duplicates

问题 I want to create a set of random numbers without duplicates in Java. For example I have an array to store 10,000 random integers from 0 to 9999. Here is what I have so far: import java.util.Random; public class Sort{ public static void main(String[] args){ int[] nums = new int[10000]; Random randomGenerator = new Random(); for (int i = 0; i < nums.length; ++i){ nums[i] = randomGenerator.nextInt(10000); } } } But the above code creates duplicates. How can I make sure the random numbers do not

问题 I have this code which compares a number to a number(what i called item in my code) in the domain range to see if it is already there. If it its then print to the output file if it is not then only print it once. Question How to make sure that if the number isn't between the domain range then print only one time. ( I used true and false statements but this doesn't work because when it is false, it would print several duplicates- on the code below i am not sure how to implement so that it

问题 I'm using the Hapi framework for a Node.js application, and the Hapi framework comes with its own Cookie management tools, which i'm using for authentication. The framework then sets a cookie named session, with a json value encoded to base64. The domain is set to example.com (not .example.com) Now, the problem lies when i attempt to edit this cookie client-side, by doing the following document.cookie = 'session=' + btoa(JSON.stringify(_decoded)) + "; path=/; domain=example.com"; This

问题 Editing. Suppose I have the following series in pandas: >>>p 0 0.0 1 0.0 2 0.0 3 0.3 4 0.3 5 0.3 6 0.3 7 0.3 8 1.0 9 1.0 10 1.0 11 0.2 12 0.2 13 0.3 14 0.3 15 0.3 I need to identify each sequence of consecutive duplicates - its first and last index. Using the above example, I need to identify the first sequence of 0.3 (from index 3 to 7) independently from the last sequence of 0.3 (from index 13 to 15). Using Series.duplicated is insufficient because: *using keep='first' marks all first

问题 I have a plans list, or whatever it is, and I don't want any of them to be deleted. That's why when someone choose the "edit" option - I actually want to add a new plan with the same references, but just a new ID. Then, I don't care at all what changes will be made in it in the edit view (which is in fact the create view). I use the same view whether it create new or edit, but the only difference is that if the action get a plan - I understand it is not create new but edit and then I want to

问题 I have written the below macro to remove duplicate rows after checking all columns. I thought it was working correctly, based on the logic, but the output is not correct, and a few of the rows that should be showing up are being deleted. Can anyone help me with that? Before this macro is run, i have another macro to sort the data by a few columns to ensure that similar rows are grouped together, so maybe the macro can take that into account, and check only the row above it instead of checking

问题 So that: array = [[12,13,24],[24,22,11],[11,44,55]] would return: cleanedArray = [[12,13,24],[22,11],[44,55]] I'm surprised not to have found this answered here. 回答1: var array = [[12,13,24],[24,22,11],[11,44,55]]; var output = []; var found = {}; for (var i = 0; i < array.length; i++) { output.push([]); for (var j = 0; j < array[i].length; j++) { if (!found[array[i][j]]) { found[array[i][j]] = true; output[i].push(array[i][j]); } } } console.log(output); 回答2: Are you looking for a function

问题 So that: array = [[12,13,24],[24,22,11],[11,44,55]] would return: cleanedArray = [[12,13,24],[22,11],[44,55]] I'm surprised not to have found this answered here. 回答1: var array = [[12,13,24],[24,22,11],[11,44,55]]; var output = []; var found = {}; for (var i = 0; i < array.length; i++) { output.push([]); for (var j = 0; j < array[i].length; j++) { if (!found[array[i][j]]) { found[array[i][j]] = true; output[i].push(array[i][j]); } } } console.log(output); 回答2: Are you looking for a function

问题 So that: array = [[12,13,24],[24,22,11],[11,44,55]] would return: cleanedArray = [[12,13,24],[22,11],[44,55]] I'm surprised not to have found this answered here. 回答1: var array = [[12,13,24],[24,22,11],[11,44,55]]; var output = []; var found = {}; for (var i = 0; i < array.length; i++) { output.push([]); for (var j = 0; j < array[i].length; j++) { if (!found[array[i][j]]) { found[array[i][j]] = true; output[i].push(array[i][j]); } } } console.log(output); 回答2: Are you looking for a function

问题 Looking for a bit of help to modify some already-working JavaScript. I am using a piece of JavaScript along with a filtered textbox, the filtered text box only allows {1234567890,-} The below JavaScript works and prevents the user from entering more than 1 decimal I want to also add a dash/minus {-} to the allowed characters and prevent duplicates <script type="text/javascript"> function PreventDuplicateDecimal(evt) { var charCode = (evt.which) ? evt.which : event.keyCode; var itemdecimal =