dplyr

问题 I have a dataframe which has multiple values in a single file. I want to divide it into multiple files around 25 from the file. Pattern for the file is where there is one blank row and a header title is there , it is a new df. I Have tried this Splitting dataframes in R based on empty rows but this does not take care of any blank row within the new df (V1 column 9th row). I want the data to be divided on empty row and a header title my data and code i have tried is given below . Also how can

问题 I would like to remove duplicate rows based on >1 column using dplyr / tidyverse Example library(dplyr) df <- data.frame(a=c(1,1,1,2,2,2), b=c(1,2,1,2,1,2), stringsAsFactors = F) I thought this would return rows 3 and 6, but it returns 0 rows. df %>% filter(duplicated(a, b)) # [1] a b # <0 rows> (or 0-length row.names) Conversely, I thought this would return rows 1,2,4 and 5, but it returns all rows. df %>% filter(!duplicated(a, b)) # a b # 1 1 1 # 2 1 2 # 3 1 1 # 4 2 2 # 5 2 1 # 6 2 2 What

问题 I have two data frames that I want to join by the first column and to ignore the case: df3<- data.frame("A" = c("XX28801","ZZ9"), "B" = c("one","two"),stringsAsFactors = FALSE) df4<- data.frame("Z" = c("X2880","Zz9"),"C" = c("three", "four"), stringsAsFactors = FALSE) What I want is this: df5<- data.frame(A = c("XX28801","ZZ9"), B = c("one","two"), Z = c(NA,"Zz9"), C = c(NA, "four")) but interestingly, I get this using the fuzzyjoin package: join <- regex_left_join(df3,df4,by= c("A" = "Z"),

问题 I have a problem changing the Azure Cost Management response into a data frame. This is what I get from AzureRMR : response_example <- list(id = 'subscriptions/00000000-0000-0000-0000-000000000000/providers/Microsoft.CostManagement/query/00000000-0000-0000-0000-000000000000', name = '00000000-0000-0000-0000-000000000000', type = 'Microsoft.CostManagement/query', location = NULL, sku = NULL, eTag = NULL, properties = list( nextLink = 'https://management.azure.com/subscriptions/00000000-0000

问题 I have a problem changing the Azure Cost Management response into a data frame. This is what I get from AzureRMR : response_example <- list(id = 'subscriptions/00000000-0000-0000-0000-000000000000/providers/Microsoft.CostManagement/query/00000000-0000-0000-0000-000000000000', name = '00000000-0000-0000-0000-000000000000', type = 'Microsoft.CostManagement/query', location = NULL, sku = NULL, eTag = NULL, properties = list( nextLink = 'https://management.azure.com/subscriptions/00000000-0000

问题 This question already has answers here : Relative frequencies / proportions with dplyr (9 answers) Extend contigency table with proportions (percentages) (6 answers) Closed 7 months ago . I am trying to calculate the percentage of different levels of a factor within a group. I have nested data and would like to see the percentage of schools in each country is a private schools (factor with 2 levels). However, I cannot figure out how to do that. # my data: CNT <- c("A", "A", "A", "A", "A", "B"

问题 lets say I have following data ind1 <- rnorm(99) ind2 <- rnorm(99) ind3 <- rnorm(99) ind4 <- rnorm(99) ind5 <- rnorm(99) dep <- rnorm(99, mean=ind1) group <- rep(c("A", "B", "C"), each=33) df <- data.frame(dep,group, ind1, ind2, ind3, ind4, ind5) the following code is calculating multiple linear regression between dependend variable and 2 independent variables by group which is exactly what I want to do. But I want to regress dep variable against all combination pair of independent variables

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 3 years ago . Improve this question I am trying to use group by in a for loop. I would like the gourp by to cycle through each column and then I can perform a summarise action. I tried to used colnames(df[i]) within the groupby but because colnames comes back with quotation marks this method does not work. Any

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 3 years ago . Improve this question I am trying to use group by in a for loop. I would like the gourp by to cycle through each column and then I can perform a summarise action. I tried to used colnames(df[i]) within the groupby but because colnames comes back with quotation marks this method does not work. Any

问题 Target: Building a shiny-app which enables the user to make 3 inputs via Groupcheckboxfields: Groupingvariables Metricvariables Statistics which are used in dplyr look at this code first - it is executed without shiny and displays the to be achived results: library("plyr") library("dplyr") ## Without shiny - it works! groupss <- c("gear", "carb") statistics <- c("min", "max", "mean") metrics <- c("drat", "hp") grp_cols <- names(mtcars[colnames(mtcars) %in% groupss]) dots <- lapply(grp_cols,