double-click

React Native: Double back press to Exit App

对着背影说爱祢 提交于 2019-11-30 14:19:10
How to exit application with twice clicking the back button without needing Redux I was looking for a solution to limit the user and do not get out of the application with one click in react native. Mahdi Bashirpour import React, {Component} from 'react'; import {BackHandler, View, Dimensions, Animated, TouchableOpacity, Text} from 'react-native'; let {width, height} = Dimensions.get('window'); export default class App extends Component<Props> { state = { backClickCount: 0 }; constructor(props) { super(props); this.springValue = new Animated.Value(100); } componentWillMount() { BackHandler

Double-click DataGridView row?

时光毁灭记忆、已成空白 提交于 2019-11-30 13:01:19
I am using vb.net and DataGridView on a winform. When a user double-clicks on a row I want to do something with this row. But how can I know whether user clicked on a row or just anywhere in the grid? If I use DataGridView.CurrentRow then if a row is selected and user clicked anywhere on the grid the current row will show the selected and not where the user clicked (which in this case would be not on a row and I would want to ignore it). Try the CellMouseDoubleClick event... Private Sub DataGridView1_CellMouseDoubleClick(ByVal sender As Object, ByVal e As System.Windows.Forms

HTML Double Click Selection Oddity

情到浓时终转凉″ 提交于 2019-11-30 09:10:19
I didn't post this on DocType because it's not really a design thing, the visual representation isn't my problem, the behaviour is. I'm sorry if this is misplaced but I don't feel it's a designer issue. The following DOM: <ul style="overflow: hidden;"> <li style="float: left;"><strong>SKU:</strong>123123</li> <li style="float: left;"><strong>ILC:</strong>asdasdasdasd</li> </ul> Or <div style="overflow: hidden;"> <div style="float: left; width: 49%"><strong>SKU:</strong>123123</div> <div style="margin-left: 50%; width: auto;"><strong>ILC:</strong>asdasdasdasd</div> </div> Or <p> <span><strong

C#: How to avoid TreeNode check from happening on a double click event

こ雲淡風輕ζ 提交于 2019-11-30 08:27:21
So I have a TreeView in a C# windows form app. What I need is for some nodes to be "locked" so that they cannot be checked (or unchecked), based on a parameter. What I am doing now is this: private void tv_local_BeforeCheck(object sender, TreeViewCancelEventArgs e) { TNode node = (TNode)e.Node; //if a part node, cancel the action. if (node.Type == "Part") { e.Cancel = true; } //if a locked node, cancel the action if (node.Locked == true) { e.Cancel = true; } } This code works great on a single click of the checkbox, but if the user double clicks on a checkbox, it still checks/unchecks. I have

C#: How to avoid TreeNode check from happening on a double click event

走远了吗. 提交于 2019-11-30 07:06:59
问题 So I have a TreeView in a C# windows form app. What I need is for some nodes to be "locked" so that they cannot be checked (or unchecked), based on a parameter. What I am doing now is this: private void tv_local_BeforeCheck(object sender, TreeViewCancelEventArgs e) { TNode node = (TNode)e.Node; //if a part node, cancel the action. if (node.Type == "Part") { e.Cancel = true; } //if a locked node, cancel the action if (node.Locked == true) { e.Cancel = true; } } This code works great on a

Phonegap 2.4.0 with Android 4.2 - strange double click behaviour

梦想与她 提交于 2019-11-30 06:59:47
I'm using phonegap 2.4.0 to create an Android and iOS App. Now I recognized that the onclick event in links is fired twice inside the Android App using Android 4.2.2 on a Nexus 4 device, like a double click (althoug I tapped it only once!). <a href="#" onclick="$(this).append('test'); return false;" style="some styles...">some text</a> libs in use: jquery 1.9.1 jquery mobile 1.3.0 (rc) jquery ui 1.10.0 jquery touch punch 0.2.2 phonegap 2.4.0 After I clicked (or tapped) the link on my Nexus 4 (Android 4.2.2) the string 'test' is appended twice inside the app. This does NOT happen when I test it

Java : ignore single click on double click?

两盒软妹~` 提交于 2019-11-30 04:54:23
can anyone think of a good way to ignore the single click that comes with a double-click in Java ? I'm looking to have different behaviors for each such that: single-click paints crosshairs on the click point double-click selects an object on the screen, but should not paint crosshairs on the click point ... can anyone think of a way to do this ? Some sort of timer set-up maybe ? An ideas appreciated :-) <disclaimer> ...and yes, I know I'm committing a most heinous usability / UI faux pas. </disclaimer> EDIT #2: Even though this works the delay due to the timer is maddening - I'm abandoning

Ajax request failing in cordova/phonegap app on real device

自作多情 提交于 2019-11-30 04:43:57
问题 I'm building a Cordova 4.0 jQuery Mobile 1.4.2 Android app and I'm having issues with a particular AJAX call. I've looked for similar questions and already implemented the solutions there with no success. Here's what happens: I have the following AJAX call: var request = $.ajax({ type: "GET" , crossDomain: true, url: 'http://pubads.g.doubleclick.net/gampad/adx?iu=/XXX/YYY&sz=300x50&c=123456789' }); request.done(function (response, textStatus, jqXHR){ console.log(response); }); request.fail

identifying double click in java

三世轮回 提交于 2019-11-30 04:11:23
I want to know how can we perform action when mouse is double clicked in a component. public void mouseClicked(MouseEvent event) { if (event.getClickCount() == 2) { System.out.println("double clicked"); } } Assuming you mean in Swing, assign a MouseListener to your Component: addMouseListener(new MouseAdapter(){ @Override public void mouseClicked(MouseEvent e){ if(e.getClickCount()==2){ // your code here } } }); Reference: Java Tutorial: How to write a Mouse Listener davidxxx The e.getClickCount()==2 is not enough if you want to allow your users to do multiple double clicks in a short delay.

Why android onLongPress always is fired after onDoubleTap?

你说的曾经没有我的故事 提交于 2019-11-30 03:52:15
I have onLongPress and onDoubleTap actions placed on the button according to this code: ... GestureDetector detector = new GestureDetector(this, new TapDetector()); public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); detector = new GestureDetector(this, new TapDetector()); ... } private class TapDetector extends GestureDetector.SimpleOnGestureListener { @Override public boolean onDoubleTap(MotionEvent e) { // Do something return true; } @Override public void onLongPress(MotionEvent e) { // Do something } } Button incomeButton =