eof

Some code style tools recommend this and I remember seeing some unix command line tools warning about missing empty line. What is the reasoning for having an extra empty line? Many older tools misbehave if the last line of data in a text file is not terminated with a newline or carriage return / new line combination. They ignore that line as it is terminated with ^Z (eof) instead. If you try to concatenate two text files together, you will be much happier if the first one ends with a newline character. Apart from the fact that it is a nicer cursor position when you move to the end of a file in

This question already has an answer here: Difference between int and char in getchar/fgetc and putchar/fputc? 2 answers The program below runs fine on various Solaris/Linux flavours, but not on AIX. However, if I replace while(c!=EOF) with while(c!=0xff) on AIX it runs completely fine. Any thoughts? I checked the fgetc man page on AIX, and it should return the EOF constant! #include <stdio.h> #include<unistd.h> #include <string.h> int main() { char c; FILE *fp; fp = fopen("a.txt", "r"); c=fgetc(fp); while(c!=EOF) { c=fgetc(fp); printf("%d",c); } fclose(fp); return 0; } The return value of

Let’s say I have the following Bash script: while read SCRIPT_SOURCE_LINE; do echo "$SCRIPT_SOURCE_LINE" done I noticed that for files without a newline at the end, this will effectively skip the last line. I’ve searched around for a solution and found this : When read reaches end-of-file instead of end-of-line, it does read in the data and assign it to the variables, but it exits with a non-zero status. If your loop is constructed "while read ;do stuff ;done So instead of testing the read exit status directly, test a flag, and have the read command set that flag from within the loop body.

I've been reading "The C Programming Language" and I got to this part of inputs and outputs. I've read other threads saying that the console doesn't recognize enter as EOF . So that I should use CTRL + Z in Windows or CTRL + D in Unix (neither of those is working for me). I also read other people asking the same saying they could make it work, the problem in their codes was syntax not the program not terminating. Is there another solution? This is the code: #include <stdio.h> main() { int nb, nl, nt, c; nb = 0; nl = 0; nt = 0; while ((c = getchar()) != '\n'){ if (c == ' ') ++nb; else if (c ==