duplicates

Find unique record for duplicate records over two columns

爱⌒轻易说出口 提交于 2019-12-13 20:28:29
问题 This is my database dataset : Table ID Name XXX-23305 Edward, Stue^Jenna XXX-23305 Edward, Stue^Jenna XXX-23306 Cole, Slaw^Bali XXX-23306 Cole, Slaw^Bali XXX-23306 Cole, Slaw^Bali XXX-23310 Zerg, War^Finja XXX-23310 Road^Sieglinde XXX-23319 Gras, Dr.Carl^Yolo XXX-23319 Gras, Dr.Carl^Yolo As you can see there might be multiple entries for the same ID and Name combination. However in case of ID XXX-23310 there are two different names available. Now what I want is displaying that exact dataset (

Removing duplicate rows from data.frame (with some details about column ordering)

我的梦境 提交于 2019-12-13 19:08:12
问题 I have a large data.frame with 12 columns and a lot of rows but lets simplify Id A1 A2 B1 B2 Result 1 55 23 62 12 1 2 23 55 12 62 1 * (dup of Id 1) 3 23 6 2 62 1 4 23 55 62 12 1 * (dup of Id 1) 5 21 62 55 23 0 * (dup of Id 1) 6 . . . . . . . . . Now the ordering of the A's (A1, A2) and B's (B1, B2) does not matter. If they both have the same values eg (55,23) and (62,12) they are duplicates, no matter the ordering of A and B variables. Furthermore if A_id_x = B_id_y and B_id_x = A_id_y and

prolog avoiding duplicate predicates

烈酒焚心 提交于 2019-12-13 17:52:33
问题 I was wondering whether it is possible to test whether a predicate already exists (with the same information) to then avoid the user being able to input the same information again. I have already managed to do it for a single predicate: :- dynamic(test/2). test(a,b). top(X,Y) :- (test(X,Y), write('Yes'),! ;write('No'),! ). This version works just fine, returning 'Yes' if the information already exists and 'No' if it doesn't. I was wondering whether it would be possible to do this for multiple

Finding duplicate INT in 2D array

送分小仙女□ 提交于 2019-12-13 17:46:36
问题 I'm stuck on this method. public class Duplicate{ public static boolean extra(int [][] grid) { for(int i = 0; i < grid.length; i++) for(int j = 0; j < grid[i].length-1; j++) if(grid[i][j] == grid[i][j+1]) { System.out.println(grid[i][j]); return true; } return false; } public static void main(String[] args){ int [][] grades = {{3,5,8,7}, {2,1,11,4}, {13,20,10,6}, {7,0,12,15} }; System.out.print(extra(grades)); } } I want to find if there are any duplicated ints in the array. return true if

Finding duplicates in MYSQL table where data is in multiple tables (multiple conditions needed)

落花浮王杯 提交于 2019-12-13 17:42:42
问题 My knowledge of MYSQL is rather basic, I would appreciate help with the following: subrecords schema id | record | element | title | name | type | value The above table stores data submitted via a web form. Each row is one field (i.e. "phone number", "email", "subject" etc..) where "title" is the label of the field and "value" is the content of the submitted field the "record" identifies each unique submitted form, it is a foreign key of the "records" table (records.id) clarified below (the

Resolve duplicate versions of dependency

半世苍凉 提交于 2019-12-13 17:40:41
问题 This has been very annoying. I have 2 projects, project A and B , B with dependency on A as a JAR file. So a 3rd library X in A has a dependency on another 3rd party library Y , the problem is maven resolves Y in project A to a version, but in project B to another version, like the following: commons-beanutils:jar:1.9.2 vs. commons-beanutils:jar:1.8.0 And the version below is specified in project A : net.sf.json-lib:json-lib:jar:jdk15:2.4 In the POM.xml of project B , there isn't really any

Identify duplicates of one value with different values in another column

倖福魔咒の 提交于 2019-12-13 17:32:14
问题 I have a dataframe of IDs and addresses. Normally, I would expect each recurring ID to have the same address in all observations, but some of my IDs have different addresses. I want to locate those observations that are duplicated on ID, but have at least 2 different addresses. Then, I want to randomize a new ID for one of them (an ID that didn't exist in the DF before). For example: ID Address 1 X 1 X 1 Y 2 Z 2 Z 3 A 3 B 4 C 4 D 4 E 5 F 5 F 5 F Will return: ID Address 1 X 1 X 6 Y 2 Z 2 Z 3 A

Remove duplicates based on order

China☆狼群 提交于 2019-12-13 15:34:29
问题 In R, I'm looking to remove any instances after the first two b and c after each a (please note the numbering). I've got the following: 1 a 2 b 3 c 4 a 5 b 6 c 7 a 8 b 9 c 10 b 11 c 12 a 13 b 14 c 15 c I'm looking to reduce it to: 1 a 2 b 3 c 4 a 5 b 6 c 7 a 8 b 9 c 12 a 13 b 14 c I'm trying to do this within a dplyr pipe if possible. Any ideas? 回答1: One possible solution: df = read.table(text="1 a 2 b 3 c 4 a 5 b 6 c 7 a 8 b 9 c 10 b 11 c 12 a 13 b 14 c 15 c",header=F) library(dplyr) df %>%

R sum consecutive duplicate rows and remove all but first

落爺英雄遲暮 提交于 2019-12-13 15:33:10
问题 I am stuck with a probably simple question - how to sum consecutive duplicate rows and remove all but first row. And, if there is a NA in between two duplicates (such as 2,na,2 ) , also sum them and remove all but the first entry. So far so good, here is my sample data ia<-c(1,1,2,NA,2,1,1,1,1,2,1,2) time<-c(4.5,2.4,3.6,1.5,1.2,4.9,6.4,4.4, 4.7, 7.3,2.3, 4.3) a<-as.data.frame(cbind(ia, time)) sample output a ia time 1 1 4.5 2 1 2.4 3 2 3.6 4 NA 1.5 5 2 1.2 6 1 4.9 7 1 6.4 8 1 4.4 9 1 4.7 10 2

What SQL returns duplicates in first column where values in 2nd column differ?

萝らか妹 提交于 2019-12-13 15:15:00
问题 Question is very similiar to this find duplicates but I'd like to find only those duplicate id with code different than 'ROME' and at least one name is 'ROME'. I want desired results because: 1. ID is duplicate. 2. At least one origin is 'ROME' 3. Remaining rows for that ID are NOT 'ROME' Table ID ORIGIN ----------- 1 ROME 1 ROME 2 ROME 2 LODI 3 ASTI 4 PISA 4 BARI Desired Results ID ORIGIN ----------- 2 ROME 2 LODI 回答1: SELECT id, origin FROM My_Table T1 WHERE EXISTS (SELECT * FROM My_Table