each

jQuery get the input value in an .each loop

自闭症网瘾萝莉.ら 提交于 2019-12-19 13:48:27
问题 I am trying to get the input value in an each loop of a checkbox, i cant figure out how to get this to work, the value keeps outputting as the first checkbox value. $('.custemb, input[name=cb], input[class=multadd]').live("click", function() { $('input[class=multadd]:checked').each(function(index) { val = index + 2; valu = $('input[class=multadd]:checked').val(); multiz = multiz + '&aid' + val + '=' + valu; }); }); the problem is the output of the variable valu is the first checkbox of the

Is perl's each function worth using?

半城伤御伤魂 提交于 2019-12-19 13:11:37
问题 From perldoc -f each we read: There is a single iterator for each hash, shared by all each , keys , and values function calls in the program; it can be reset by reading all the elements from the hash, or by evaluating keys HASH or values HASH . The iterator is not reset when you leave the scope containing the each() , and this can lead to bugs: my %h = map { $_, 1 } qw(1 2 3); while (my $k = each %h) { print "1: $k\n"; last } while (my $k = each %h) { print "2: $k\n" } Output: 1: 1 2: 3 2: 2

Is perl's each function worth using?

a 夏天 提交于 2019-12-19 13:11:09
问题 From perldoc -f each we read: There is a single iterator for each hash, shared by all each , keys , and values function calls in the program; it can be reset by reading all the elements from the hash, or by evaluating keys HASH or values HASH . The iterator is not reset when you leave the scope containing the each() , and this can lead to bugs: my %h = map { $_, 1 } qw(1 2 3); while (my $k = each %h) { print "1: $k\n"; last } while (my $k = each %h) { print "2: $k\n" } Output: 1: 1 2: 3 2: 2

Is perl's each function worth using?

雨燕双飞 提交于 2019-12-19 13:10:08
问题 From perldoc -f each we read: There is a single iterator for each hash, shared by all each , keys , and values function calls in the program; it can be reset by reading all the elements from the hash, or by evaluating keys HASH or values HASH . The iterator is not reset when you leave the scope containing the each() , and this can lead to bugs: my %h = map { $_, 1 } qw(1 2 3); while (my $k = each %h) { print "1: $k\n"; last } while (my $k = each %h) { print "2: $k\n" } Output: 1: 1 2: 3 2: 2

Looping with .each with delay in Jquery

心已入冬 提交于 2019-12-19 11:38:14
问题 I am not good at jQuery so I am not sure if my assumptions are corrent. I am using the isotope plugin, with which I want to insert elements one by one (and not everything at once) with a slight delay so it will also look like it (for the human eye) to insert an item with isotope I use $('#container').isotope( 'insert', $item); so in order to insert one-by-one I am doing $("#items_are_here").find('.item').each(function( index ) { setTimeout(function() { $('#container').isotope( 'insert', $

Looping with .each with delay in Jquery

余生颓废 提交于 2019-12-19 11:38:13
问题 I am not good at jQuery so I am not sure if my assumptions are corrent. I am using the isotope plugin, with which I want to insert elements one by one (and not everything at once) with a slight delay so it will also look like it (for the human eye) to insert an item with isotope I use $('#container').isotope( 'insert', $item); so in order to insert one-by-one I am doing $("#items_are_here").find('.item').each(function( index ) { setTimeout(function() { $('#container').isotope( 'insert', $

20190621-N皇后

こ雲淡風輕ζ 提交于 2019-12-19 10:24:27
N皇后 难度分类 困难 题目描述 n皇后问题研究的是如何将 n个皇后放置在 n×n 的棋盘上,并且使皇后彼此之间不能相互攻击。 上图为 8 皇后问题的一种解法。 给定一个整数 n,返回所有不同的 n 皇后问题的解决方案。 每一种解法包含一个明确的 n 皇后问题的棋子放置方案,该方案中 'Q' 和 '.' 分别代表了皇后和空位。 示例: 输入: 4 输出: [ [".Q..", // 解法 1 "...Q", "Q...", "..Q."], ["..Q.", // 解法 2 "Q...", "...Q", ".Q.."] ] 算法图示 Step1:遍历第一行所有的列,先在第一行的第一个位置放置第一个皇后,第一个皇后放置后其对应的位置以及冲突位置如下: Step2:遍历第二行所有的列,发现第一第二列冲突,第三列个可以放第二个皇后,放置后如图,放置后对应的位置以及冲突位置如下: Step3: 遍历第三行所有的列,发现没有位置放置第三个皇后,所有列均冲突,所有此种情况下第三行无法放置第三个皇后(不可能得到最终解)。因此回到第二行,继续遍历第二行的第四列查看是否可以放置第二个皇后,放置后对应位置以及冲突位置如下: Step4: 在调整了第二个皇后的位置后继续遍历第三行所有的列,发现第二列可以放置第三个皇后,放置后对应位置以及冲突位置如下:Step3: 遍历第三行所有的列

JQuery跳出each循环的方法

巧了我就是萌 提交于 2019-12-19 09:42:07
一、jquery each循环,要实现break和continue的功能: break----用return false; continue --用return ture; 二、jquery怎么跳出当前的each循环 有些朋友可能会以为在jquery跳出循环可以直接使用continue和break了,但是使用之后没有效果,因为在jquery中没有这两条命令。 后来上网查了下,得到了结果: return false;——跳出所有循环;相当于 javascript 中的 break 效果。 return true;——跳出当前循环,进入下一个循环;相当于 javascript 中的 continue 效果 例 复制代码 代码如下: $(function (){ $("input[type='text']").each(function (i){ var _val=$(this).val(); alert(_val); if(_val=='2'){ return false; //跳出循环 } }) }); 三、Jquery each方法跳出循环并获得返回值的方法 return false:将停止循环 (就像在普通的循环中使用 'break')。 return true:跳至下一个循环(就像在普通的循环中使用'continue')。 复制代码 代码如下: function test(){

wait for each jQuery

喜你入骨 提交于 2019-12-19 06:25:00
问题 I'm trying to make a div fade in/out that's within an each statement. The problem is that next item is called before the fade in/out is complete. <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js" type="text/javascript"></script> <div id='one'>one</div> <div id='two'>two</div> <div id='three'>three</div> <script> $.each([ "one", "two", "three"], function() { console.log( 'start - ' + this ); animate( this ); console.log( 'end - ' + this ); }); function animate( id )

How to write a loop in jQuery which waits for each function to complete before continuing the loop

余生长醉 提交于 2019-12-19 05:18:08
问题 Please forgive me if this is an obvious one. I have an unknown amount of elements on a page, which I need to loop through one at a time and do stuff to. However, I need the loop to pause until the functions used on the elements have completed, and then continue on to the next iteration. I tried doing this in a $.each loop, but it fired off the commands far to quickly and finished without waiting for them to complete. Any ideas? $('elem').each(function(){ $(this).fadeIn().wait(5000).fadeOut();