duplicates

Remove duplicate and count them in row

╄→гoц情女王★ 提交于 2020-01-11 14:09:30
问题 I would like to delete duplicate entries and then count them to display them next to my entries in my php ROW I've already tried this: <?php foreach (array_unique($events) as $eventorga) { $eventorgan = $eventorga['organizer']; echo $eventorga['organizer'].'</br>'; } ?> But an error: Array to string conversion is returned to me <?php foreach ($events as $eventorga) { echo $eventorga['organisateur'].'</br>'; } ?> Currently, my code returns this result: Holyblood Nessy Pokégaia Sorrow JOHN

Get number of duplicates from ArrayList

社会主义新天地 提交于 2020-01-11 13:59:13
问题 For example, say I have an ArrayList that could contain the following values: x x x y y Now what I want to retrieve is the number of x and x and I want to be able to differentiate what I have, either x or y because in actuality, I could have any object in the ArrayList and I have to be able to tell them apart. What I was thinking of doing was first converting the ArrayList into a LinkedHashSet , which would keep the ordering and remove the duplicates so I would just have x and y But how would

Java Method for removing duplicates from char array

时光总嘲笑我的痴心妄想 提交于 2020-01-11 12:30:10
问题 I have a char array filled by the user ( arrayInput[] ) with some characters, like {b, d, a, b, f, a, g, a, a, f}, and I need to create a method which returns a new char array with only the first occurrence of the character, but in the order of input. The book also says "A way to solve this problem is to create a boolean array to keep track of the characters to mantain!", but I can't imagine how the boolean array should work with the other arrays. The main problem is that I can save in a

R - subset column based on condition on duplicate rows

橙三吉。 提交于 2020-01-11 12:13:11
问题 I have a dataframe with an id column that is repeated, with site counts. I want to know how I can remove the duplicates ID records only when Site_Count record is more than 0. Generate DF: DF <- data.frame( 'ID' = sample(100:300, 100, replace=T), 'Site_count' = sample(0:1, 100, replace=T) ) My attempt at the subset: subset(DF[!duplicated(DF$ID),], site_count > 0) But in this case it will remove all 0 site counts - I want to subset to only remove the record when there is a duplicate record with

Find the most repeated row in a matrix

我的梦境 提交于 2020-01-11 09:11:31
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

爷,独闯天下 提交于 2020-01-11 09:11:28
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

自作多情 提交于 2020-01-11 09:11:26
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

前提是你 提交于 2020-01-11 09:11:10
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Remove Duplicate Cells in a Row

我的梦境 提交于 2020-01-11 07:31:29
问题 Just to clarify : I don't want to remove duplicates rows, I want to remove Duplicate Cells within a row So here's a classic address table, and in some row there's duplicate entries I need to remove those entries. Most of what I've seen in VBA is used to remove duplicates values within a column, but I can't find a way to remove duplicate values within a row. Name | Address1 | Address2 | City | Country Peter | 2 foobar street |2 foobar street | Boston | USA And I want it to be like : Name |

Find duplicate items within a list of list of tuples Python

故事扮演 提交于 2020-01-11 06:42:14
问题 I want to find the matching item from the below given list.My List may be super large. The very first item in the tuple "N1_10" is duplicated and matched with another item in another array tuple in 1st array in the ListA ('N1_10', 'N2_28') tuple in 2nd array in the ListA ('N1_10', 'N3_98') ListA = [[('N1_10', 'N2_28'), ('N1_35', 'N2_44')], [('N1_22', 'N3_72'), ('N1_10', 'N3_98')], [('N2_33', 'N3_28'), ('N2_55', 'N3_62'), ('N2_61', 'N3_37')]] what I want for the output is output --> [('N1_10',