enums

Only first element of Enum list is displayed instead of Entire list in Swagger

孤者浪人 提交于 2020-08-10 23:15:48
问题 Below is the generated YAML from python execution requestBody: content: application/json: schema: properties: element_ids: items: type: string type: array element_type: items: enum: - NC - CELL type: string type: array expires_in: format: int32 type: integer group_id: type: string required: - element_ids - element_type - expires_in - group_id I have provided my enum values in the form of list. I see only NC in the swagger(3.0.0) shown below 回答1: Your spec is correct. "Example Value" displays

Only first element of Enum list is displayed instead of Entire list in Swagger

雨燕双飞 提交于 2020-08-10 23:13:12
问题 Below is the generated YAML from python execution requestBody: content: application/json: schema: properties: element_ids: items: type: string type: array element_type: items: enum: - NC - CELL type: string type: array expires_in: format: int32 type: integer group_id: type: string required: - element_ids - element_type - expires_in - group_id I have provided my enum values in the form of list. I see only NC in the swagger(3.0.0) shown below 回答1: Your spec is correct. "Example Value" displays

Is there no problem using enumeration without declaration of enum variable in C?

折月煮酒 提交于 2020-08-07 18:24:28
问题 I'm confused with how exactly the enum-type variable and int-type variable works different in C. I heard there could be a casting error between enum type and integer type in C++, but C doesn't. Then if there's no difference between integer variable and enum type variable in C, can I just declare enum names and use them without declaring any that enum type variables, for example, ... enum { WIN, LOSE, DRAW }; int main() { int result; result = play_game(...); if (result == WIN) { ... } else if

How to get enum value of raw type from an enum class and a string in kotlin

别等时光非礼了梦想. 提交于 2020-08-07 06:07:51
问题 I have the following code in java: Enum getEnumValue(Class<?> enumClass, String value) { return Enum.valueOf((Class<Enum>) enumClass, value); } How to rewrite this in Kotlin? Update enumValueOf<>() function is not applicable in this case because I don't know the actual type parameter, I only have a Class<?> object with unknown type ( Class<*> in kotlin) and a name string. The Class is known to be enum: Class.isEnum returns true. Using these two inputs, the java code above allows to obtain the

How from Entity to DTO if Entity has an Enum variable?

隐身守侯 提交于 2020-08-05 09:34:31
问题 I'm creating DTO versions of all my entities. I have a problem with an entity that has one Enum value. This is my entity: @Getter @Setter @Table(name = "TIPOS_MOVIMIENTO") @Entity public class TipoMovimiento { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; @Column @Convert(converter = TipoMovEnumConverter.class) private TipoMov tipo; public String getTipo() { return tipo.getTipoNombre(); } @OneToMany(mappedBy = "tipoMov") private List<Movimiento> movimientos; No, I

How can I construct an enum.Enum from a dictionary of values?

≯℡__Kan透↙ 提交于 2020-08-04 04:26:19
问题 I'd like to generate some types at runtime from a config file. For simplity, let's assume I already have the data loaded as a python dictionary: color_values = dict(RED = 1, YELLOW = 2, GREEN = 3) How can I transform this into the type (using enum) class Color(enum.Enum): RED = 1 YELLOW = 2 GREEN = 3 The following doesn't work def make_enum(name, values): return type(name, (enum.Enum,), values) >>> Color = make_enum('Color', color_values) AttributeError: 'dict' object has no attribute '

How can I construct an enum.Enum from a dictionary of values?

大兔子大兔子 提交于 2020-08-04 04:26:17
问题 I'd like to generate some types at runtime from a config file. For simplity, let's assume I already have the data loaded as a python dictionary: color_values = dict(RED = 1, YELLOW = 2, GREEN = 3) How can I transform this into the type (using enum) class Color(enum.Enum): RED = 1 YELLOW = 2 GREEN = 3 The following doesn't work def make_enum(name, values): return type(name, (enum.Enum,), values) >>> Color = make_enum('Color', color_values) AttributeError: 'dict' object has no attribute '

Update enum column types in knex migration

a 夏天 提交于 2020-08-03 04:20:08
问题 I'm looking to write a migration string to add a new string to the enum column type. I'm trying to add gamma to the service column. I tried with this code below. This collides because the table and the column already exists. const table = 'user_associations' export function up (knex, Promise) { return knex.schema.table(table, function (table) { table.enu('service', ['alpha', 'beta', 'gamma']).notNullable() }) } export function down (knex, Promise) { return knex.schema.table(table, function

Enum multiple cases with the same value in Swift

早过忘川 提交于 2020-08-02 05:57:08
问题 In C you could make your enums have this: typedef enum _Bar { A = 0, B = 0, C = 1 } Bar; In Swift I want to make the equivalent. However, the compiler complains that it isn't unique. How do I tell it that I want two cases to have the same value? enum Bar : Int { case A = 0 case B = 0 // Does not work case C = 1 } I've tried case A | B = 0 and case A, B = 0 But it doesn't seem to work as I want it to. 回答1: Swift doesn't support duplicated values (or "aliases" semantically). If you don't mind,

Enum multiple cases with the same value in Swift

主宰稳场 提交于 2020-08-02 05:57:06
问题 In C you could make your enums have this: typedef enum _Bar { A = 0, B = 0, C = 1 } Bar; In Swift I want to make the equivalent. However, the compiler complains that it isn't unique. How do I tell it that I want two cases to have the same value? enum Bar : Int { case A = 0 case B = 0 // Does not work case C = 1 } I've tried case A | B = 0 and case A, B = 0 But it doesn't seem to work as I want it to. 回答1: Swift doesn't support duplicated values (or "aliases" semantically). If you don't mind,