epoch

问题 This question already has answers here : SimpleDateFormat producing wrong date time when parsing “YYYY-MM-dd HH:mm” (4 answers) Closed last year . I want to convert 2018-02-21 15:47:35 UTC to epoch UTC form. How do we do it? I am currently in PST. SimpleDateFormat df = new SimpleDateFormat("YYYY-MM-DD HH:MM:SS"); df.setTimeZone(TimeZone.getTimeZone("UTC")); date = df.parse(dateString).getTime(); The code above should return the number of milliseconds since January 1, 1970, 00:00:00 GMT , but

问题 This question already has answers here : SimpleDateFormat producing wrong date time when parsing “YYYY-MM-dd HH:mm” (4 answers) Closed last year . I want to convert 2018-02-21 15:47:35 UTC to epoch UTC form. How do we do it? I am currently in PST. SimpleDateFormat df = new SimpleDateFormat("YYYY-MM-DD HH:MM:SS"); df.setTimeZone(TimeZone.getTimeZone("UTC")); date = df.parse(dateString).getTime(); The code above should return the number of milliseconds since January 1, 1970, 00:00:00 GMT , but

问题 I am having trouble converting posix_time::ptime to a timestamp represented by time_t or posix_time::milliseconds , or any other appropriate type which can be easily printed (from Epoch). I actually need just to print the timestamp represented by the posix_time::ptime in milliseconds, so if there is an easy way to print in that format, I don't actually need the conversion. 回答1: This code will print the number of milliseconds since 1941-12-07T00:00:00. Obviously, you can choose whatever epoch

问题 So I understand from this question that the integer used in the construction of a chrono::year corresponds to the Anno Domini origin of 0. So my question is, what if I wanted to get the current chrono::year . Is there a function for that? I can obviously do: const auto time = std::time(nullptr); const auto current_date = *std::gmtime(&time); const chrono::year foo{ current_date.tm_year + 1900 }; But that seems like a pretty convoluted process. Is there anything better available to me? 回答1:

问题 I have a table like this: id | date ---- | ----------- 1 | 1319043263 2 | 1319043578 which date field format is in epoch. I have to group every row that belongs to same day and show them in a separate group. How can I do that in MySQL? Thanks. 回答1: Group By: SELECT COUNT(`id`) AS `Records`, DATE(FROM_UNIXTIME(`date`)) AS `Date` FROM `table` GROUP BY DATE(FROM_UNIXTIME(`date`)) Output: Records | Date -------------------------------- 10 | 2011-10-19 10 | 2011-10-18 Order By: SELECT `id`, FROM

问题 I'm aware that the default value of a std::chrono::system_clock::time_point is the clock's epoch, but I can't find any mandate in the C++11 standard that system_clock 's epoch is the same as the POSIX epoch (1970-01-01T00:00:00Z). Is it safe to assume on Linux and Windows that this is the case? Or would it be smarter to use std::chrono::system_clock::from_time_t(0) ? 回答1: The standard leaves the epoch of std::chrono::system_clock::time_point unspecified. There are three implementations of std

问题 I have some data in FirebaseDatabase in which every data set has two properties: startTime and endTime . Here's the data-structure: app -ref -uniqueID1 -key: value -startTime: 1488849333 -endTime: 1488853842 -key: value -uniqueID2 -key: value -startTime: 1488850198 -endTime: 1488853802 -key: value What I want is to deleted the data set when the endTime has passed automatically or when the user opens the app. I have done some research on this topic and found this, but this doesn't seems

问题 I've got a pandas.Series object that might look like this: import pandas as pd myVar = pd.Series(["VLADIVOSTOK 690090", "MAHE", NaN, NaN, "VLADIVOSTOK 690090", "2000-07-01 00:00:00"]) myVar[5] is parsed as a datetime.datetime object when the data is read into Python via pandas . I'm assuming that converting this value to the number of days since epoch (36708) isn't difficult at all. I'm just new to Python and don't know how to do it. Thanks in advance! 回答1: myVar = pd.Series(["VLADIVOSTOK

问题 I want the UNIX Epoch Time (Posix Time, Unix Time) of a string in some pattern , the string is in normal format (so UTC). Please using Java 8, not Joda or old Java. (For milliseconds please see How to convert a date time string to long (UNIX Epoch Time) Milliseconds in Java 8 (Scala)) So far I have the below, but I hate this for a number of reasons: It's way too verbose for what is the most common thing to do with dates (convert to UNIX Epoch Time). 7 method calls for what should be 1. It has

问题 Could you help me convert UNIX epoch time into format yyyy-mm-dd hh:mm:ss (24h) in SQLite? (GMT+7 would be appreciated). Example: from 1319017136629 to Wednesday, October 19, 2011 4:38:56 PM GMT+7 . p/s: Just looked around and found a solution: SELECT datetime(1319017136629, 'unixepoch', 'localtime'); But i am still looking for a way to batch convert UNIX epoch time in SQLite. 回答1: To change the values in the database, use the UPDATE command: UPDATE MyTable SET MyColumn = datetime(MyColumn,