each

Excel VBA For Each Worksheet Loop

点点圈 提交于 2019-11-27 21:19:23
I am working on code to basically go through each sheet in my Workbook, and then update column widths. Below is the code I wrote; I don't receive any errors, but it also doesn't actually do anything. Any help is greatly appreciated! Option Explicit Dim ws As Worksheet, a As Range Sub forEachWs() For Each ws In ActiveWorkbook.Worksheets Call resizingColumns Next End Sub Sub resizingColumns() Range("A:A").ColumnWidth = 20.14 Range("B:B").ColumnWidth = 9.71 Range("C:C").ColumnWidth = 35.86 Range("D:D").ColumnWidth = 30.57 Range("E:E").ColumnWidth = 23.57 Range("F:F").ColumnWidth = 21.43 Range("G

Nested jQuery.each() - continue/break

纵饮孤独 提交于 2019-11-27 19:37:01
Consider the following code: var sentences = [ 'Lorem ipsum dolor sit amet, consectetur adipiscing elit.', 'Vivamus aliquet nisl quis velit ornare tempor.', 'Cras sit amet neque ante, eu ultrices est.', 'Integer id lectus id nunc venenatis gravida nec eget dolor.', 'Suspendisse imperdiet turpis ut justo ultricies a aliquet tortor ultrices.' ]; var words = ['ipsum', 'amet', 'elit']; $(sentences).each(function() { var s = this; alert(s); $(words).each(function(i) { if (s.indexOf(this) > -1) { alert('found ' + this); return false; } }); }); The interesting part is the nested jQuery.each() loops.

Should I use jQuery.each()?

随声附和 提交于 2019-11-27 19:18:41
I'm doing very frequent iterations over arrays of objects and have been using jQuery.each(). However, I'm having speed and memory issues and one of the most called methods according to my profiler is jQuery.each(). What's the word on the street about its performance? Should I switch to a simple for loop? Of course I'm fixing the many issues in my own code too. The source code for jQuery's each is as follows (Thank you John Resig and MIT License): each: function( object, callback, args ) { var name, i = 0, length = object.length; if ( args ) { if ( length === undefined ) { for ( name in object

Por Costel and the Match Gym - 100923H(经典种类并查集)

半世苍凉 提交于 2019-11-27 19:01:10
Por Costel and the Match Gym - 100923H 题目链接: https://vjudge.net/problem/Gym-100923H 题目: Oberyn Martell and Gregor Clegane are dueling in a trial by combat. The fight is extremely important, as the life of Tyrion Lannister is on the line. Oberyn and Gregor are measuring their skill in combat the only way the two best fighters in Westeros can, a match of Starcraft. The one who supervises the match in none other than Por Costel the pig. Oberyn and Gregor are both playing the Terrans, and they confront each other in the middle of the map, each with an army of Marines. Unfortunately, pigs cannot

jQuery loop through data() object

不羁的心 提交于 2019-11-27 18:33:25
Is it possible to loop through a data() object? Suppose this is my code: $('#mydiv').data('bar','lorem'); $('#mydiv').data('foo','ipsum'); $('#mydiv').data('cam','dolores'); How do I loop through this? Can each() be used for this? jQuery stores all the data information in the jQuery.cache internal variable. It is possible to get all the data associated with a particular object with this simple but helpful plugin: jQuery.fn.allData = function() { var intID = jQuery.data(this.get(0)); return(jQuery.cache[intID]); }; With this in place, you can do this: $('#myelement').data('test1','yay1') .data(

jQuery .each() with input elements

安稳与你 提交于 2019-11-27 15:40:49
问题 //save tablet jQuery("#savetablet"+jTablets[i].idtablets).on('click', function() { alert("alertsepy2..."); console.log(jTablets[i].idtablets); jQuery("#tablet"+jTablets[i].idtablets+" .detailsrow").each(function( index ) { $(this).each(function( index2 ) { console.log($(this).html()); }); }); }); <div class="column0"><input type="text" value="-D"></div> <div class="column1"><input type="text" value="D"></div> <div class="column2"><input type="text" value="D"></div> <div class="column3"><input

AtCoder Beginner Contest 136 D - Gathering Children

会有一股神秘感。 提交于 2019-11-27 15:36:42
我最近做的都是什么shabi题,这道题顶多noip(最近听说ccf给鸽了)Day 1 T2 ,或者noip提高组都不到,像我这么菜只能做普及-的题; D - Gathering Children Time Limit: 2 sec / Memory Limit: 1024 MB Score : 400 points Problem Statement Given is a string S consisting of L and R . Let N be the length of S . There are N squares arranged from left to right, and the i -th character of S from the left is written on the i -th square from the left. The character written on the leftmost square is always R , and the character written on the rightmost square is always L . Initially, one child is standing on each square. Each child will perform the move below 10

How to replace element's attr href with each ? // strip url

帅比萌擦擦* 提交于 2019-11-27 15:12:13
im trying to change href with each method, here is demo, inspect a, you'll see there is no change html: <a href="#/news">News</a> <a href="#/news/detail">Detail</a> <a href="#/sport">Sport</a> <a href="#/sport/football">Football</a>​​​​​​​​​​​​ jQuery: $('a').each(function() { $(this).attr('href').replace('#/',''); //tried to erase #/ from all hrefs });​ The code you posted will get the value as a string then properly replace the values but it immediately discards the result. You need to pass in the replaced value to attr . Try the following $('a').each(function() { var value = $(this).attr(

jQuery: How to use each starting at an index other than 0

丶灬走出姿态 提交于 2019-11-27 14:42:42
I have a collection of elements that I want to loop over using each, but I am looping over them inside an outer for loop. When I find what I want in the each, I return false to break out. The next time the outer loop runs, I want to start in the each at the element after the one I returned at. A generic code example: var nextIndex = 0; for (var j=1; j <= someCount; j++) { // do outside loop stuff $('#someElemID').find('.someClass').each(function(index) { if (/*this is right one*/) { // do something // next index should get passed to each function next loop... somehow? nextIndex = index + 1;

jQuery: Finding duplicate ID's and removing all but the first

馋奶兔 提交于 2019-11-27 12:27:33
问题 $('[id]').each(function () { var ids = $('[id="' + this.id + '"]'); // remove duplicate IDs if (ids.length > 1 && ids[0] == this) $('#' + this.id).remove(); }); The above will remove the first duplicate ID, however I want to remove the last. I've tried $('#'+ this.id + ':last') but to no avail. Fiddle In the fiddle the input with the value 'sample' should be kept when the append action takes place. 回答1: Use jquery filter :gt(0) to exclude first element. $('[id]').each(function () { $('[id="'