duplicates

mysql concat_ws without duplicates

我只是一个虾纸丫 提交于 2020-01-02 08:23:04
问题 I am trying to concatenate a few fields into a single one, but only keep unique values in the resulting string. Example: title_orig | title_fr | title_de | title_it --------------------------------------------------------------------- KANDAHAR | KANDAHAR | REISE NACH KANDAHAR | VIAGGO A KANDAHAR SCREAM 2 | SCREAM 2 | SCREAM 2 | SCREAM 2 With CONCAT_WS(', ', title_orig, title_fr, title_de, title_it) AS titles I would get titles ------------------------------------------------------------

mysql concat_ws without duplicates

帅比萌擦擦* 提交于 2020-01-02 08:22:50
问题 I am trying to concatenate a few fields into a single one, but only keep unique values in the resulting string. Example: title_orig | title_fr | title_de | title_it --------------------------------------------------------------------- KANDAHAR | KANDAHAR | REISE NACH KANDAHAR | VIAGGO A KANDAHAR SCREAM 2 | SCREAM 2 | SCREAM 2 | SCREAM 2 With CONCAT_WS(', ', title_orig, title_fr, title_de, title_it) AS titles I would get titles ------------------------------------------------------------

Solr, block updating of existing document

别等时光非礼了梦想. 提交于 2020-01-02 06:40:34
问题 When a document is sent to solr and such document already exists in the index (by its ID) then the new one replaces old one. But I don't want to automatically replace documents. Just ignore and proceed to the next. How can I configure solr. Of course I can query solr to check if it has the document already but it's bad for me since I do bulk updates and this will complicate the process and increase amount of request. So are there any ways to configure solr to ignore duplicates? 回答1: You can

replace duplicate values with NA in time series data using dplyr

蹲街弑〆低调 提交于 2020-01-02 04:34:29
问题 My data seems a bit different than other similar kind of posts. box_num date x y 1-Q 2018-11-18 20.2 8 1-Q 2018-11-25 21.23 7.2 1-Q 2018-12-2 21.23 23 98-L 2018-11-25 0.134 9.3 98-L 2018-12-2 0.134 4 76-GI 2018-12-2 22.734 4.562 76-GI 2018-12-9 28 4.562 Here I would like to replace the repeated values with NA in both x and y columns. The code I have tried using dplyr : (1)df <- df %>% group_by(box_num) %>% arrange(box_num,date) %>% mutate(df$x[duplicated(df$x),] <- NA) It creates a new column

Using Linq to find duplicates but get the whole record

…衆ロ難τιáo~ 提交于 2020-01-02 02:19:19
问题 So I am using this code var duplicates = mg.GroupBy(i => new { i.addr1, i.addr2 }) .Where(g => g.Count() > 1) .Select(g=>g.Key); GridView1.DataSource = duplicates; GridView1.DataBind(); to find and list the duplicates in a table based on addr1 and addr2. The only problem with this code is that it only gives me the pair of addr1 and addr2 that are duplicates when i actually want to display all the fields of the records. ( all the fields like ID, addr1, addr2, city, state...) Any ideas ? 回答1:

Checking for duplicate Javascript objects

北城余情 提交于 2020-01-01 06:54:57
问题 TL;DR version: I want to avoid adding duplicate Javascript objects to an array of similar objects, some of which might be really big. What's the best approach? I have an application where I'm loading large amounts of JSON data into a Javascript data structure. While it's a bit more complex than this, assume that I'm loading JSON into an array of Javascript objects from a server through a series of AJAX requests, something like: var myObjects = []; function processObject(o) { myObjects.push(o)

Binary search if array contains duplicates

拟墨画扇 提交于 2020-01-01 03:58:10
问题 Hi, what is the index of the search key if we search for 24 in the following array using binary search. array = [10,20,21,24,24,24,24,24,30,40,45] I have a doubt regarding binary search that how does it works if a array has duplicate values.Can anybody clarify... 回答1: The array you proposed has the target value in the middle index, and in the most efficient implementations will return this value before the first level of recursion. This implementation would return '5' (the middle index). To

strategies for finding duplicate mailing addresses

人盡茶涼 提交于 2020-01-01 03:28:06
问题 I'm trying to come up with a method of finding duplicate addresses, based on a similarity score. Consider these duplicate addresses: addr_1 = '# 3 FAIRMONT LINK SOUTH' addr_2 = '3 FAIRMONT LINK S' addr_3 = '5703 - 48TH AVE' adrr_4 = '5703- 48 AVENUE' I'm planning on applying some string transformation to make long words abbreviated, like NORTH -> N, remove all spaces, commas and dashes and pound symbols. Now, having this output, how can I compare addr_3 with the rest of addresses and detect

Unbelievable duplicate in an Entity Framework Query

痞子三分冷 提交于 2020-01-01 01:52:08
问题 My SQL query against a particular view returns me 3 different rows. select * from vwSummary where vidate >= '10-15-2010' and vidate <= '10-15-2010' and idno = '0330' order by viDate But if i run the same query through my entity framework, I get 3 rows but all the 3 rows are same, equivalent to the third row. firstVisibleDate = new DateTime(2010, 10, 15); lastVisibleDate = new DateTime(2010, 10, 15); var p1 = (from v in db.vwSummary where v.viDate >= firstVisibleDate && v.viDate <=

Using XOR operator for finding duplicate elements in a array fails in many cases

痴心易碎 提交于 2019-12-31 14:37:14
问题 I came across a post How to find a duplicate element in an array of shuffled consecutive integers? but later realized that this fails for many input. For ex: arr[] = {601,602,603,604,605,605,606,607} #include <stdio.h> int main() { int arr[] = {2,3,4,5,5,7}; int i, dupe = 0; for (i = 0; i < 6; i++) { dupe = dupe ^ a[i] ^ i; } printf ("%d\n", dupe); return 0; } How can I modify this code so that the duplicate element can be found for all the cases ? 回答1: From original question: Suppose you