eof

Vim no end of line on last line or eof

由 自作多情 提交于 2019-12-02 18:34:05
I am trying to setup vim to skip adding eol on last line or eof, i have tried this :set binary :set noeol :w which is not perfect cause binary override filetype for later use. Any other option to set this, i don't need newline on last line. I wanted to add an answer that I think can be as useful. The selected answer always remove the EOL on files even if they had one to begin with. This may be the behavior that you want, it also may not be. In my opinion I want to preserve the EOL as I originally opened the file. What I suggest is a slight modification. Put set binary at the top of your .vimrc

Why can Windows not read beyond the 0x1A (EOF) character but Unix can? [duplicate]

由 China☆狼群 提交于 2019-12-02 16:33:26
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Why failbit set when eof on read? Is there a way out? I am writing a little program and it was working brilliantly on Mac OS and Ubuntu (Unix...). The program has to read in a data file and separate the bytes ( char s / unsigned char s) and memcpy() them into floats. This would include the process of taking say the following four values, reading & left shifting them into a 32bit int and then copying the int s

How to return to terminal when logstash filter get eof?

由 吃可爱长大的小学妹 提交于 2019-12-02 16:29:43
问题 Now when logstash filter get eof, it seems that logstash filter is running yet, but file doesn't have more logs to output to elasticsearch index. How can i get out of logstash filter when it's the end of file (eof), to do another tasks? 回答1: I solve the problem using exec on output of logstash filter, and create a bash script to kill logstash process. In logstash filter: input { ... } filter { ... } output { exec { command => "sh kill_logstash.sh" } ... } In bash script (kill_logstash.sh): #!

getchar() doesn't pass EOF and Ctrl+Z doesn't terminate the program on Cygwin

由 杀马特。学长 韩版系。学妹 提交于 2019-12-02 14:13:30
问题 Here is a simple program, counting strings, symbols and words. Everything is ok with the computation, using Cygwin. But while launching, after input values, the program doesn't print nc , nw , nl and wait for entering further values. Changing EOF to 13 (Enter) doesn't help anyway. ctrl + Z is useful too: the program is stopping, writing [n]+ Stopped , where 'n' is always different number. The code is #include <stdio.h> #define IN 1 #define OUT 0 int main () { char c; int state; int nc, nw, nl

c++ EOF running one too many times?

由 好久不见. 提交于 2019-12-02 14:01:37
问题 This is my first time using EOF and/or files, and I am having an issue where my code hangs, which I believe is because my EOF is looping one too many times. I am imputing from a file, and dynamically creating objects that way, and it hangs once the file is run through. while( !studentFile.eof() ) { cout << "38\n"; Student * temp = new Student(); (*temp).input( studentFile ); (*sdb).insert( (*temp) ); } This chunk of code is the code in question. The cout >> "38\n"; is the line number and the

PHP EOF shows only one result from loop

由 丶灬走出姿态 提交于 2019-12-02 12:38:18
I am using in my PHP EOF. The problem is that it does display only one item coming from a mySQL loop. It shows only the last result. Is this necessary in EOF? or can I avoid this issue? Thanks function getYiBAdminBanner() { global $site; global $dir; $queryYiBmenu = "SELECT * FROM `(YiB)_cPanel_Menu` WHERE Type = 'top'"; $resultYiBmenu=mysql_query($queryYiBmenu) or die("Errore select menu: ".mysql_error()); $countYiBmenu = mysql_num_rows($resultYiBmenu); while($rowYiBmenu = mysql_fetch_array($resultYiBmenu)) { $menu = "<div id=\"menu\" style=\"display:none;\"><li><a href=\"".$site['url'].

END OF FILE token with flex and bison (only works without it)

由 走远了吗. 提交于 2019-12-02 10:12:55
问题 OK this is kind of an odd question because what I have here works the way I want it to. What I'm doing is writing a parser for a lambda calculus expression. So an expression can be one of four things: variable constant (expression expression) (lambda variable.expression) Now as you can see, the last two expressions have expressions within them. What I was trying to do was determine the overall expression so I can report which type it is. So for example the expression ((lambda x.(f1 x)) 100)

How does the EOF macro work with getchar?

由 邮差的信 提交于 2019-12-02 09:15:35
#include<stdio.h> int main(void) { FILE *fp; int ch; fp = fopen("input.txt", "w"); printf("Enter data"); while ((ch = getchar()) != EOF) { putc(ch, fp); } fclose(fp); fp = fopen("input.txt", "w"); while ((ch = getc(fp)) != EOF) { printf("%c", ch); } fclose(fp); } How does the first while loop stop inputting from user? Since there is EOF present as a condition. Or else do I need to use for loop? Sourav Ghosh EOF is a value, not a function. It is essentially defined as a macro. For reference, from C11 , chapter §7.21.1, <stdio.h> EOF which expands to an integer constant expression, with type int

How to end scanf by entering only one EOF

由 筅森魡賤 提交于 2019-12-02 09:09:41
问题 I am encoutering this problem. I am using while loop to scan string of numbers and need to end scanning and start proceeding the rest of my program. I just can't figure out, how to flush the stdin or do anything to not press Ctrl+D twice. I just need to send EOF only once to tell my loop to end. while (! feof (stdin)) {status=scanf ("%d", &array[i]); if ( (status != 1 && status != EOF) ) { printf("\nWrong input.\n"); return 1;} i++;} 回答1: Edit: it's bug 1190 on glibc, it was apparently done

How to end scanf by entering only one EOF

由 这一生的挚爱 提交于 2019-12-02 06:23:23
I am encoutering this problem. I am using while loop to scan string of numbers and need to end scanning and start proceeding the rest of my program. I just can't figure out, how to flush the stdin or do anything to not press Ctrl+D twice. I just need to send EOF only once to tell my loop to end. while (! feof (stdin)) {status=scanf ("%d", &array[i]); if ( (status != 1 && status != EOF) ) { printf("\nWrong input.\n"); return 1;} i++;} Edit: it's bug 1190 on glibc , it was apparently done purposefully for System V compatibility (and Solaris behaves in the same way, FreeBSD and NetBSD behave as
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