duplicates

问题 I have a list of Shapely polygons. From that list I want to extract only unique polygons removing the duplicates. How to do it in a faster way? (My list contains thousands of polygons) from shapely.geometry import Polygon lists = [[(1,1),(2,2),(3,3),(4,4)], [(6,6),(7,7),(8,8),(9,9)], [(1,1),(2,2),(3,3),(4,4)]] polys = [Polygon(item) for item in lists] ##This is given condition for poly in polys: test = [p.intersects(poly) for p in polys] ##Return true or false print test [True, False, True]

问题 I have a question regarding removing duplicates after sorting within a tuple in R. Let's say I have a dataframe of values df<-cbind(c(1,2,7,8,5,1),c(5,6,3,4,1,8),c(1.2,1,-.5,5,1.2,1)) a and b a=df[,1] b=df[,2] temp<-cbind(a,b) What I am doing is uniquing based upon a sorted tuple. For example, I want to keep a=1,2,7,8,1 and b=5,6,3,4,8 with the entry a[5] and b[5] removed. This is basically for determining interactions between two objects. 1 vs 5, 2 vs 6 etc. but 5 vs 1 is the same as 1 vs 5,

问题 I know there are many answers about returning unique values in an array after removing duplicates, but isn't every element in an array unique after you remove the duplicates? I want to only return values that are unique prior to removing any duplicates. If the element repeats in the original array, I don't want it in my final array. So this array... [0, 1, 1, 2, 3, 3, 3, 4] should return only: [0, 2, 4] Another way to phrase this would be to remove all duplicates as well as all unique values

问题 Given the following data frame: import pandas as pd d=pd.DataFrame({'label':[1,2,2,2,3,4,4], 'values':[3,5,7,2,5,8,3]}) d label values 0 1 3 1 2 5 2 2 7 3 2 2 4 3 5 5 4 8 6 4 3 I know how to count the unique values like this: d['dup']=d.groupby('label')['label'].transform('count') Which results in: label values dup 0 1 3 1 1 2 5 3 2 2 7 3 3 2 2 3 4 3 5 1 5 4 8 2 6 4 3 2 But what I would like is a column to have the following values: 1 if there is 1 unique row per the label column, 2 if there

问题 I have a vector of vectors: vector< vector<int> > BigVec; It contains an arbitrary number of vectors, each of an arbitrary size. I want to delete not duplicate elements of each vector, but any vectors that are the exact same as another. I don't need to preserve the order of the vectors so I can sort etc.. It should be a really simple problem to solve but I'm new to this, my (not-working) best effort: for (int i = 0; i < BigVec.size(); i++) { for (int j = 1; j < BigVec.size() ; j++ ) { if

问题 I thought this was going to be Very simple: =COUNTIF(Foo[Bar],$A1)>0 applying this to the entire column I thought would highlight any cell that is found in the Column Bar of table Foo. But excel is telling me my formula contains an error, even though when I paste it into a cell it does give me a correct value of True/False. I thought maybe for some reason I needed to complicate it for excel so i tried: =COUNTIF(Foo[Bar],$A1) + CountIf(A1:A10000, $A1>1 Not sure why i tried it but I figured why

问题 I have a registration form. Here I'm able to check duplicate email by my custom is unique call back function (Don't try to use is_unique). But it doesn't returns anything. Here is my code. Controller - public function add_member () { $this->load->library('form_validation'); $post_email = $this->input->post('email_id'); $this->form_validation->set_rules('email_id', 'Email ID/ Username', 'required|trim|xss_clean|valid_email|callback_check_duplicate_email[' . $post_email . ']'); $this->form

问题 I want to duplicate a very large table, but I do not want to copy it row by row. Is there a way to duplicate it? For example, you can TRUNCATE w/o deleting row/row, so i was wondering if there is something similar for copying entire tables UPDATE: row by row insert is very painful (because of 120M rows). Anyway to avoid that? 回答1: MySQL no longer has a reliable "copy table" functionality - many reasons for this related to how data is stored. However, the below does row-by-row insertion but is

问题 I am getting build failed, I tried so many things but I couldn't figure out how to solve it duplicate symbol _GSDK_GTMNSDataZLibExportToSuppressLibToolWarning in: /Users/Macpro/Documents/evoteam/ClassifiedTemplate/../Pods/GoogleUtilities/Libraries/libGTM_NSData+zlib_external.a(GTMNSData+zlib.o) /Users/Macpro/Documents/evoteam/Pods/GoogleUtilities/Libraries/libGTM_NSData+zlib_external.a(GTMNSData+zlib.o) ld: 1 duplicate symbol for architecture x86_64 thank you for any help. 回答1: Add it to your

问题 I am using Data factory to create our staging area, the problem is whenever source data changes, we add a new row to staging tables. For instance, assume we have the following data: ID Fields created edited 100 ---------- '2017-07-01' '2017-07-05' this will be stored in our staging tables like this: ID Fields created edited 100 ---------- '2017-07-01' null 100 ---------- '2017-07-01' '2017-07-05' Selecting the most recent row is expensive and We don't want that. How do you think we can avoid