duplicates

问题 I have a character vector, including some elements that are duplicates e.g. v <- c("d09", "d11", "d13", "d01", "d02", "d10", "d13") And another vector that includes single counts of those characters e.g. x <- c("d10", "d11", "d13") I want to remove only the first occurrence of each element in x from the 2nd vector v . In this example, d13 occurs in x and twice in v , but only the first match is removed from v and the duplicate is kept. Thus, I want to end up with: "d09", "d01", "d02", "d13" I

问题 I have two tables like the following hotels ------ hotelID hotelName Second table operators --------- opID opName opServices opHotelID a short explanation: In the first table I have a lot of hotels which have an increment id which is unique. The second table contains all the operators offering this hotel with additional services. The opID here is unique too but the opHotelID exists multiple times, because there can be many operators offering the hotel. Now, what I want to get is the following

问题 I am trying to create folders using google drive API using the scope 'https://www.googleapis.com/auth/drive.file' Surprisingly, the api allows me to upload multiple files with the exact same title into the same folder. I can even see these duplicate files if I browse over to my google drive in my web browser. Is there any way I can have the API prevent duplicates in filenames? I could check for a file's existence before uploading another with the same name, but that seems to be a strange way

问题 I have a stored procedure that is run every night which is supposed to send the results of a query to several recipients. However on most days it ends up sending a duplicate email a minute later. The code I am using is as follows (all emails and database refs have been changed): EXEC msdb.dbo.sp_send_dbmail @recipients = 'email1@email.com', @copy_recipients = 'email2@email.com;email3@email.com;email4@email.com', @subject = 'Example Email', @profile_name = 'ExampleProfile', @query = 'SELECT

问题 This comment suggests that there is a O(n) alternative to my O(n log n) solution to this problem: Given string str("helloWorld") the expected output is: l = 3 o = 2 My solution was to do this: sort(begin(str), end(str)); for(auto start = adjacent_find(cbegin(str), cend(str)), finish = upper_bound(start, cend(str), *start); start != cend(str); start = adjacent_find(finish, cend(str)), finish = upper_bound(start, cend(str), *start)) { cout << *start << " = " << distance(start, finish) << endl;

问题 ld: duplicate symbol _velocityX in \ /Users/Student/Library/Developer/Xcode/DerivedData/finalproject-ffzevekmatxvhrgisgeleoijyllr/Build/Intermediates/finalproject.build/Debug-iphonesimulator/finalproject.build/Objects-normal/i386/Level2ViewController.o \ and \ /Users/Student/Library/Developer/Xcode/DerivedData/finalproject-ffzevekmatxvhrgisgeleoijyllr/Build/Intermediates/finalproject.build/Debug-iphonesimulator/finalproject.build/Objects-normal/i386/Level1ViewController.o \ for architecture

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . If I have an array set up as: test[10] = {1,2,1,3,4,5,6,7,8,3,2} I want to return the number 3 since there is a duplicate 1, a duplicate 2 and a duplicate 3. How can I achieve this? Efficiency doesn't matter. 回答1

问题 So I am working in Ruby, and say I have 6 rows in a table of two columns that are exactly identical. In my case, my table "campaign_items" has two columns "campaign_name" and "item." I would like to delete only one row out of the 6 duplicates using a single query. I started with this: db.exec("DELETE FROM products WHERE campaign_name = '#{camp_name}' AND product_type = 'fleecejacket' AND size = '#{size_array[index]}'") Which of course deleted all items of that condition. So I found in another

问题 I am new to image processing. My SO question is... I take an image using a camera, then I use this image and check it against a list container. If the list container contains an image that looks like this image then do an operation, otherwise don't. Example... I have one image "img_one" My list contains "image_one,image_two,image_three" Show list has image_one (i.e. it looks like this image) So how do I check this image against the items in the list container and show which image looks like

问题 Which one is more reliable and has better performance? Setting MySQL unique key and using INSERT IGNORE or first checking if data exists on database and act according to the result? If the answer is the second one, is there any way to make a single SQL query instead of two? UPDATE: I ask because my colleagues in the company I work believe that deal with such issues should be done in application part which is more reliable according to them. 回答1: You application won't catch duplicates. Two