enumeration

multi-column factorize in pandas

我是研究僧i 提交于 2019-11-29 01:23:53
问题 The pandas factorize function assigns each unique value in a series to a sequential, 0-based index, and calculates which index each series entry belongs to. I'd like to accomplish the equivalent of pandas.factorize on multiple columns: import pandas as pd df = pd.DataFrame({'x': [1, 1, 2, 2, 1, 1], 'y':[1, 2, 2, 2, 2, 1]}) pd.factorize(df)[0] # would like [0, 1, 2, 2, 1, 0] That is, I want to determine each unique tuple of values in several columns of a data frame, assign a sequential index

Java getting the Enum name given the Enum Value

倾然丶 夕夏残阳落幕 提交于 2019-11-29 00:53:39
How can I get the name of a Java Enum type given its value? I have the following code which works for a particular Enum type, can I make it more generic ? public enum Category { APPLE("3"), ORANGE("1"), private final String identifier; private Category(String identifier) { this.identifier = identifier; } public String toString() { return identifier; } public static String getEnumNameForValue(Object value){ Category[] values = Category.values(); String enumValue = null; for(Category eachValue : values) { enumValue = eachValue.toString(); if (enumValue.equalsIgnoreCase(value)) { return eachValue

Populate an enum with values from database

对着背影说爱祢 提交于 2019-11-29 00:07:18
问题 I have a table which maps String->Integer. Rather than create an enum statically, I want to populate the enum with values from a database. Is this possible ? So, rather than delcaring this statically: public enum Size { SMALL(0), MEDIUM(1), LARGE(2), SUPERSIZE(3) }; I want to create this enum dynamically since the numbers {0,1,2,3} are basically random (because they are autogenerated by the database's AUTOINCREMENT column). 回答1: No. Enums are always fixed at compile-time. The only way you

Is the order in which handles are returned by EnumWindows meaningful?

坚强是说给别人听的谎言 提交于 2019-11-28 21:19:04
From a couple of preliminary tests it seems that EnumWindows always returns windows in reverse instantiation order, i.e. most recently instantiated window first. Is that a valid observation? If so, is it true across all versions of Windows? And is this a reliable assumption, i.e. is that behaviour documented somewhere? Context: I'm dealing with a situation where I am triggering a third-party application to open several non-modal windows and I need to send some window messages to those windows once they're open, yet I have no sure-fire way of identifying them as neither their window classes nor

Get to get all child scopes in Angularjs given the parent scope

社会主义新天地 提交于 2019-11-28 21:15:01
I would like to know how to get a list of all child scopes given a parent scope. All I can find from the properties of the scope are $$childHead, $$childTail, $$nextSibling and $$prevSibling. The approach I'm using now is to get the childHead from the parent and then using the nextSibling to get the next child until nextSibling is null. Is there a better approach? Given that I want to call a method [getModel] on all the children, is there again a better way of doing this? Mark Rajcok The child directives are using isolated scopes and at such have their own values which are not visible from the

eliminating duplicate Enum code

半世苍凉 提交于 2019-11-28 21:12:26
问题 I have a large number of Enums that implement this interface: /** * Interface for an enumeration, each element of which can be uniquely identified by it's code */ public interface CodableEnum { /** * Get the element with a particular code * @param code * @return */ public CodableEnum getByCode(String code); /** * Get the code that identifies an element of the enum * @return */ public String getCode(); } A typical example is: public enum IMType implements CodableEnum { MSN_MESSENGER("msn

How to count the number of lines in an Objective-C string (NSString)?

主宰稳场 提交于 2019-11-28 21:11:11
I want to count the lines in an NSString in Objective-C. NSInteger lineNum = 0; NSString *string = @"abcde\nfghijk\nlmnopq\nrstu"; NSInteger length = [string length]; NSRange range = NSMakeRange(0, length); while (range.location < length) { range = [string lineRangeForRange:NSMakeRange(range.location, 0)]; range.location = NSMaxRange(range); lineNum += 1; } Is there an easier way? cobbal well, a not very efficient, but nice(ish) looking way is NSString *string = @"abcde\nfghijk\nlmnopq\nrstu"; NSInteger length = [[string componentsSeparatedByCharactersInSet: [NSCharacterSet newlineCharacterSet

How to stop enumerateObjectsUsingBlock Swift

扶醉桌前 提交于 2019-11-28 21:09:42
How do I stop a block enumeration? myArray.enumerateObjectsUsingBlock( { object, index, stop in //how do I stop the enumeration in here?? }) I know in obj-c you do this: [myArray enumerateObjectsUsingBlock:^(id *myObject, NSUInteger idx, BOOL *stop) { *stop = YES; }]; Christian Dietrich In Swift 1: stop.withUnsafePointer { p in p.memory = true } In Swift 2: stop.memory = true In Swift 3 - 4: stop.pointee = true This has unfortunately changed every major version of Swift. Here's a breakdown: Swift 1 stop.withUnsafePointer { p in p.memory = true } Swift 2 stop.memory = true Swift 3 stop.pointee

Elixir - Looping through and adding to map

爱⌒轻易说出口 提交于 2019-11-28 17:28:04
I'm rebuilding something in Elixir from some code I built in C#. It was pretty hacked together, but works perfectly (although not on Linux, hence rebuild). Essentially what it did was check some RSS feeds and see if there was any new content. This is the code: Map historic (URL as key, post title as value). List<string> blogfeeds while true for each blog in blogfeeds List<RssPost> posts = getposts(blog) for each post in posts if post.url is not in historic dothing(post) historic.add(post) I am wondering how I can do Enumeration effectively in Elixir. Also, it seems that my very process of

Objective C — What is the fastest and most efficient way to enumerate an array?

旧时模样 提交于 2019-11-28 17:10:31
问题 Edit I read through some articles on blocks and fast enumeration and GCD and the like. @Bbum, who's written many articles on the subject of GCD and blocks, says that the block enumeration methods are always as fast or faster than the fast enumeration equivalents. You can read his reasoning here. While this has been a fascinating, intellectual conversation, I agree with those who said that it really depends on the task at hand. I have some tasks to accomplish and I need them done fast, cheap,