each

Using jQuery each to grab image height

由 半世苍凉 提交于 2019-12-22 11:33:47
问题 I have a bunch of images on a page. I'm trying to use jQuery to grab the height of each image and display it after the image. So here is my code: $(document).ready(function() { $(".thumb").each(function() { imageWidth = $(".thumb img").attr("width"); $(this).after(imageWidth); }); }); <div class="thumb"><img src="" border="0" class="thumb_img"></div> <div class="thumb"><img src="" border="0" class="thumb_img"></div> <div class="thumb"><img src="" border="0" class="thumb_img"></div> [...] My

$.each animation running separately

由 穿精又带淫゛_ 提交于 2019-12-22 10:59:38
问题 I'm trying to run each animation function one after the other instead of all at once. This is what I've got so far: $(document).ready(function(){ var bars = $('.bar'); bars.each(function(){ var widthpercent = $(this).attr("data-percent"); $(this).fadeIn(); $(this).animate({width:widthpercent},500); }); }); I've tried using .delay() and setTimeout() in various combinations to no avail. Could anyone point me in the right direction? Thank you! 回答1: It sounds to me like you're looking for animate

distributing json array output to each <li>

由 亡梦爱人 提交于 2019-12-22 10:34:47
问题 I have a JSON output and i want to show each item inside each <li> . The JSON output looks like this: var data = [ { "MachineID":"171914", "Cost":"13,642.41", "Currency":"PHP" }, { "MachineID":"172233", "Cost":"1,367.73", "Currency":"PHP" }, { "MachineID":"41116", "Cost":"2,608.20", "Currency":"PHP" }, { "MachineID":"178077", "Cost":"1,517.04", "Currency":"PHP"}, { "MachineID":"176430", "Cost":"20,876.72", "Currency":"PHP" } ] And my code is this: $.each(data, function(i, obj) { $.each(obj,

Dynatree Expand Parents of Selected Nodes

由 徘徊边缘 提交于 2019-12-22 08:23:55
问题 I have Dynatree running well on my page. I am using an initAjax to get the structure. When I generate my json I include "select": true where appropriate to select check-boxes. Most (all) of the check-boxes are at a depth of three levels down from the root. I would like to expand the parents of the selected nodes so the user can see the selected check-boxes when the page loads. I think I need to do something on the onPostInit function with getSelectedNodes, but I can not nail down the code?? I

jQuery each - combining (this) with class specification

由 为君一笑 提交于 2019-12-22 07:55:12
问题 I'm trying to cycle through some table rows. The simplified rows are as follows: <table> <tr id="ucf48"> <td class="ucf_text"> <input name="ucf_t48" value="Ann becomes very involved in the text she is reading." type="text"> </td> </tr> <tr id="ucf351"> <td class="ucf_text"> <input name="ucf_t351" value="Ann is a fast and confident reader." type="text"> </td> </tr> </table> I'm using this code to cycle: $('#ucf tr').each(function(i,obj){ var cn=$(this).attr('id').substr(3); var t=$(this +'.ucf

javascript Array对象

由 て烟熏妆下的殇ゞ 提交于 2019-12-22 05:29:35
数组是一段线性分配的内存，它通过整数去计算偏移并访问其中的元素。数组是很快的数据结构，但不幸的是，Javascript并没有像这种数组一样的数据结构。Javascript的数组实质是对象，它把数组的下标转换成字符串，用其作为属性，因此它明显比真正的数组慢，但它可以更方便地使用。 改变自身pop,push,reverse,shift,sort,splice,unshift, 不改变自身concat,join,slice,indexOf,lastIndexOf(后两个为1.6),1.6新增的迭代器：map,filter,forEach,every,some,1.8新增reduce,reduceRight Array 对象的方法 FF: Firefox, N: Netscape, IE: Internet Explorer 方法 描述 FF N IE concat() 方法concat()将创建并返回一个新数组，这个数组是将所有参数都添加到array中生成的。它并不修改array。如果要进行concat()操作的参数是一个数组，那么添加的是数组中的元素，而不是数组。 var a = [1,2,3]; a.concat(4, 5); // Returns [1,2,3,4,5] a.concat([4,5]); // Returns [1,2,3,4,5] a.concat([4,5],

What's the purpose of using an Element parameter in your callback when using the jquery .each() function?

由 北战南征 提交于 2019-12-21 21:00:02
问题 Looking at the docs for the .each() function in jquery shows the following method signature: .each( function(index, Element) ) http://api.jquery.com/each/ I can understand needing to pass in an index so that it is available for use within the callback but why would you explicitly include the Element parameter if you can just reference the current element by the this keyword? Is it there just so that you can specify an instance name of your choice? I mean, if you still have to wrap a named

ACM 第十六天

由 浪子不回头ぞ 提交于 2019-12-21 09:34:57
计算几何 练习题: F - Beauty Contest POJ - 2187 Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farmers and their cows. For simplicity, the world will be represented as a two-dimensional plane, where each farm is located at a pair of integer coordinates (x,y), each having a value in the range -10,000 ... 10,000. No two farms share the same pair of coordinates. Even though Bessie travels directly in a straight

jquery for each all elements having similar id

由 雨燕双飞 提交于 2019-12-21 07:34:24
问题 I have many elements accross page - ID1, ID2 ID3 ... I want to manipulate all the elements. Is there any simpler way to do this. $("#ID").each(function(){ ... }); 回答1: You can use ^ selector. Example $('div[id^="ID"]') ^= select DOM whose ID attribute starts with ID (i.e ID1, IDID,IDS,ID2 etc) 回答2: Give them a class, so you can select them by the class? $('.class').each(function(i,e) { // }); 回答3: If the ID portion isn't necessarily at the beginning you could do: $( "[tagName][id*='ID']" )

for loop in thymeleaf

由 雨燕双飞 提交于 2019-12-21 07:09:23
问题 How can I do the following (java): for(int i = 0; i < 81 ; i+=20){ //Should loop through 5 times! } in Thymeleaf? I've tried this: <option th:each="i : ${#numbers.sequence( 1, 81/20)}"> <p th:text="${ i }"></p> <!-- THIS loops 4 times, instead of 5 --> </option> The problem is that it is not as accurate as the java piece of code. How to do this? 回答1: I am assuming this is due to the numbers you are using. For your java code, int i = 0; i < 81 ; i+=20 will return i=0, i=20, i=40, i=60 and i=80
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