1楼 不要使用Date（）。 参见下文。 使用 performance.now() ： <script> var a = performance.now(); alert('do something...'); var b = performance.now(); alert('It took ' + (b - a) + ' ms.'); </script> 它适用于： IE 10 ++ 火狐15 ++ 铬24 ++ Safari 8 ++ Opera 15 ++ Android 4.4 ++ 等等 console.time 对您来说 可能是可行 的 ，但这是非标准的 § ： 此功能是非标准的，不在标准轨道上。 请勿在面向Web的生产站点上使用它：它不适用于每个用户。 实现之间 也 可能存在很大的不兼容性， 并且将来的行为可能会更改。 除了浏览器支持， performance.now 似乎因为它似乎是的裸机版本，必须提供更准确的计时的 潜力 console

Issue converting epoch time to standard convention in Perl

由 Deadly 提交于 2019-12-13 08:32:28
问题 In Perl I am trying to convert a variable containing millisecond epoch time variable $adjSendTime to standard convention using the following code: $timeLabel = sprintf("%02d:%02d:%02d", (($adjSendTime/3600000) % 24), (($adjSendTime/60000) % 60), $currentSecond); The issue is that whenever it has reach the 59th second the minute portion of the time will be on minute higher than it should be. The output looks something like 11:58:57 11:58:58 11:59:59 11:59:00 11:59:01 The calculation for

How to convert ( round ) epoch Time to nearest hour and day wrt IST (in Java)

由 非 Y 不嫁゛ 提交于 2019-12-13 06:01:29
问题 I have time in epoch format (as Java long variable). I want to convert it to nearest hour as well as day with respect to Indian Standard Time (IST). For example, if the epoch time is 1372618032000 (7/1/2013 12:17:12 AM IST), then i want to get 1372620600000 (7/1/2013 1:00:00 AM IST). Similarly for day rounding. I want to get 1372703400 (7/2/2013 12:00:00 AM IST). [Starting of the next day.] I have gone through some documentation of Java Date, Java Calendar, Apache DateUtils, and JodaTime. But

How dose the setting of steps_per_epoch and epochs affect the training result in Keras?

由 我只是一个虾纸丫 提交于 2019-12-13 05:26:51
问题 My generator always yields two images from my dataset randomly and then I calculate the loss using this two samples. Say I set steps_per_epoch=40 and epochs=5 , what's the difference if I set steps_per_epoch=5 and epochs=40 (I use Adam for my optimizer)? 回答1: The epochs argument (also called iteration) refers to the number of full passes over the whole training data. The steps_per_epoch argument refers to the number of batches generated during one epoch. Therefore we have steps_per_epoch = n

Obtain Day of the week from epoch

由 ℡╲_俬逩灬. 提交于 2019-12-12 20:05:35
问题 I have epoch time and I am trying to get the day of the week. For example lets say I get time as 16/04/2015 16:03:56. I want to find out what day is 16th (Monday, Tuesday... ) scala> import java.text.SimpleDateFormat import java.text.SimpleDateFormat scala> import java.util.{TimeZone, Locale} import java.util.{TimeZone, Locale} scala> dateFormat.setTimeZone(TimeZone.getTimeZone("Etc/UTC")) scala> val dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss", Locale.US) Following code will
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