elem

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an XML file that I would like to map some attributes of in with a script. For example: might have attributes scaled by a factor of two: This page has a suggestion for adding attributes but doesn't detail a way to map a current attribute with a function (this way would make that very hard): http://www.scalaclass.com/book/export/html/1 What I've come up with is to manually create the XML (non-scala) linked-list... something like: // a typical match case for running thru XML elements: case Elem(prefix, e, attributes, scope, children @ _*

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Does anyone know how to test for the first member and last member in a gsp loop? Here's my jsp code: <c:forEach items='${aSet}' var='elem' varStatus="loop"> <c:if test='${loop.first}'> <p>Display something</p> </c:if> </c:forEach> I know you can test for status in a g:each statement but that's just an integer. Is there anything to access the first and last element? If not, is there another way to do what I'm doing? Any help appreciated. 回答1: I'm not sure what the problem with <g:each status> is. Yes, it's "just" an integer, but isn't that

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a p:dataTable pretty similar to the showcase . Unfortunatly, the showcase uses randomly generated values for the p:summaryRow . Refering to the showcase, imagine the car had a price attribute. How would I sum up the price for the cars grouped by the specified column for displaying it in the summary row? 回答1: I have same problem with you and found correct usage from primefaces blog SummaryRow from primefaces forum this is some example show correct calculation for sum price, count... Listener gets the group property which is the sortBy

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am attempting to create a simple dropdown that is triggered by a hover event. To save on writing code I want to take advantage of the $(this) selector but I keep running into a problem when I try to target $(this) next 'a' element. Does anyone know the correct way to code this while still using the $(this) selector? In the below code if I change $(this).next('a') to $('.base a') the code works fine but then I would have to write the same block of jQuery code for each time I want to use this feature using a different class selector each

//finder.h #ifndef FINDER_H #define FINDER_H #include <QStack> struct Position { int x ; int y ; Position ( int x = 0 , int y = 0 ) { this -> x = x ; this -> y = y ; } } ; struct StackElem { Position pos ; int direction ; } ; class Finder { public : Finder (); bool findPath ( int maze [][ 10 ], Position startpoint , Position endpoint ); void nextPos ( Position * p_pos , StackElem pm ); bool pass ( int maze [][ 10 ] , Position curpos ); void footPrint ( int maze [][ 10 ] , Position curpos ); void setElem ( Position pos , int direction , StackElem * p_e ); void markprint ( int maze [][ 10 ] ,

稀疏矩阵三元顺序组模板 typedef struct { int i,j; int elem; }Triple;//一个点的三元组。 typedef struct { Triple Data[MAXN]; int m,n,len; //m,n记录的是这个矩阵的行与列；但本题没用到整个矩阵的行与列，因为是稀疏矩阵 }TripleMatrix; //一个矩阵的三元组 稀疏矩阵三元顺序组的创建 void CreateTriple(TripleMatrix *p,int n) //因为有->,所以用指针传方便 { int cnt; for(cnt=0;cnt<n;cnt++) //i从0开始，是因为addtriple这个函数while跳出的小于号决定的 { scanf("%d%d%d",&p->Data[cnt].i,&p->Data[cnt].j,&p->Data[cnt].elem); //因为不是链表存储结构，所以不用malloc构建空间 } p->len=cnt; //for里不要再习惯i了 } 稀疏矩阵三元组顺序的相加 void AddTriple(TripleMatrix *a,TripleMatrix *b,TripleMatrix *c) { int k,l; int temp; c->len=0; k=0,l=0; while(k<(a->len)&&l<(b->len)

Map：一键值对存在的一种数据结构，创建Map的时候默认长度是不可变的 package com . lyz import scala . collection .{ SortedMap , mutable } import scala . collection . mutable . Map /** * 类的注释 * * @Package com.lyz * @ClassName MapAndTuple * @Description ${TODO} * @Author liyuzhi * @Date 2018-06-08 19:08 */ object MapAndTuple { def main ( args : Array [ String ]): Unit = { //immutableMap //mutableMap hashMap } //可变的Map private def hashMap = { /** * 初始化HashMap */ val hashMap = new mutable . HashMap [ String , Int ]() hashMap . put ( "zhangsan" , 21 ) hashMap . put ( "lisi" , 22 ) hashMap . put ( "wangwu" , 23 ) hashMap . put (

幂集的定义： 所谓幂集（Power Set）， 就是原集合中所有的子集（包括全集和空集）构成的集族。 例如S={1，2} 2 S ( 幂集的一种表示方法 )={ {}，{1}，{2}，{1，2} }，|2 S |=2 |S| ,|…|表示…的基数，即集合元素的数目 代码思想： 记 power（S）：S的幂集 递归表达式 power(S）=power（S/{ elem }）+ (power(S/{ elem }) + { elem }) Note: 1.elem指S集中任一元素，是从S集中剔除来的，为了方便，下面我都是剔除的最后一个元素 2.第一个+表示：前后两个幂集求并集 第二个+表示：迭代S/{ elem }的幂集，将elem一一加入 代码（python）： def powerSet ( l ) : if len ( l ) == 1 : return [ [ ] , l ] l1 = l [ : len ( l ) - 1 ] elem = l [ len ( l ) - 1 ] temp = powerSet ( l1 ) temp1 = [ ] for i in temp : temp1 . append ( i + [ elem ] ) return temp + temp1 l = [ 1 , 2 , 3 , 4 ] print ( powerSet ( l ) )

伪数组转为真数组 对DOM元素进行map、forEach操作时候需要进行遍历，伪数组遍历会报错：'elem.map is not a function',为了避免这个问题，需要进行转换。 (1) ES5 转为真数组 Array.prototype.slice.call(元素对象) let elem1 = Array.prototype.slice.call(elem) (2) ES6 转为真数组 Array.from（元素对象） let elem2 = Array.from(elem) (3) 例子 <ul> <li class="a" ></li> <li class="a" ></li> <li class="a" ></li> <li class="a" ></li> <li class="a" ></li> </ul> <script> /* 获取li元素*/ let elem = document.getElementsByClassName('a') /* 这样写是错误的,因为是伪数组*/ elem.map((item,index,elem) => { console.log(item +'---'+index + '----'+elem) /*elem.map is not a function*/ }) // （1）es6 转为真数组 let elem1 =

LeetCode.80 删除排序数组中的重复项 算法：原地挪动一般都是双指针 如果是当前判断元素elem，那么当前元素个数++，如果满足不超过两次的条件，那么将这个数保存，然后左指针+1 如果超过三个，那么只是index+1 如果当前元素已经更改，那么重新选择当前元素，index不变 public int removeDuplicates ( int [ ] nums ) { if ( nums . length <= 2 ) { return nums . length ; } int count = 0 , elem = nums [ 0 ] ; int lastValidIndex = 0 , index = 0 ; while ( index < nums . length ) { if ( nums [ index ] == elem ) { count ++ ; if ( count <= 2 ) { nums [ lastValidIndex ++ ] = nums [ index ] ; } index ++ ; } else { elem = nums [ index ] ; count = 0 ; } } return lastValidIndex ; } ``` 来源：51CTO 作者： hustfc 链接：https://blog.csdn.net