doubly-linked-list

I am currently teaching myself C++ and am attempting to implement a doubly-linked list in C++ using pointers which is partially complete. I am aware that the code currently fails to deal with dangling nodes or output errors, both of which I will implement next. However, the code should atleast be able to construct a list object and add elements to it. Currently, I am getting an error when I attempt to call a constructor for the list, which says that I am requesting a conversion from LinkedList* to non scalar type LinkedList. Why is my list being declared as a pointer? Any help would be much

I am trying to design a program that takes in data from a file, after which it gives numbering to unique data, linked list also contains parent and child lists. Data structure: ____A / | B C | / \ E--> F G | | | I J K The nodes can have more than one next nodes (e.g. A and C), and can have more than one previous nodes. The text file contains the data like this, i'll get the data from file and turn them into linked list : A B E I A C E F J A C G K My Question: Is it possible to create linked list with nodes with more than one next or more than one previous nodes, if so how would the struct look

On CLRS's textbook "Introduction to Algorithm", there's such paragraph on pg. 258. We can delete an element in O(1) time if the lists are doubly linked. (Note that CHAINED-HASH-DELETE takes as input an element x and not its key k, so that we don't have to search for x first. If the hash table supports deletion, then its linked list should be doubly linked so that we can delete an item quickly. If the lists were only singly linked, then to delete element x, we would first have to find x in the list so that we could update the next attribute of x's predecessor. With singly linked lists, both

I'm studying sys/queue.h from FreeBSD and I have one question: In sys/queue.h , LIST_ENTRY is defined as follows: #define LIST_ENTRY(type) \ struct { \ struct type *le_next; /* next element */ \ struct type **le_prev; /* address of previous next element */ \ } Why does it maintain the address of previous next element ( struct type **le_prev ) rather than simply previous elment like struct type *le_prev ? If you would have read the queue.h file from the beginning, you may have got following comment: * A list is headed by a single forward pointer (or an array of forward * pointers for a hash

I have an array of objects of the following type: struct Node { Node *_pPrev, *_pNext; double *_pData; }; Some of the nodes participate in a doubly-linked list, with _pData!=nullptr for such nodes. There is also a dummy head node with _pNext pointing to the beginning of the list, and _pPrev pointing to the end. The list starts with containing only this head node, and it should be never removed from the list. The doubly-linked list is backed by an array, with initial size equal to the maximum number of nodes in the list. struct Example { Node _nodes[MAXN]; Node _head; }; Now I want to perform

I've heard that it's possible to implement binary search over a doubly-linked list in O(n) time. Accessing a random element of a doubly-linked list takes O(n) time, and binary search accesses O(log n) different elements, so shouldn't the runtime be O(n log n) instead? templatetypedef It's technically correct to say that the runtime of binary search on a doubly-linked list is O(n log n), but that's not a tight upper bound. Using a slightly better implementation of binary search and a more clever analysis, it's possible to get binary search to run in time O(n). The basic idea behind binary