duplicates

Find and Remove Duplicate Rows from a SQL Server Table

此生再无相见时 提交于 2020-04-17 20:49:46
问题 I'm using a SQL Server database and I have a datetime column datatype is datetime . Some rows under datetime column are duplicate, how can I delete the duplicate row and sort table by datetime ? T-SQL: SELECT [datetime] FROM [database].[dbo].[data] Result: datetime 2020-03-18 09:18:00.000 2020-03-18 09:19:00.000 2020-03-18 09:20:00.000 ............. ............. ............. 2020-03-18 09:19:00.000 2020-03-18 09:20:00.000 Can anyone help? 回答1: If I understand correctly, you just want:

Merge list of dictionaries where id is duplicate - python3 [duplicate]

半腔热情 提交于 2020-04-06 04:14:10
问题 This question already has answers here : python list of dictionaries find duplicates based on value (3 answers) Closed last month . I have a list of dictionaries : [{"id":"1", "name":"Alice", "age":"25", "languages":"German"}, {"id":"1", "name":"Alice", "age":"25", "languages":"French"}, {"id":"2", "name":"John", "age":"30", "languages":"English"}, {"id":"2", "name":"John", "age":"30", "languages":"Spanish"}] I'd like the end result to be (I am only considering the id when checking for

How to find duplicate based upon multiple columns in a rolling window in pandas?

拜拜、爱过 提交于 2020-04-05 06:43:58
问题 Sample Data {"transaction": {"merchant": "merchantA", "amount": 20, "time": "2019-02-13T10:00:00.000Z"}} {"transaction": {"merchant": "merchantB", "amount": 90, "time": "2019-02-13T11:00:01.000Z"}} {"transaction": {"merchant": "merchantC", "amount": 90, "time": "2019-02-13T11:00:10.000Z"}} {"transaction": {"merchant": "merchantD", "amount": 90, "time": "2019-02-13T11:00:20.000Z"}} {"transaction": {"merchant": "merchantE", "amount": 90, "time": "2019-02-13T11:01:30.000Z"}} {"transaction": {

How to find duplicate based upon multiple columns in a rolling window in pandas?

生来就可爱ヽ(ⅴ<●) 提交于 2020-04-05 06:42:20
问题 Sample Data {"transaction": {"merchant": "merchantA", "amount": 20, "time": "2019-02-13T10:00:00.000Z"}} {"transaction": {"merchant": "merchantB", "amount": 90, "time": "2019-02-13T11:00:01.000Z"}} {"transaction": {"merchant": "merchantC", "amount": 90, "time": "2019-02-13T11:00:10.000Z"}} {"transaction": {"merchant": "merchantD", "amount": 90, "time": "2019-02-13T11:00:20.000Z"}} {"transaction": {"merchant": "merchantE", "amount": 90, "time": "2019-02-13T11:01:30.000Z"}} {"transaction": {

How can I drop consecutive duplicate rows in one column based on condition/grouping from another column?

守給你的承諾、 提交于 2020-03-23 08:17:23
问题 [EDITED TO CLARIFY QUESTION] I have large dataframe (approx. 10k rows) with the first few rows looking like what I'll call df_a: logtime | zone | value 01/01/2017 06:05:00 | 0 | 14.5 01/01/2017 06:05:00 | 1 | 14.5 01/01/2017 06:05:00 | 2 | 17.0 01/01/2017 06:25:00 | 0 | 14.5 01/01/2017 06:25:00 | 1 | 14.5 01/01/2017 06:25:00 | 2 | 10.0 01/01/2017 06:50:00 | 0 | 10.0 01/01/2017 06:50:00 | 1 | 10.0 01/01/2017 06:50:00 | 2 | 10.0 01/01/2017 07:50:00 | 0 | 14.5 01/01/2017 07:50:00 | 1 | 14.5 01

Finding duplicates on one column using select where in SQL Server 2008

谁说我不能喝 提交于 2020-03-18 04:52:40
问题 I am trying to select rows from a table that have duplicates in one column but also restrict the rows based on another column. It does not seem to be working correctly. select Id,Terms from QueryData where Track = 'Y' and Active = 'Y' group by Id,Terms having count(Terms) > 1 If I remove the where it works fine but I need to restrict it to these rows only. ID Terms Track Active 100 paper Y Y 200 paper Y Y 100 juice Y Y 400 orange N N 1000 apple Y N Ideally the query should return the first 2

Finding duplicates on one column using select where in SQL Server 2008

佐手、 提交于 2020-03-18 04:52:23
问题 I am trying to select rows from a table that have duplicates in one column but also restrict the rows based on another column. It does not seem to be working correctly. select Id,Terms from QueryData where Track = 'Y' and Active = 'Y' group by Id,Terms having count(Terms) > 1 If I remove the where it works fine but I need to restrict it to these rows only. ID Terms Track Active 100 paper Y Y 200 paper Y Y 100 juice Y Y 400 orange N N 1000 apple Y N Ideally the query should return the first 2

How to print keys with duplicate values in a hashmap?

狂风中的少年 提交于 2020-03-16 08:01:11
问题 I have a hashmap with some keys pointing to same values. I want to find all the values that are equal and print the corresponding keys. This is the current code that I have: Map<String, String> map = new HashMap<>(); map.put("hello", "0123"); map.put("hola", "0123"); map.put("kosta", "0123"); map.put("da", "03"); map.put("notda", "013"); map.put("twins2", "01"); map.put("twins22", "01"); List<String> myList = new ArrayList<>(); for (Map.Entry<String, String> entry : map.entrySet()) { for (Map

MongoDb Aggregate , find duplicate records within 7 days

假装没事ソ 提交于 2020-03-04 21:36:20
问题 I have to create a check for this use case- Duplicate payment check • Same amount to a same account number in last 7 days for all transactions. I haven't used mongoDb as much would have been easier for me to write in sql This is what I am trying without the 7 days part db.transactiondetails.aggregate({$group: {"_id":{"account_number":"$account_number","amount":"$amount"},"count": { $sum: 1 }}}) Where I get something like this : { "_id" : { "account_number" : "xxxxxxxy", "amount" : 19760 },

MongoDb Aggregate , find duplicate records within 7 days

时间秒杀一切 提交于 2020-03-04 21:35:50
问题 I have to create a check for this use case- Duplicate payment check • Same amount to a same account number in last 7 days for all transactions. I haven't used mongoDb as much would have been easier for me to write in sql This is what I am trying without the 7 days part db.transactiondetails.aggregate({$group: {"_id":{"account_number":"$account_number","amount":"$amount"},"count": { $sum: 1 }}}) Where I get something like this : { "_id" : { "account_number" : "xxxxxxxy", "amount" : 19760 },